This MCQ module is based on: Similarity and Ratios
Similarity and Ratios
This mathematics assessment will be based on: Similarity and Ratios
Targeting Class 8 level in Algebra, with Basic difficulty.
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7.1 Observing Similarity in Change
We are all familiar with digital images. We often change their size and orientation to suit our needs. Observe the set of five tiger images below — Image A, Image B, Image C, Image D and Image E.
We can see that all the images are of different sizes.
Images A, C, and D look similar?, even though they have different sizes.
No, they are slightly distorted. The tiger appears elongated in B and compressed and fatter in E.
Can we observe any pattern to answer this question? Perhaps by measuring the widths and heights of the rectangles holding each image.
| Image | Width (in mm) | Height (in mm) |
|---|---|---|
| Image A | 60 | 40 |
| Image B | 40 | 40 |
| Image C | 30 | 20 |
| Image D | 90 | 60 |
| Image E | 60 | 60 |
When we compare image A with C, we notice that the width of C is half that of A. The height is also half of A. Both the width and height of image A have changed by the same factor (namely, \(\frac{1}{2}\)) to obtain image C. Since the widths and heights have changed by the same factor, the images look similar.
When we compare image A with image D, we notice that the width of D is \(\frac{90}{60}=\frac{3}{2}\) times that of A. The height is also \(\frac{60}{40}=\frac{3}{2}\) times that of A. Again, both measures have changed by the same factor — so the images look similar.
Now compare A with B. The height of B is the same as A (40 mm), but the width has been reduced by the factor \(\frac{40}{60}=\frac{2}{3}\). Since width and height did not change by the same factor, image B looks different. Similarly for image E, the width has been kept the same as A but the height has changed — so E looks different.
- Draw a simple picture on a grid — say, a house fitting in a 4 × 3 cell box.
- Make a copy where every measurement (width and height) is doubled (8 × 6 cells). Sketch the same house inside.
- Make another copy where only the width is doubled (8 × 3 cells). Draw the house inside.
- Compare the three figures side by side.
Observation: The first copy (both doubled) looks like a bigger version of the original — the shape is preserved. The second copy (only width doubled) looks stretched. The first change is proportional; the second is not. This is the core idea of similarity.
7.2 Ratios
We use the notion of a ratio? to represent such proportional relationships in mathematics. We can say that the ratio of width to height of image A is
60 : 40
The numbers 60 and 40 are called the terms of the ratio. The ratio of width to height of image C is 30 : 20, and that of image D is 90 : 60.
So, in Image A, we can say that for every 60 mm of width, there are 40 mm of height.
We can say that the ratios of width to height of images A, C, and D are proportional because the terms of these ratios change by the same factor. Let us see how:
Image A → 60 : 40
Multiplying both the terms by \(\frac12\), we get \(60 \times \frac12 : 40 \times \frac12 = 30:20\), which is the ratio of width to height in image C.
Multiply both terms by \(\frac{3}{2}\): \(60 \times \frac32 : 40 \times \frac32 = 90:60\) ✓
A more systematic way to compare whether the ratios are proportional is to reduce them to their simplest form and see if these simplest forms are the same.
7.3 Ratios in their Simplest Form
We can reduce ratios to their simplest form by dividing the terms by their HCF.
In image A, the terms are 60 and 40. What is the HCF of 60 and 40? It is 20. Dividing the terms by 20, we get the ratio of image A to be 3 : 2 in its simplest form.
The ratio of image D is 90 : 60. Dividing both terms by 30 (HCF of 90 and 60), we get the simplest form to be 3 : 2. The ratios of images A and D are proportional as well.
The ratio of image B is 40 : 40; in simplest form, it is 1 : 1.
The ratio of image E is 60 : 60; in simplest form, it is also 1 : 1.
These ratios are not the same as 3 : 2. So, we can say that the ratios of width to height of images B and E are not proportional to the ratios of images A, C, and D.
So \(a : b :: c : d\) indicates that the ratios \(a : b\) and \(c : d\) are proportional.
7.4 Problem Solving with Proportional Reasoning
Example 1: Testing Proportionality
Are the ratios 3 : 4 and 72 : 96 proportional?
To find the simplest form of 72 : 96, we need to divide both terms by their HCF.
HCF of 72 and 96 = 24. Dividing, we get \(72 \div 24 : 96 \div 24 = 3 : 4\).
Since both ratios in simplest form are the same, they are proportional. So \(3:4 :: 72:96\). ✓
Example 2: Kesang's Lemonade
Kesang wanted to make lemonade for a celebration. She made 6 glasses of lemonade in a vessel and added 10 spoons of sugar to the drink. Her father expected more people to join the celebration. So he asked her to make 18 more glasses of lemonade.
To maintain the same sweetness, the ratio of the number of glasses of lemonade to the number of spoons of sugar should be proportional. For 6 glasses, she added 10 spoons of sugar. The ratio of glasses of sugar is 6 : 10. If she needs to make 18 more glasses of lemonade, how many spoons of sugar should she use? We model this as
6 : 10 :: 18 : ?
We know that each term in the ratio must change by the same factor, for the ratios to be proportional.
The first term has increased from 6 to 18. To find the factor of change, we can divide 18 by 6 to get 3.
The second term should also change by the same factor. When 10 increases by a factor of 3, it becomes \(10 \times 3 = 30\). So the ratio becomes 6 : 10 :: 18 : 30. Kesang should use 30 spoons of sugar.
Example 3: Nitin's Building
Nitin and Hari were constructing a compound wall around their house. Nitin was building the longer side, 60 ft in length, and Hari was building the shorter side, 40 ft in length. Nitin used 3 bags of cement but Hari used only 2 bags of cement. Nitin was worried that the wall Hari built would not be as strong as the wall he built because she used less cement.
The ratio in Nitin's case is 60 : 3, i.e., 20 : 1 (in simplest form).
The ratio in Hari's case is 40 : 2, i.e., 20 : 1 (in simplest form).
Since both ratios are proportional, the walls are equally strong. Nitin should not worry!
Competency-Based Questions
Assertion–Reason Questions
Reason (R): Both ratios reduce to 2 : 3 in their simplest form.
Reason (R): Both images share the same width of 60 mm.
Reason (R): Rectangles are similar when both their width and height change by the same factor.