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NCERT Exercises and Solutions: Biotechnology: Principles and Processes

🎓 Class 12 Biology CBSE Theory Ch 9 – Biotechnology: Principles and Processes ⏱ ~8 min
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Biotechnology: Principles and Processes - Summary and NCERT Exercise Solutions

This last part of Chapter 9 gathers the chapter into one summary, answers the questions raised inside the text, and then works through every NCERT exercise question in full.

Chapter Summary

Biotechnology deals with large scale production and marketing of products and processes using live organisms, cells or enzymes. Modern biotechnology using genetically modified organisms was made possible only when man learnt to alter the chemistry of DNA and construct recombinant DNA.

This key process is called recombinant DNA technology, or genetic engineering. The process involves the use of restriction endonucleases, DNA ligase, and appropriate plasmid or viral vectors, to isolate and ferry the foreign DNA into host organisms; then expression of the foreign gene; purification of the gene product, that is the functional protein; and finally making a suitable formulation for marketing. Large scale production involves the use of bioreactors.

Chapter 9 at a glance
ElementWhat it isWhat it contributes
Genetic engineeringTechniques to alter the chemistry of DNA and RNA and introduce it into hostsChanges the phenotype of the host organism
Bioprocess engineeringMaintenance of a sterile ambience in chemical engineering processesLets only the desired cell grow, in large quantities
Restriction endonucleaseCuts DNA at a palindromic recognition sequence, leaving sticky endsIsolates a defined gene; creates joinable ends
DNA ligaseJoins the ends of cut DNA moleculesSeals insert into vector, making recombinant DNA
Origin of replicationSequence from where replication starts; sets copy numberLets the alien DNA be copied and inherited
Selectable markerUsually an antibiotic resistance gene on the vectorFinds transformants among millions of cells
Insertional inactivationA second marker broken by the insertDistinguishes recombinants from non-recombinants
Competent hostCells treated with divalent cations, then heat-shockedAllows hydrophilic DNA to enter the cell
PCRDenaturation, primer annealing, extension — repeatedAmplifies the gene about a billion-fold in vitro
BioreactorVessel processing 100–1000 litres under controlled conditionsTurns a working cell line into industrial quantities
Downstream processingSeparation, purification, formulation, trials, quality controlTurns the product into a marketable finished product

The chapter in one idea. Every tool in this chapter exists to solve one of three problems: how to get only the gene you want (restriction enzymes, electrophoresis, elution, PCR), how to make a host keep and copy it (origin of replication, vectors, competence), and how to find the few cells that worked (selectable markers, insertional inactivation, reporter enzymes). Learn the three problems and the tools stop being a list.

Questions raised inside the chapter

In-text question — Figure 9.3

Look at the agarose gel and guess at which end of the gel the sample was loaded.

The sample was loaded at the end where the largest, slowest-moving bands are — that is, at the cathode end, farthest from the anode.

The reasoning is that DNA fragments are negatively charged molecules and are separated by forcing them to move towards the anode under an electric field. They therefore all travel away from the wells in one direction. Because the fragments resolve according to size through the sieving effect provided by the agarose gel, the smaller the fragment size, the farther it moves — so the band nearest the loading point is the largest fragment, and the undigested DNA in lane 1 barely moves from the well at all.

In-text question — Section 9.2.3

Since DNA is a hydrophilic molecule, it cannot pass through cell membranes. Why?

Because of what a membrane is made of. A cell membrane is a bilayer whose interior is a hydrophobic region of fatty acid tails. Only small, non-polar, lipid-soluble molecules cross such a layer freely.

DNA fails on every count. It is a very large polymer; it carries a dense negative charge along its phosphate backbone; and it is strongly hydrated, that is hydrophilic. A charged, water-loving macromolecule cannot dissolve into or diffuse through a hydrophobic core.

This is precisely why hosts have to be made competent: treatment with a specific concentration of a divalent cation such as calcium increases the efficiency with which DNA enters the bacterium through pores in its cell wall, and the ice-heat shock-ice sequence then forces the recombinant DNA in. Where that will not work, DNA is delivered by micro-injection, by biolistics, or by disarmed pathogen vectors.

In-text question — Section 9.3.5

Can you think of any reason why there is a need for large-scale production?

Because the quantities actually needed are enormous compared with what a laboratory culture yields. Small volume cultures cannot yield appreciable quantities of products. A single diabetic patient needs insulin every day for life, and there are hundreds of millions of such patients; a laboratory flask could not supply one hospital for one week.

Because purification loses most of what you make. The desired protein is a tiny fraction of the cell's total protein, and every step of separation and purification in downstream processing costs some of it. You must begin with far more than you intend to sell.

Because cost falls with scale. Biotechnology deals with large scale production and marketing. The vessel, the sterilisation, the monitoring and the trained staff cost nearly the same for 10 litres as for 1000, so the price per dose of a medicine is set largely by the scale at which it is made.

This is why bioreactors were developed, in which large volumes of 100 to 1000 litres of culture can be processed, and why cells are often grown in a continuous culture system to keep them in their most productive phase.

NCERT Exercises — Solved

Question 1

Can you list 10 recombinant proteins which are used in medical practice? Find out where they are used as therapeutics.

A recombinant protein is any protein-encoding gene expressed in a heterologous host. The following are in routine medical use.

Recombinant proteinUsed as a therapeutic in
1. Human insulinDiabetes mellitus — replaces animal insulin, with no risk of an immune reaction to a non-human protein
2. Human growth hormone (somatotropin)Pituitary dwarfism and growth-hormone deficiency in children
3. ErythropoietinAnaemia, especially in chronic renal failure and in patients on dialysis — it stimulates erythropoiesis
4. Blood clotting factor VIIIHaemophilia A
5. Blood clotting factor IXHaemophilia B
6. Tissue plasminogen activatorDissolving clots in heart attack (myocardial infarction) and ischaemic stroke
7. Interferon αChronic hepatitis B and C, and some cancers
8. Hepatitis B surface antigenThe recombinant hepatitis B vaccine — the antigen alone, with no virus involved
9. Follicle stimulating hormoneTreatment of infertility and in assisted reproductive technology
10. AsparaginaseAcute lymphoblastic leukaemia
11. DNase I (dornase alfa)Cystic fibrosis — thins the viscous airway secretions
12. Interleukin-2Certain cancers, as an immune stimulant

What the list shows. Notice the pattern: most of these are human proteins that a patient cannot make enough of. Before recombinant DNA technology they had to be extracted from animal tissue, human cadavers or pooled blood — which meant tiny supplies, immune reactions to non-human protein, and the real risk of transmitting infection. Making the human protein in a heterologous host solved all three problems at once.

Question 2

Make a chart (with diagrammatic representation) showing a restriction enzyme, the substrate DNA on which it acts, the site at which it cuts DNA and the product it produces.

Taking EcoRI as the example.

ItemDetail
Restriction enzymeEcoRI — from Escherichia coli RY 13; E for the genus, co for the species, R for the strain, I because it was the first isolated from that strain
Substrate DNAAny double-stranded DNA containing the palindromic recognition sequence 5′-GAATTC-3′ / 3′-CTTAAG-5′
Site at which it cutsBetween G and A on each strand — a little away from the centre of the palindrome site, but between the same two bases on the opposite strands
ProductTwo fragments, each carrying a four-base single-stranded overhang (AATT and TTAA) — the sticky ends, which form hydrogen bonds with their complementary cut counterparts
Substrate DNA (recognition sequence in red) 5′- A T C G A A T T C G G A -3′ 3′- T A G C T T A A G C C T -5′ EcoRI cuts here on the top strand and here on the bottom strand Products: two fragments with complementary sticky ends 5′- A T C G 3′- T A G C T T A A A A T T C G G A -3′ G C C T -5′ Any two fragments cut by EcoRI carry matching overhangs, so DNA ligase can join them — whatever genome they came from.
EcoRI: enzyme, substrate, cut site and products. The staggered cut is what creates the sticky ends.
Question 3

From what you have learnt, can you tell whether enzymes are bigger or DNA is bigger in molecular size? How did you know?

DNA is very much bigger. An enzyme is a protein of a few hundred amino acids, with a molecular mass of the order of ten thousand to a hundred thousand daltons. A DNA molecule is a polymer of millions of nucleotides — the single circular chromosome of E. coli alone runs to about 4.6 million base pairs, and a human chromosome to far more.

How you can know it from this chapter, without being told.

(i) From the way they act on each other. Each restriction endonuclease functions by inspecting the length of a DNA sequence until it finds its recognition sequence. An enzyme that must travel along a molecule searching for a six-base site is obviously the smaller of the two; the DNA is the landscape, the enzyme the walker.

(ii) From how many cuts one molecule yields. A single DNA molecule can be cut by an enzyme into many fragments, each still large enough to be seen as a band on a gel. Something that can be divided into many visible pieces must be much larger than the tool dividing it.

(iii) From what you can see. Purified DNA precipitated with chilled ethanol can be seen as a collection of fine threads in the suspension — visible to the naked eye. No enzyme solution shows anything of the kind.

(iv) From the genetics. The enzyme is the product of a gene, and that gene is only one short stretch of the DNA molecule. The whole cannot be smaller than a product of one of its parts.

Question 4

What would be the molar concentration of human DNA in a human cell? Consult your teacher.

This is an order-of-magnitude calculation, and it is worth doing carefully because the answer is startling.

Step 1 — how many DNA molecules are in one cell? A human diploid somatic cell has 46 chromosomes, and each unreplicated chromosome is one DNA molecule. So there are 46 molecules of nuclear DNA per cell.

Step 2 — convert to moles. One mole contains 6.022 × 1023 molecules, so

\( n = \dfrac{46}{6.022 \times 10^{23}} \approx 7.6 \times 10^{-23}\ \text{mol} \)

Step 3 — divide by the volume. Molar concentration is moles per litre. Taking a typical human cell volume of about 2000 µm3, which is 2 × 10−12 litre,

\( c = \dfrac{7.6 \times 10^{-23}\ \text{mol}}{2 \times 10^{-12}\ \text{L}} \approx 4 \times 10^{-11}\ \text{mol L}^{-1} \)

The answer. Of the order of 10−11 M, that is a few tens of picomolar. (If you assume a smaller cell, or calculate for the nucleus alone, you will get a somewhat higher figure; the order of magnitude is what matters.)

Why the number is worth thinking about. Water in the same cell is about 40 M. So the molecule that specifies the entire organism is present at roughly one part in 1012 by concentration — among the rarest molecules in the cell. It is rare because it does not need to be abundant: a single copy is read repeatedly, and the RNA and protein products are what get made in quantity. It is also why PCR matters so much: amplifying a DNA sequence about a billion-fold is what takes a vanishingly dilute molecule into the range where chemistry can be done with it.

Question 5

Do eukaryotic cells have restriction endonucleases? Justify your answer.

No — eukaryotic cells do not possess restriction endonucleases of the kind used in genetic engineering. They have plenty of other nucleases, for DNA repair, for recombination and for degrading DNA during programmed cell death, but not the sequence-specific restriction–modification system found in bacteria.

Justification 1 — the function these enzymes serve. Recall how they were discovered: the two enzymes isolated in 1963 were responsible for restricting the growth of bacteriophage in Escherichia coli. Restriction enzymes are a bacterial defence against invading phage DNA. Bacteria have no nuclear envelope and no immune system, so cutting up foreign DNA the moment it arrives is their protection.

Justification 2 — the system needs a partner, and it would be dangerous without one. One of the two enzymes isolated in 1963 added methyl groups to DNA. That methylase is what marks the cell's own DNA so it is spared. A eukaryote with a large genome full of recognition sites, but no such protection, would cut its own chromosomes to pieces. Maintaining the system would cost more than it is worth.

Justification 3 — eukaryotes defend themselves differently. A eukaryotic cell keeps its DNA inside a nucleus, behind a nuclear envelope. Multicellular eukaryotes add interferons, immune surveillance and RNA-based silencing of viral nucleic acid. The problem is solved by other means, so the bacterial solution was never needed.

The practical confirmation. All of the more than 900 restriction enzymes now available have been isolated from over 230 strains of bacteria. If eukaryotes had them, biotechnology would certainly have found them there too.

Question 6

Besides better aeration and mixing properties, what other advantages do stirred tank bioreactors have over shake flasks?

(i) Control of the growth conditions. A bioreactor provides the optimal conditions for achieving the desired product by providing optimum growth conditions — temperature, pH, substrate, salts, vitamins and oxygen. It has a dedicated temperature control system and pH control system, so neither drifts as the cells metabolise. A shake flask offers no such control.

(ii) Sampling without contamination. The bioreactor has sampling ports, so that small volumes of the culture can be withdrawn periodically. The progress of the run can therefore be followed without opening the vessel, which in a flask would risk losing the batch.

(iii) Foam control. Agitating a protein-rich medium generates foam, which carries cells out of the liquid and blocks filters. The bioreactor has a foam control system.

(iv) Volume, and therefore usable yield. Small volume cultures cannot yield appreciable quantities of products, whereas a bioreactor allows large volumes of 100 to 1000 litres of culture to be processed.

(v) Continuous operation. A bioreactor can be run as a continuous culture system, with used medium drained out from one side while fresh medium is added from the other, maintaining the cells in their physiologically most active log or exponential phase. This produces a larger biomass and higher yields of the desired protein. A flask is inherently a batch culture, which must exhaust its medium.

(vi) Sterility at scale. A closed, steam-sterilisable vessel with controlled air entry keeps the sterile, contamination-free ambience that bioprocess engineering requires — something impossible to guarantee in repeatedly opened flasks.

Question 7

Collect 5 examples of palindromic DNA sequences by consulting your teacher. Better try to create a palindromic sequence by following base-pair rules.

Five real examples — each is the recognition sequence of a restriction enzyme, and each reads the same on both strands in the 5′→3′ direction.

EnzymeTop strand 5′→3′Bottom strand 3′→5′
EcoR IG A A T T CC T T A A G
BamH IG G A T C CC C T A G G
Hind IIIA A G C T TT T C G A A
Pst IC T G C A GG A C G T C
Sal IG T C G A CC A G C T G

How to create one yourself. The rule is that the second half of the sequence must be the reverse complement of the first half.

  1. Choose any three bases for the first half — say T G C.
  2. Reverse them: C G T.
  3. Complement each base (A↔T, G↔C): G C A.
  4. Join the two halves: T G C G C A.

Check it. The bottom strand of 5′-TGCGCA-3′ is 3′-ACGCGT-5′. Read that bottom strand in the 5′→3′ direction, that is from right to left: T G C G C A. Identical to the top strand — so it is a genuine palindrome. (It is in fact the recognition site of Fsp I.)

Note the difference from a word-palindrome. MALAYALAM reads the same backwards on the same line. A DNA palindrome reads the same on the two strands, when the orientation of reading is kept the same. That is why the symmetry rule involves complementing as well as reversing.

Question 8

Can you recall meiosis and indicate at what stage a recombinant DNA is made?

During crossing over, in the pachytene stage of prophase I of meiosis.

Recall the sequence. In zygotene, homologous chromosomes pair by synapsis and form bivalents or tetrads. In pachytene, the four chromatids of each bivalent become distinct, recombination nodules appear at sites along the paired chromosomes, and crossing over takes place — the exchange of genetic material between the non-sister chromatids of homologous chromosomes. This exchange is enzyme-mediated, and the enzyme involved is recombinase. By diplotene, the recombined chromatids remain attached at the chiasmata, which is the visible evidence that the exchange has happened.

Why this counts as recombinant DNA. After crossing over, a single chromatid carries a stretch of DNA of maternal origin covalently joined to a stretch of paternal origin. That is exactly the definition of a recombinant DNA molecule — DNA composed of DNA from different sources joined into one continuous molecule.

The comparison worth drawing.

In meiosisIn the laboratory
WhenPachytene of prophase IIn vitro, at the bench
Cutting done byRecombinase systemRestriction endonuclease
Joining done byRecombinase system (ligation step)DNA ligase
Partners joinedNon-sister chromatids of homologous chromosomes onlyAny two DNAs cut with the same enzyme — even from different kingdoms
Control over the outcomeNone; the site of exchange is not chosenComplete; the construct is defined before transfer

So nature had been making recombinant DNA long before 1972. What genetic engineering added was choice — over which sequences are joined, and over the species barrier.

Question 9

Can you think and answer how a reporter enzyme can be used to monitor transformation of host cells by foreign DNA, in addition to a selectable marker?

What the two do differently. A selectable marker — typically an antibiotic resistance gene — separates transformants from non-transformants: it helps in identifying and eliminating non-transformants and selectively permitting the growth of the transformants. But it cannot tell a cell carrying a recombinant plasmid from one carrying a plasmid that re-closed empty, because both retain the resistance gene. A reporter enzyme fills exactly that gap.

How a reporter enzyme works. A reporter enzyme is one whose activity produces an easily detected signal, usually a colour, in the presence of a suitable substrate. The foreign DNA is inserted within the coding sequence of the reporter gene. If the insert is present, the reporter gene suffers insertional inactivation and no signal is produced; if the plasmid has no insert, the reporter gene is intact and the signal appears.

The standard example. Recombinant DNA is inserted within the coding sequence of the enzyme β-galactosidase. In the presence of a chromogenic substrate, colonies whose plasmid has no insert produce blue coloured colonies; where the insert is present, the β-galactosidase gene is inactivated and the colonies produce no colour. Those colourless colonies are identified as the recombinant ones.

Why this is better than the two-antibiotic method. Selection of recombinants by inactivation of antibiotic resistance is a cumbersome procedure, because it requires simultaneous plating on two plates having different antibiotics and a comparison between them. The reporter method gives the answer on a single plate, at a glance, in a few hours.

The two are used together, not instead of each other. The antibiotic marker first removes the vast majority of cells — those that took up nothing. The reporter then sorts the survivors into recombinant and non-recombinant. One plate does the coarse filter, the colour does the fine one.

Question 10

Describe briefly the following: (a) Origin of replication   (b) Bioreactors   (c) Downstream processing

(a) Origin of replication. A specific DNA sequence, present in a chromosome or a vector, from where replication starts, and which is responsible for initiating replication. Any piece of DNA linked to this sequence can be made to replicate within the host cells, which is why an alien gene must be joined to an ori before it can be multiplied and inherited. The sequence is also responsible for controlling the copy number of the linked DNA, so if one wants to recover many copies of the target DNA it should be cloned in a vector whose origin supports a high copy number.

(b) Bioreactors. Vessels in which raw materials are biologically converted into specific products, individual enzymes and so on, using microbial, plant, animal or human cells. They were developed because small volume cultures cannot yield appreciable quantities of products; a bioreactor processes large volumes of 100 to 1000 litres of culture. It provides the optimal conditions for achieving the desired product by supplying optimum growth conditions — temperature, pH, substrate, salts, vitamins and oxygen. The most commonly used are of the stirring type: a stirred-tank reactor, usually cylindrical or with a curved base to facilitate mixing, in which the stirrer facilitates even mixing and oxygen availability throughout, or alternatively air is bubbled through, giving the sparged stirred-tank type. A bioreactor has an agitator system, an oxygen delivery system, a foam control system, a temperature control system, a pH control system and sampling ports.

(c) Downstream processing. After completion of the biosynthetic stage, the product has to be put through a series of processes before it is ready for marketing as a finished product. These processes of separation and purification are collectively referred to as downstream processing. The product then has to be formulated with suitable preservatives; such a formulation has to undergo thorough clinical trials, as in the case of drugs; and strict quality control testing is required for each product. Both the downstream processing and the quality control testing vary from product to product.

Question 11

Explain briefly: (a) PCR   (b) Restriction enzymes and DNA   (c) Chitinase

(a) PCR. PCR stands for Polymerase Chain Reaction. In this reaction, multiple copies of the gene or DNA of interest are synthesised in vitro using two sets of primers — small chemically synthesised oligonucleotides complementary to the regions of DNA flanking the target — and the enzyme DNA polymerase, which extends the primers using the nucleotides provided in the reaction and the genomic DNA as template. Each cycle has three steps: denaturation, primer annealing and extension of primers. If the process is repeated many times, the segment of DNA can be amplified to approximately a billion times. Such repeated amplification is achieved by using a thermostable DNA polymerase, isolated from the bacterium Thermus aquaticus, which remains active during the high-temperature-induced denaturation of double-stranded DNA. The amplified fragment can then be ligated with a vector for further cloning.

(b) Restriction enzymes and DNA. Restriction enzymes belong to the class of enzymes called nucleases, of which exonucleases remove nucleotides from the ends of DNA while endonucleases make cuts at specific positions within the DNA. A restriction endonuclease functions by inspecting the length of a DNA sequence; once it finds its specific recognition sequence, it binds to the DNA and cuts each of the two strands of the double helix at specific points in their sugar-phosphate backbones. Each one recognises a specific palindromic nucleotide sequence, and cuts a little away from the centre of the palindrome site but between the same two bases on the opposite strands. This leaves single-stranded overhanging stretches called sticky ends, which form hydrogen bonds with their complementary cut counterparts, and so facilitate the action of DNA ligase. When cut by the same restriction enzyme, DNA fragments from different sources have the same kind of sticky ends and can be joined end-to-end to form recombinant DNA.

(c) Chitinase. An enzyme that digests chitin, the material of the fungal cell wall. It is used during the isolation of genetic material: since DNA is enclosed within membranes, the cell must be broken open to release it, and this is achieved by treating the tissue with enzymes such as lysozyme for bacteria, cellulase for plant cells and chitinase for fungus. Without opening the fungal wall, no DNA is released, and no later step can succeed.

Question 12

Discuss with your teacher and find out how to distinguish between: (a) Plasmid DNA and Chromosomal DNA   (b) RNA and DNA   (c) Exonuclease and Endonuclease

(a) Plasmid DNA and Chromosomal DNA

FeaturePlasmid DNAChromosomal DNA
LocationExtra-chromosomal; floats freely in the cytoplasm of certain bacterial cellsThe main genetic complement of the cell
FormSmall circular ringlets of DNALong; circular in bacteria, linear and histone-bound in eukaryotes
SizeVery smallVery large — millions of base pairs
ReplicationAutonomous — replicates independently of the chromosomal DNAReplicates once per cell cycle, under cellular control
Copy numberOne or two per cell in some plasmids, 15–100 or more in othersFixed — one copy per haploid genome
Genes carriedNon-essential but useful genes, such as antibiotic resistanceAll the genes essential for the life of the cell
Use in biotechnologyUsed as a cloning vector; can be removed from a cell, engineered and reinsertedNot used as a vector; it is the source of the gene of interest

(b) RNA and DNA

FeatureRNADNA
SugarRiboseDeoxyribose — lacks the oxygen at the 2′ position
Pyrimidine basesCytosine and uracilCytosine and thymine
StrandsUsually single-strandedUsually double-stranded, as a double helix
StabilityLess stable; the 2′-OH group makes it easily degradedChemically more stable — which is why it is the genetic material of most organisms
RoleMainly transfer and expression of genetic information; also catalytic and structural rolesStorage and transmission of genetic information
Removed byRibonucleaseDeoxyribonuclease

(c) Exonuclease and Endonuclease

FeatureExonucleaseEndonuclease
Site of actionRemoves nucleotides from the ends of the DNAMakes cuts at specific positions within the DNA
Sequence specificityDoes not require a specific internal recognition sequenceA restriction endonuclease acts only at its own palindromic recognition sequence
ProductFree nucleotides, and a progressively shortened moleculeTwo or more defined fragments, often with sticky ends
Action on a circular DNACannot act — a circle has no free endsActs normally, opening the circle
Use in genetic engineeringTrimming ends; degrading linear DNA selectivelyEssential — used to isolate the gene and to open the vector

🎯 Interactive: Rapid Revision Quiz

Answer, then reveal. Select a question to begin.

🎯 Competency-Based Questions

Q1. Arrange the following in the order in which they are used in recombinant DNA technology, and state what would fail if any one were removed: DNA ligase, chilled ethanol, agarose gel, restriction endonuclease, calcium chloride, bioreactor.

The order. Chilled ethanol → restriction endonuclease → agarose gel → DNA ligase → calcium chloride → bioreactor.

What each does, and what fails without it.

Chilled ethanol precipitates the purified DNA out of solution after ribonuclease and protease have removed RNA and protein. Without it you have no pure DNA, and DNA must be in pure form, free from other macromolecules, before restriction enzymes can cut it.

Restriction endonuclease cuts at the palindromic recognition sequence, giving a defined fragment with sticky ends. Without it there is no gene of interest and no opened vector.

Agarose gel separates the fragments by size, so the right one can be stained, identified and eluted. Without it you cannot tell which fragment is which, nor check that the digestion worked.

DNA ligase joins the cut ends of insert and vector. Without it the sticky ends merely touch, held by hydrogen bonds, and come apart again — no recombinant molecule.

Calcium chloride, a divalent cation, makes the bacterial cells competent, increasing the efficiency with which DNA enters through pores in the cell wall. Without it, DNA being hydrophilic cannot cross the membrane and no transformation occurs.

Bioreactor allows 100 to 1000 litres of culture to be processed under controlled conditions. Without it you have a working construct but only laboratory-scale quantities, and small volume cultures cannot yield appreciable quantities of products.

Q2. Both meiotic crossing over and laboratory gene cloning produce recombinant DNA. Compare the two, and explain what genetic engineering added that sexual reproduction could never provide.

What is common. In both, DNA from two different sources is cut and rejoined into one continuous molecule. In meiosis this happens at pachytene of prophase I, when crossing over exchanges genetic material between non-sister chromatids of homologous chromosomes, mediated by recombinase. In the laboratory it happens in vitro, with a restriction endonuclease doing the cutting and DNA ligase the joining.

What genetic engineering added. First, choice of sequence: crossing over occurs where it occurs, and the breeder has no say in it, whereas a construct is defined before transfer. Second, and far more importantly, indifference to the species barrier. Meiotic recombination can only join homologous chromosomes within one species. Recombinant DNA technology can join DNA from different sources or genomes altogether — a human gene into a bacterial plasmid, which no amount of breeding could achieve.

Why that mattered so much. Traditional hybridisation procedures very often lead to inclusion and multiplication of undesirable genes along with the desired genes. Genetic engineering allows us to isolate and introduce only one or a set of desirable genes without introducing undesirable genes into the target organism. Sexual reproduction shuffles; engineering selects.

Q3. Before recombinant DNA technology, insulin for diabetics was extracted from the pancreases of slaughtered cattle and pigs. List the problems of that method and show how each is solved by the recombinant route.

Problem 1 — supply. Each pancreas yields a minute quantity, so the supply was limited by the number of animals slaughtered and could never match the number of patients. Solved: a recombinant protein is made by cells that multiply indefinitely, and bioreactors process 100 to 1000 litres of culture, so production is limited only by capacity.

Problem 2 — the protein is not human. Cattle and pig insulin differ slightly in sequence from human insulin, and some patients developed immune reactions to the foreign protein. Solved: because any protein-encoding gene can be expressed in a heterologous host, the human gene is used, and the product is the human protein.

Problem 3 — purity and contamination. Animal tissue extracts carry other animal proteins, and any biological material pooled from many animals carries a risk of transmitting infection. Solved: the recombinant host makes one protein of interest in a defined medium, and downstream processing provides separation and purification, formulation, clinical trials and strict quality control testing on each batch.

Problem 4 — consistency. Extracts vary from batch to batch with the animals used. Solved: a single engineered cell line in a controlled bioreactor, with regulated temperature, pH, substrate, salts, vitamins and oxygen, gives a reproducible product.

The wider point. The same argument applies to growth hormone, clotting factors and the hepatitis B vaccine — which is why so many of the recombinant proteins in medical use are human proteins that were previously scavenged from tissue.

Q4. A vector without a selectable marker, a vector without an origin of replication, and a vector with four sites for the chosen enzyme: each fails in a different way. Describe precisely what you would observe in each case after transformation.

No selectable marker. The transformation itself may succeed perfectly, but you cannot find the cells it succeeded in. A selectable marker helps in identifying and eliminating non-transformants and selectively permitting the growth of the transformants; with none, you would see a lawn of bacteria in which the handful of transformed cells — a tiny minority — are indistinguishable. You would have to screen colonies individually by PCR, which is why markers exist.

No origin of replication. Cells would take up the DNA, and on the very first plate some might even briefly show the trait. But there would be no stable transformants: the DNA cannot be copied, so it is diluted out as the cells divide and then degraded. Any colonies that did appear would lose the construct on subculture. An alien piece of DNA must be part of something carrying the sequence responsible for initiating replication.

Four sites for the chosen enzyme. The digestion would cut the vector into four fragments rather than opening it at one point, and the essential features would be separated — the ori on one fragment, the marker on another. The presence of more than one recognition site within the vector generates several fragments, which complicates gene cloning: after ligation you would get a mixture of scrambled products, and the intended recombinant would be a rare minority, if it formed at all. The remedy is to use a different enzyme that cuts this vector only once.

Q5. Explain why PCR, which merely makes copies of DNA, is often described as the single most useful technique in modern biology. Give three distinct kinds of use.

The underlying reason. DNA in a cell is present at a concentration of the order of 10−11 M — among the rarest molecules there. Almost nothing can be done chemically with a sample that dilute. PCR amplifies a chosen segment approximately a billion times, which moves it from undetectable to abundant. It converts a shortage of material into a non-problem, and shortage of material is the limiting factor in a very large number of biological questions.

Three kinds of use.

(i) As a preparative tool. The amplified fragment can be used to ligate with a vector for further cloning — so a gene can be prepared from a trace of genomic DNA instead of being laboriously isolated from a library.

(ii) As a detection tool. Because amplification only happens if the primer sites are present, a product means the target sequence is there. This is the basis of molecular diagnosis of infection and of inherited disease, long before symptoms appear.

(iii) As an identification tool. A trace of DNA from a hair, a bloodstain or an ancient bone can be amplified to a workable quantity, which is what makes forensic identification and the study of ancient DNA possible at all.

And note what makes it practical. The reaction runs unattended because the thermostable DNA polymerase from Thermus aquaticus survives the high-temperature denaturation step of every cycle. A heat-labile enzyme would have to be replenished each round, and PCR would have remained a curiosity.

🧠 Assertion–Reason Questions

For each pair, decide whether both statements are true and whether the reason correctly explains the assertion.

Assertion (A): A recombinant DNA molecule is formed during meiosis as well as in the laboratory.
Reason (R): Crossing over at pachytene exchanges genetic material between non-sister chromatids of homologous chromosomes.

Both A and R are true, and R is the correct explanation of A.

After crossing over, a chromatid carries maternal and paternal DNA joined into one continuous molecule — DNA from different sources, which is what recombinant DNA means. The difference from the laboratory case is not the chemistry but the control: meiosis cannot cross the species barrier and cannot choose the site of exchange.

Assertion (A): An exonuclease cannot linearise a circular plasmid.
Reason (R): Exonucleases remove nucleotides from the ends of DNA, and a circular molecule has no free ends.

Both A and R are true, and R is the correct explanation of A.

This is exactly why endonucleases, which make cuts at specific positions within the DNA, are the enzymes used to open a vector. It is also the basis of a useful laboratory trick: an exonuclease will destroy linear DNA in a mixture while leaving circular plasmid DNA untouched.

Assertion (A): Eukaryotic cells do not possess restriction endonucleases.
Reason (R): Eukaryotic cells contain no DNA-cutting enzymes of any kind.

A is true but R is false.

Eukaryotic cells contain many nucleases — for DNA repair, for recombination, and for degrading DNA during programmed cell death. What they lack is the bacterial restriction–modification system: a sequence-specific endonuclease paired with a methylase that protects the cell's own DNA. Bacteria need it as a defence against bacteriophage DNA; eukaryotes, with a nuclear envelope and other defences, do not.

Frequently Asked Questions - Summary and NCERT Exercises

What is recombinant DNA technology?
It is the key process of modern biotechnology, also called genetic engineering. It involves the use of restriction endonucleases, DNA ligase and appropriate plasmid or viral vectors to isolate and ferry foreign DNA into host organisms, followed by expression of the foreign gene, purification of the gene product which is the functional protein, and finally making a suitable formulation for marketing. Large scale production involves the use of bioreactors.
Name ten recombinant proteins used in medical practice.
Human insulin for diabetes mellitus, human growth hormone for pituitary dwarfism, erythropoietin for anaemia in renal failure, clotting factor VIII for haemophilia A, clotting factor IX for haemophilia B, tissue plasminogen activator for dissolving clots in heart attack and stroke, interferon alpha for chronic hepatitis and some cancers, hepatitis B surface antigen as the recombinant hepatitis B vaccine, follicle stimulating hormone for infertility, and asparaginase for acute lymphoblastic leukaemia. DNase I for cystic fibrosis and interleukin-2 for certain cancers are two more.
Are enzymes or DNA bigger in molecular size?
DNA is very much bigger. An enzyme is a protein of a few hundred amino acids, whereas a DNA molecule is a polymer of millions of nucleotides. You can also infer it from the chapter: a restriction endonuclease functions by inspecting the length of a DNA sequence until it finds its recognition site, so the DNA is the landscape and the enzyme the walker. Purified DNA can even be seen as fine threads after precipitation with chilled ethanol, which no enzyme solution shows.
At what stage of meiosis is recombinant DNA made?
During crossing over in the pachytene stage of prophase I. Crossing over is the exchange of genetic material between non-sister chromatids of homologous chromosomes, mediated by the enzyme recombinase, and it leaves each recombined chromatid carrying maternal and paternal DNA joined into one continuous molecule.
Do eukaryotic cells have restriction endonucleases?
No. Eukaryotic cells have many nucleases for repair, recombination and cell death, but not the bacterial restriction-modification system. Restriction enzymes evolved in bacteria as a defence that restricts the growth of bacteriophage, paired with a methylase that protects the cell's own DNA. A eukaryote, which keeps its DNA inside a nucleus and has other defences such as interferons and RNA silencing, has no need of such a system, and all of the more than 900 known restriction enzymes were isolated from over 230 strains of bacteria.
What advantages do stirred tank bioreactors have over shake flasks, besides aeration and mixing?
They provide control of temperature and pH through dedicated control systems; they have sampling ports so culture can be withdrawn periodically without opening the vessel; they have a foam control system; they process large volumes of 100 to 1000 litres, whereas small volume cultures cannot yield appreciable quantities; they can be run as a continuous culture system that keeps cells in their most active log phase and so gives a larger biomass and higher yields; and being closed and sterilisable they maintain the contamination-free ambience that bioprocess engineering requires.
Give five examples of palindromic DNA sequences.
EcoR I recognises GAATTC, BamH I recognises GGATCC, Hind III recognises AAGCTT, Pst I recognises CTGCAG and Sal I recognises GTCGAC. Each reads the same on both strands in the 5' to 3' direction. To create one yourself, choose any three bases and make the second half their reverse complement: TGC gives TGCGCA, which is the site of Fsp I.
How can a reporter enzyme be used to monitor transformation?
A reporter enzyme produces an easily detected signal, usually a colour, with a suitable substrate. The foreign DNA is inserted within the coding sequence of the reporter gene, so an insert causes insertional inactivation and the signal disappears. With beta-galactosidase and a chromogenic substrate, colonies without an insert are blue and colonies with an insert are colourless. This is more convenient than selection by inactivation of antibiotic resistance, which requires simultaneous plating on two plates with different antibiotics.
Explain PCR briefly.
PCR stands for Polymerase Chain Reaction. Multiple copies of the gene of interest are synthesised in vitro using two sets of primers, which are small chemically synthesised oligonucleotides complementary to the flanking regions of DNA, and the enzyme DNA polymerase, which extends the primers using the nucleotides provided and the genomic DNA as template. Each cycle has three steps: denaturation, primer annealing and extension of primers. Repeated many times, the segment can be amplified about a billion times, using a thermostable DNA polymerase from Thermus aquaticus that survives the high temperature denaturation step.
What is the difference between plasmid DNA and chromosomal DNA?
Plasmid DNA is small, circular, extra-chromosomal DNA that floats freely in the cytoplasm of certain bacterial cells and replicates autonomously, independent of the chromosomal DNA; its copy number ranges from one or two per cell to 15 to 100 or more, and it carries non-essential but useful genes such as antibiotic resistance, which is why it is used as a cloning vector. Chromosomal DNA is the very large main genetic complement of the cell, carrying all the essential genes, replicating once per cell cycle under cellular control.
What is the difference between an exonuclease and an endonuclease?
An exonuclease removes nucleotides from the ends of the DNA, so it cannot act on a circular molecule which has no free ends, and it does not need an internal recognition sequence. An endonuclease makes cuts at specific positions within the DNA; a restriction endonuclease acts only at its own palindromic recognition sequence and produces defined fragments, often with sticky ends. Only endonucleases can open a vector for an insert.
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