This MCQ module is based on: Nerve Impulse Generation Conduction
Nerve Impulse Generation Conduction
This assessment will be based on: Nerve Impulse Generation Conduction
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Generation and Conduction of Nerve Impulse
Neurons are excitable cells because their membranes are in a polarised state. This part answers three linked questions: why the membrane of a neuron is polarised at rest, how a stimulus generates a nerve impulse, and how that impulse travels the length of an axon.
Why the Resting Membrane Is Polarised
Different types of ion channels are present on the neural membrane. These ion channels are selectively permeable to different ions. When a neuron is not conducting any impulse, i.e., resting, the following holds:
- the axonal membrane is comparatively more permeable to potassium ions (K+);
- it is nearly impermeable to sodium ions (Na+);
- it is impermeable to the negatively charged proteins present in the axoplasm.
Consequently, the axoplasm inside the axon contains a high concentration of K+ and negatively charged proteins and a low concentration of Na+. In contrast, the fluid outside the axon contains a low concentration of K+ and a high concentration of Na+, and thus a concentration gradient is formed.
These ionic gradients across the resting membrane are maintained by the active transport of ions by the sodium-potassium pump, which transports 3 Na+ outwards for 2 K+ into the cell.
As a result, the outer surface of the axonal membrane possesses a positive charge while its inner surface becomes negatively charged, and the membrane therefore is polarised. The electrical potential difference across the resting plasma membrane is called as the resting potential.
| Feature | Inside the axon (axoplasm) | Outside the axon |
|---|---|---|
| K+ concentration | High | Low |
| Na+ concentration | Low | High |
| Negatively charged proteins | Present (membrane is impermeable to them) | — |
| Membrane permeability at rest | Comparatively more permeable to K+; nearly impermeable to Na+ | |
| Net charge on the membrane surface | Negative (inner surface) | Positive (outer surface) |
| Maintained by | Sodium-potassium pump: 3 Na+ out for 2 K+ in | |
Two separate causes of the resting potential. First, selective permeability — K+ can leak out but Na+ cannot easily come in, and the large negative proteins cannot leave at all. Second, active transport — the sodium-potassium pump moves 3 positive charges out for every 2 it brings in, which by itself leaves the outside more positive. Both work in the same direction, so the outer surface is positive and the inner surface negative.
Generation of a Nerve Impulse
When a stimulus is applied at a site — call it point A — on the polarised membrane, the membrane at the site A becomes freely permeable to Na+. This leads to a rapid influx of Na+, followed by the reversal of the polarity at that site: the outer surface of the membrane becomes negatively charged and the inner side becomes positively charged.
The polarity of the membrane at the site A is thus reversed, and hence depolarised. The electrical potential difference across the plasma membrane at the site A is called the action potential, which is in fact termed as a nerve impulse.
So a nerve impulse is not a substance travelling down a nerve. It is a local, momentary reversal of membrane polarity, regenerated again and again at successive points. Nothing material moves along the axon — what moves is the event.
Conduction Along the Axon
At sites immediately ahead — call it site B — the axon membrane still has a positive charge on the outer surface and a negative charge on its inner surface. As a result:
- a current flows on the inner surface from site A to site B;
- on the outer surface current flows from site B to site A, to complete the circuit of current flow.
Hence the polarity at the site is reversed, and an action potential is generated at site B. Thus the impulse (action potential) generated at site A arrives at site B. The sequence is repeated along the length of the axon and consequently the impulse is conducted.
Restoring the Resting State
The rise in the stimulus-induced permeability to Na+ is extremely short-lived. It is quickly followed by a rise in permeability to K+. Within a fraction of a second, K+ diffuses outside the membrane and restores the resting potential of the membrane at the site of excitation, and the fibre becomes once more responsive to further stimulation.
| Feature | Resting potential | Action potential |
|---|---|---|
| State of the neuron | Not conducting any impulse (resting) | Stimulated at that site |
| Permeability | Comparatively more permeable to K+, nearly impermeable to Na+ | Freely permeable to Na+ at that site |
| Outer surface of membrane | Positive | Negative |
| Inner surface of membrane | Negative | Positive |
| State of membrane | Polarised | Depolarised |
| Also called | The electrical potential difference across the resting plasma membrane | A nerve impulse |
| Duration | Maintained so long as the neuron is not stimulated | Extremely short-lived; quickly followed by a rise in K+ permeability |
Stand a long row of dominoes upright, each just close enough to knock over the next. Tip the first one and watch. Then stand them all up again and this time tip the one in the middle of the row.
(i) Why the model works. No domino travels along the row — each one only topples its neighbour. Similarly, no substance travels along the axon: the action potential at site A causes a local current flow which reverses the polarity at site B, so an action potential is generated afresh at B. The signal is regenerated at every point rather than transmitted as a moving object, which is why it does not weaken with distance.
(ii) One domino falling corresponds to one point of the membrane being depolarised — the rapid influx of Na+ reversing the polarity at that site, which is the action potential, i.e. the nerve impulse.
(iii) What the model is missing. A fallen domino stays fallen, whereas the membrane at the excited site is repolarised within a fraction of a second: K+ diffuses outside and restores the resting potential, after which the fibre becomes once more responsive to further stimulation. This recovery takes a little time, so immediately behind an advancing impulse the membrane has not yet recovered and cannot be re-excited. That is what makes real conduction effectively one-way. A better model would be dominoes that spring upright again a moment after falling.
🎯 Interactive: Step Through the Nerve Impulse
Select a stage to see what is happening to the ions, the membrane and the charge.
🎯 Competency-Based Questions
Immediately after blocking: the axon still conducts. The concentration gradients — high K+ and low Na+ inside, low K+ and high Na+ outside — are already established, and a single impulse moves only a very small number of ions. So a stimulus will still make the membrane freely permeable to Na+ at that site, Na+ will rush in, polarity will reverse and an action potential will be generated and conducted normally.
After a long interval: conduction fails. The ionic gradients across the resting membrane are maintained by the active transport of ions by the sodium-potassium pump, which transports 3 Na+ outwards for 2 K+ into the cell. With the pump blocked, every impulse and every leak runs the gradients down and nothing restores them. Once the concentration difference is gone, an opening of sodium channels produces no inward rush, no depolarisation and therefore no nerve impulse.
The principle: the pump does not create the impulse — it maintains the stored gradient that the impulse spends. Like a battery, it must be recharged between uses.
Permeability. At rest, the axonal membrane is comparatively more permeable to K+ and nearly impermeable to Na+. Since K+ is at high concentration inside, it tends to diffuse outwards down its gradient, carrying positive charge out of the cell. Sodium cannot come in to replace that charge, because the membrane is nearly impermeable to it. In addition, the membrane is impermeable to the negatively charged proteins present in the axoplasm, so those negative charges are trapped inside and cannot follow the potassium out.
Stoichiometry. The pump transports 3 Na+ outwards for 2 K+ into the cell. That is three positive charges out for every two in — a net loss of one positive charge from the interior per cycle. So the pump's own action also makes the outside more positive, despite carrying potassium inwards.
Together: outward leak of K+, trapped internal anions, and a pump with an unequal ratio all push in the same direction. The outer surface of the axonal membrane possesses a positive charge while its inner surface becomes negatively charged — the membrane is polarised.
In a wire the original signal itself travels the whole distance and is progressively lost to resistance, so it arrives weakened.
In an axon the signal is regenerated afresh at every point. The action potential at site A causes current to flow on the inner surface from A to B and on the outer surface from B to A, completing the circuit. This reverses the polarity at B, so a new action potential is generated at site B. That new action potential has the same magnitude as the one at A, because its size is set by the ion gradients and permeability of the membrane at B — not by how strong the signal at A was.
Since the sequence is repeated along the length of the axon, each point produces a full-sized impulse. Nothing is being carried and attenuated; the impulse is rebuilt at every step, which is why distance does not weaken it.
Why it must be brief. The rise in permeability to Na+ is quickly followed by a rise in permeability to K+, and within a fraction of a second K+ diffuses outside the membrane and restores the resting potential at the site of excitation. Only then does the fibre become once more responsive to further stimulation. A neuron that could not recover could not carry a second impulse.
If sodium permeability stayed high: Na+ would continue to enter and the site would remain depolarised, with the inner surface positive. The resting potential would never be restored. Three consequences follow:
(i) the neuron could not fire again, since there is no polarised state left to reverse — it would be permanently refractory at that site;
(ii) information could no longer be encoded, because a nervous system conveys intensity and duration through repeated impulses, which requires repeated recovery;
(iii) the ionic gradients would run down as sodium equilibrated across the membrane, and the sodium-potassium pump would be unable to keep pace.
An action potential can be generated only where ions can cross the membrane — that is, where the membrane can become freely permeable to Na+ and allow the rapid influx that reverses polarity.
Non-myelinated axon: the axon is enclosed by a Schwann cell that does not form a myelin sheath, so the membrane is available along its whole length. The sequence of depolarisation must therefore be repeated at every successive point, step by step, all the way along.
Myelinated axon: the axon is enveloped with Schwann cells forming a myelin sheath, and the membrane is exposed only at the nodes of Ranvier — the gaps between two adjacent myelin sheaths. The local current generated at one node therefore reaches the next node and regenerates the action potential there, effectively skipping the insulated stretches in between.
Conclusion: the myelinated axon needs far fewer regeneration events to cover the same distance, so it conducts faster. This is consistent with myelinated nerve fibres being found in the spinal and cranial nerves, where impulses must travel long distances quickly.
🧠 Assertion–Reason Questions
For each pair, decide whether both statements are true and whether the reason correctly explains the assertion.
Both A and R are true, and R is a correct explanation of A.
Moving three positive charges out for every two brought in leaves a net excess of positive charge outside. Selective permeability — high to K+, nearly nil to Na+, and nil to the internal negatively charged proteins — contributes to the same result.
Both A and R are true, and R is the correct explanation of A.
NCERT states directly that the electrical potential difference across the plasma membrane at the stimulated site is called the action potential, which is in fact termed as a nerve impulse. The impulse is therefore an electrical event of the membrane, not a substance.
A is false but R is true.
The rise in sodium permeability is indeed extremely short-lived. But the fibre does not become responsive immediately: the sodium rise must first be followed by a rise in permeability to K+, and it is only after K+ diffuses outside and restores the resting potential — within a fraction of a second — that the fibre becomes once more responsive to further stimulation. Recovery requires repolarisation, not merely the end of the sodium influx.