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Nerve Impulse Generation Conduction

🎓 Class 11 Biology CBSE Theory Ch 18 – Neural Control and Coordination ⏱ ~14 min
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Generation and Conduction of Nerve Impulse

Neurons are excitable cells because their membranes are in a polarised state. This part answers three linked questions: why the membrane of a neuron is polarised at rest, how a stimulus generates a nerve impulse, and how that impulse travels the length of an axon.

Why the Resting Membrane Is Polarised

Different types of ion channels are present on the neural membrane. These ion channels are selectively permeable to different ions. When a neuron is not conducting any impulse, i.e., resting, the following holds:

  • the axonal membrane is comparatively more permeable to potassium ions (K+);
  • it is nearly impermeable to sodium ions (Na+);
  • it is impermeable to the negatively charged proteins present in the axoplasm.

Consequently, the axoplasm inside the axon contains a high concentration of K+ and negatively charged proteins and a low concentration of Na+. In contrast, the fluid outside the axon contains a low concentration of K+ and a high concentration of Na+, and thus a concentration gradient is formed.

These ionic gradients across the resting membrane are maintained by the active transport of ions by the sodium-potassium pump, which transports 3 Na+ outwards for 2 K+ into the cell.

As a result, the outer surface of the axonal membrane possesses a positive charge while its inner surface becomes negatively charged, and the membrane therefore is polarised. The electrical potential difference across the resting plasma membrane is called as the resting potential.

Ion distribution across the resting axonal membrane
FeatureInside the axon (axoplasm)Outside the axon
K+ concentrationHighLow
Na+ concentrationLowHigh
Negatively charged proteinsPresent (membrane is impermeable to them)
Membrane permeability at restComparatively more permeable to K+; nearly impermeable to Na+
Net charge on the membrane surfaceNegative (inner surface)Positive (outer surface)
Maintained bySodium-potassium pump: 3 Na+ out for 2 K+ in

Two separate causes of the resting potential. First, selective permeability — K+ can leak out but Na+ cannot easily come in, and the large negative proteins cannot leave at all. Second, active transport — the sodium-potassium pump moves 3 positive charges out for every 2 it brings in, which by itself leaves the outside more positive. Both work in the same direction, so the outer surface is positive and the inner surface negative.

Generation of a Nerve Impulse

When a stimulus is applied at a site — call it point A — on the polarised membrane, the membrane at the site A becomes freely permeable to Na+. This leads to a rapid influx of Na+, followed by the reversal of the polarity at that site: the outer surface of the membrane becomes negatively charged and the inner side becomes positively charged.

The polarity of the membrane at the site A is thus reversed, and hence depolarised. The electrical potential difference across the plasma membrane at the site A is called the action potential, which is in fact termed as a nerve impulse.

So a nerve impulse is not a substance travelling down a nerve. It is a local, momentary reversal of membrane polarity, regenerated again and again at successive points. Nothing material moves along the axon — what moves is the event.

Conduction Along the Axon

At sites immediately ahead — call it site B — the axon membrane still has a positive charge on the outer surface and a negative charge on its inner surface. As a result:

  • a current flows on the inner surface from site A to site B;
  • on the outer surface current flows from site B to site A, to complete the circuit of current flow.

Hence the polarity at the site is reversed, and an action potential is generated at site B. Thus the impulse (action potential) generated at site A arrives at site B. The sequence is repeated along the length of the axon and consequently the impulse is conducted.

Restoring the Resting State

The rise in the stimulus-induced permeability to Na+ is extremely short-lived. It is quickly followed by a rise in permeability to K+. Within a fraction of a second, K+ diffuses outside the membrane and restores the resting potential of the membrane at the site of excitation, and the fibre becomes once more responsive to further stimulation.

Impulse conduction through an axon (at points A and B) A +++ +++ +++ ++ ++ Na⁺ influx at A → polarity reversed (depolarised) A B (still polarised) inner surface: current A → B outer surface: current B → A B ++ +++ +++ ++ +++ A repolarised: K⁺ diffuses out, resting potential restored B now depolarised — impulse has advanced the sequence repeats along the length of the axon
Resting potential and action potential compared
FeatureResting potentialAction potential
State of the neuronNot conducting any impulse (resting)Stimulated at that site
PermeabilityComparatively more permeable to K+, nearly impermeable to Na+Freely permeable to Na+ at that site
Outer surface of membranePositiveNegative
Inner surface of membraneNegativePositive
State of membranePolarisedDepolarised
Also calledThe electrical potential difference across the resting plasma membraneA nerve impulse
DurationMaintained so long as the neuron is not stimulatedExtremely short-lived; quickly followed by a rise in K+ permeability
📐 Activity — A Row of Dominoes as a Model of Conduction

Stand a long row of dominoes upright, each just close enough to knock over the next. Tip the first one and watch. Then stand them all up again and this time tip the one in the middle of the row.

Scenario: When you tipped the middle domino, the fall spread in both directions along the row. Yet a nerve impulse in a living neuron travels in one direction, from dendrite to axon terminal. Using the account of conduction above, explain (i) why the domino model captures conduction well, (ii) what the falling of a single domino corresponds to, and (iii) what the model is missing that makes real conduction one-way.

(i) Why the model works. No domino travels along the row — each one only topples its neighbour. Similarly, no substance travels along the axon: the action potential at site A causes a local current flow which reverses the polarity at site B, so an action potential is generated afresh at B. The signal is regenerated at every point rather than transmitted as a moving object, which is why it does not weaken with distance.

(ii) One domino falling corresponds to one point of the membrane being depolarised — the rapid influx of Na+ reversing the polarity at that site, which is the action potential, i.e. the nerve impulse.

(iii) What the model is missing. A fallen domino stays fallen, whereas the membrane at the excited site is repolarised within a fraction of a second: K+ diffuses outside and restores the resting potential, after which the fibre becomes once more responsive to further stimulation. This recovery takes a little time, so immediately behind an advancing impulse the membrane has not yet recovered and cannot be re-excited. That is what makes real conduction effectively one-way. A better model would be dominoes that spring upright again a moment after falling.

🎯 Interactive: Step Through the Nerve Impulse

Select a stage to see what is happening to the ions, the membrane and the charge.

🎯 Competency-Based Questions

Q1. A drug is applied to an axon that completely blocks the sodium-potassium pump but leaves all ion channels intact. The axon is stimulated immediately, and then again after a long interval. Predict both outcomes and explain.

Immediately after blocking: the axon still conducts. The concentration gradients — high K+ and low Na+ inside, low K+ and high Na+ outside — are already established, and a single impulse moves only a very small number of ions. So a stimulus will still make the membrane freely permeable to Na+ at that site, Na+ will rush in, polarity will reverse and an action potential will be generated and conducted normally.

After a long interval: conduction fails. The ionic gradients across the resting membrane are maintained by the active transport of ions by the sodium-potassium pump, which transports 3 Na+ outwards for 2 K+ into the cell. With the pump blocked, every impulse and every leak runs the gradients down and nothing restores them. Once the concentration difference is gone, an opening of sodium channels produces no inward rush, no depolarisation and therefore no nerve impulse.

The principle: the pump does not create the impulse — it maintains the stored gradient that the impulse spends. Like a battery, it must be recharged between uses.

Q2. Explain why the resting membrane is negative on the inside even though the sodium-potassium pump moves potassium into the cell. Use both permeability and stoichiometry in your answer.

Permeability. At rest, the axonal membrane is comparatively more permeable to K+ and nearly impermeable to Na+. Since K+ is at high concentration inside, it tends to diffuse outwards down its gradient, carrying positive charge out of the cell. Sodium cannot come in to replace that charge, because the membrane is nearly impermeable to it. In addition, the membrane is impermeable to the negatively charged proteins present in the axoplasm, so those negative charges are trapped inside and cannot follow the potassium out.

Stoichiometry. The pump transports 3 Na+ outwards for 2 K+ into the cell. That is three positive charges out for every two in — a net loss of one positive charge from the interior per cycle. So the pump's own action also makes the outside more positive, despite carrying potassium inwards.

Together: outward leak of K+, trapped internal anions, and a pump with an unequal ratio all push in the same direction. The outer surface of the axonal membrane possesses a positive charge while its inner surface becomes negatively charged — the membrane is polarised.

Q3. A nerve impulse travelling a long axon arrives at the far end just as strong as when it began, unlike an electrical signal in a wire, which weakens with distance. Account for this difference.

In a wire the original signal itself travels the whole distance and is progressively lost to resistance, so it arrives weakened.

In an axon the signal is regenerated afresh at every point. The action potential at site A causes current to flow on the inner surface from A to B and on the outer surface from B to A, completing the circuit. This reverses the polarity at B, so a new action potential is generated at site B. That new action potential has the same magnitude as the one at A, because its size is set by the ion gradients and permeability of the membrane at B — not by how strong the signal at A was.

Since the sequence is repeated along the length of the axon, each point produces a full-sized impulse. Nothing is being carried and attenuated; the impulse is rebuilt at every step, which is why distance does not weaken it.

Q4. Why is it essential that the stimulus-induced rise in sodium permeability is "extremely short-lived"? Predict what would happen to a neuron in which sodium permeability stayed high after depolarisation.

Why it must be brief. The rise in permeability to Na+ is quickly followed by a rise in permeability to K+, and within a fraction of a second K+ diffuses outside the membrane and restores the resting potential at the site of excitation. Only then does the fibre become once more responsive to further stimulation. A neuron that could not recover could not carry a second impulse.

If sodium permeability stayed high: Na+ would continue to enter and the site would remain depolarised, with the inner surface positive. The resting potential would never be restored. Three consequences follow:

(i) the neuron could not fire again, since there is no polarised state left to reverse — it would be permanently refractory at that site;

(ii) information could no longer be encoded, because a nervous system conveys intensity and duration through repeated impulses, which requires repeated recovery;

(iii) the ionic gradients would run down as sodium equilibrated across the membrane, and the sodium-potassium pump would be unable to keep pace.

Q5. Two axons of equal diameter are compared: one myelinated, one not. Using the account of conduction in this part, explain where the impulse can and cannot be regenerated in each, and hence which conducts faster.

An action potential can be generated only where ions can cross the membrane — that is, where the membrane can become freely permeable to Na+ and allow the rapid influx that reverses polarity.

Non-myelinated axon: the axon is enclosed by a Schwann cell that does not form a myelin sheath, so the membrane is available along its whole length. The sequence of depolarisation must therefore be repeated at every successive point, step by step, all the way along.

Myelinated axon: the axon is enveloped with Schwann cells forming a myelin sheath, and the membrane is exposed only at the nodes of Ranvier — the gaps between two adjacent myelin sheaths. The local current generated at one node therefore reaches the next node and regenerates the action potential there, effectively skipping the insulated stretches in between.

Conclusion: the myelinated axon needs far fewer regeneration events to cover the same distance, so it conducts faster. This is consistent with myelinated nerve fibres being found in the spinal and cranial nerves, where impulses must travel long distances quickly.

🧠 Assertion–Reason Questions

For each pair, decide whether both statements are true and whether the reason correctly explains the assertion.

Assertion (A): The outer surface of a resting axonal membrane is positively charged.
Reason (R): The sodium-potassium pump transports 3 Na+ outwards for 2 K+ into the cell.

Both A and R are true, and R is a correct explanation of A.

Moving three positive charges out for every two brought in leaves a net excess of positive charge outside. Selective permeability — high to K+, nearly nil to Na+, and nil to the internal negatively charged proteins — contributes to the same result.

Assertion (A): An action potential is termed a nerve impulse.
Reason (R): An action potential is the electrical potential difference across the plasma membrane at a depolarised site.

Both A and R are true, and R is the correct explanation of A.

NCERT states directly that the electrical potential difference across the plasma membrane at the stimulated site is called the action potential, which is in fact termed as a nerve impulse. The impulse is therefore an electrical event of the membrane, not a substance.

Assertion (A): After an impulse passes, the fibre immediately becomes responsive to further stimulation.
Reason (R): The rise in permeability to Na+ is extremely short-lived.

A is false but R is true.

The rise in sodium permeability is indeed extremely short-lived. But the fibre does not become responsive immediately: the sodium rise must first be followed by a rise in permeability to K+, and it is only after K+ diffuses outside and restores the resting potential — within a fraction of a second — that the fibre becomes once more responsive to further stimulation. Recovery requires repolarisation, not merely the end of the sodium influx.

Frequently Asked Questions - Generation and Conduction of Nerve Impulse

Why are neurons called excitable cells?
Neurons are excitable cells because their membranes are in a polarised state. Different types of ion channels on the neural membrane are selectively permeable to different ions, which sets up a charge difference across the membrane that a stimulus can reverse.
What is resting potential?
The electrical potential difference across the resting plasma membrane of a neuron is called the resting potential. In this state the outer surface of the axonal membrane possesses a positive charge while its inner surface is negatively charged, so the membrane is said to be polarised.
Why is the resting axonal membrane polarised?
At rest the axonal membrane is comparatively more permeable to potassium ions and nearly impermeable to sodium ions, and it is also impermeable to the negatively charged proteins in the axoplasm. Consequently the axoplasm has a high concentration of K+ and negatively charged proteins and a low concentration of Na+, while the fluid outside has a low concentration of K+ and a high concentration of Na+. These gradients are maintained by the sodium-potassium pump.
What does the sodium-potassium pump do?
The sodium-potassium pump maintains the ionic gradients across the resting membrane by the active transport of ions, transporting 3 Na+ outwards for 2 K+ into the cell. Because it moves three positive ions out for every two brought in, it also contributes to making the outer surface of the membrane positive.
What is an action potential?
When a stimulus is applied at a site on the polarised membrane, that site becomes freely permeable to Na+, leading to a rapid influx of Na+ and a reversal of polarity so that the outer surface becomes negative and the inner side positive. The electrical potential difference across the plasma membrane at this depolarised site is called the action potential, which is in fact termed a nerve impulse.
What is depolarisation of a nerve fibre?
Depolarisation is the reversal of the polarity of the membrane at a stimulated site. The membrane there becomes freely permeable to Na+, sodium rushes in, and the outer surface becomes negatively charged while the inner side becomes positively charged.
How is a nerve impulse conducted along an axon?
At sites immediately ahead of the depolarised site, the membrane still has a positive outer surface and a negative inner surface. Current therefore flows on the inner surface from the excited site to the site ahead, and on the outer surface in the opposite direction, completing the circuit. This reverses the polarity at the site ahead and generates an action potential there. The sequence is repeated along the length of the axon and consequently the impulse is conducted.
How is the resting potential restored after an impulse?
The stimulus-induced rise in permeability to Na+ is extremely short-lived and is quickly followed by a rise in permeability to K+. Within a fraction of a second K+ diffuses outside the membrane and restores the resting potential at the site of excitation, after which the fibre becomes once more responsive to further stimulation.
What is the role of Na+ in the generation of an action potential?
At rest the membrane is nearly impermeable to Na+, and sodium is at high concentration outside and low concentration inside. When a stimulus makes the membrane freely permeable to Na+ at a site, sodium rushes inwards down this gradient. This rapid influx of positive charge reverses the polarity of the membrane at that site, producing the depolarisation that constitutes the action potential, or nerve impulse.
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