આ MCQ મોડ્યુલ આના પર આધારિત છે: Special Purpose Diodes
Special Purpose Diodes
આ મૂલ્યાંકન આના પર આધારિત હશે: Special Purpose Diodes
મૂલ્યાંકન બનાવવામાં તેમની સામગ્રી સામેલ કરવા ચિત્રો, PDF અથવા Word દસ્તાવેજ અપલોડ કરો.
Special Purpose Diodes
14.8 Special-Purpose p-n Junction Diodes
Beyond rectification, the p-n junction can be engineered to perform a variety of specialised functions. By tuning the doping levels, the band gap of the semiconductor and the device geometry, we get four important "special diodes":
| Device | Operating bias | Function |
|---|---|---|
| Zener diode | Reverse (at breakdown) | Voltage regulation / reference |
| Photodiode | Reverse | Light → current (sensor) |
| LED (Light-Emitting Diode) | Forward | Current → light (emitter) |
| Solar cell | No bias (illumination only) | Light → DC voltage (energy harvester) |
14.8.1 Zener Diode — Voltage Regulator
A Zener diode is a heavily doped p-n junction designed to operate in the breakdown region under reverse bias. Two distinct breakdown mechanisms can occur:
- Zener breakdown (heavy doping, V_br < 6 V): the very thin depletion region produces a huge electric field that rips electrons out of covalent bonds. Tunnelling current rises sharply.
- Avalanche breakdown (lighter doping, V_br > 6 V): high-energy minority carriers ionise lattice atoms by impact, multiplying the carrier population.
Both produce the same effect: once V exceeds V_z, the diode current can change by orders of magnitude while V across the diode remains nearly constant at V_z. This is the property exploited for voltage regulation.
How regulation works
If V_in increases, the extra voltage drops across R_s while V across Zener stays at V_z. If V_in decreases below V_z, the Zener stops conducting and acts like an open circuit — so V_in must always exceed V_z. The Zener current adjusts itself to keep V_out fixed.
Worked Example — Designing a regulator
Total current through R_s = I_load + I_Zener = 20 + 5 = 25 mA.
Voltage drop across R_s = V_in − V_z = 9.0 − 6.2 = 2.8 V.
\[ R_s = \frac{V_{in} - V_z}{I_{R_s}} = \frac{2.8}{0.025} = \mathbf{112\ \Omega} \]Choose the nearest standard value: 100 Ω or 120 Ω.
14.8.2 Optoelectronic Devices — Photodiode and LED
Both rely on the relationship: energy of a photon = E_g of the semiconductor. If hν ≥ E_g, a photon striking the depletion region creates an electron-hole pair (light → current). Conversely, an electron-hole pair recombining releases a photon of energy ≈ E_g (current → light).
Photodiode
A photodiode is a junction diode operated under reverse bias and exposed to light. The transparent window above the junction lets photons reach the depletion region. Each absorbed photon creates an e-h pair which the field separates, producing additional reverse current proportional to the light intensity.
Why operate under reverse bias and not no-bias? Because reverse bias gives a wider depletion region, and the change in fractional current is much larger and more easily measured. Photodiodes are used in TV remote receivers, light meters, optical fibre detectors and barcode scanners.
Light-Emitting Diode (LED)
An LED is a heavily doped p-n junction operated under forward bias. Injected minority carriers recombine with majority carriers near the junction; the released energy emerges as a photon of wavelength λ ≈ hc/E_g.
The colour of an LED is set by the band gap of the semiconductor:
| Material | E_g (eV) | Wavelength (nm) | Colour |
|---|---|---|---|
| GaAs | 1.43 | ~870 | IR (invisible) |
| GaAs0.6P0.4 | ~1.9 | ~660 | Red |
| GaP | 2.26 | ~550 | Green |
| GaN / InGaN | ~3.4 | ~470 | Blue |
| White LED | — | — | Blue LED + yellow phosphor |
LEDs have several advantages over incandescent bulbs: low operating voltage, low power, long life (~10⁵ h), fast switching, no warm-up time, ruggedness. They have replaced filament bulbs in nearly every general-lighting application.
14.8.3 Solar Cell
A solar cell is a large-area p-n junction that converts sunlight directly into a DC voltage without any external bias. Sunlight (with photon energies above E_g) creates electron-hole pairs in the depletion region; the built-in field separates them — electrons drift to n-side, holes to p-side. This separation makes the n-side the (−) terminal and the p-side the (+) terminal, generating an EMF.
Design considerations:
- The semiconductor must have a band gap matched to the solar spectrum (~1.0-1.8 eV is optimal). Si (1.12 eV) and GaAs (1.43 eV) are common.
- The top junction must be very near the illuminated surface so photons reach the depletion region.
- Anti-reflection coatings reduce surface losses; metal contact grids let light in while collecting current.
Comparison Table — All Four Special Diodes
| Device | Bias | Input | Output | Key role of E_g |
|---|---|---|---|---|
| Zener | Reverse, >V_z | Voltage | Constant V_z | Sets V_z (high-doping ⇒ low V_z) |
| Photodiode | Reverse | Light (hν ≥ E_g) | Reverse current ∝ intensity | Cutoff wavelength λ_c = hc/E_g |
| LED | Forward | Current | Light (λ ≈ hc/E_g) | Sets emission colour |
| Solar cell | Unbiased (illuminated) | Sunlight | EMF + current | Optimal E_g ≈ 1-1.8 eV |
Worked Example — LED wavelength
Indeed the red part of the visible spectrum.
Point a smartphone camera at the front of any TV remote and press a button. Most phone cameras detect near-IR light and you'll see the LED at the front of the remote glow brightly on screen — even though it looks dark to your eye.
Interactive — Zener Voltage Regulator
Watch a regulator clamp the output
Adjust V_in and the load resistance. The simulator shows V_out, current through Zener, and current through load.
Competency-Based Questions
Q1 (MCQ). A Zener diode is used as a voltage regulator. It is operated in:
Q2 (MCQ). For a semiconductor with E_g = 1.55 eV, the longest photon wavelength that creates an e-h pair is approximately:
Q3 (Short Answer). Why is Si (E_g = 1.12 eV) NOT used to make LEDs that emit visible light?
Q4 (Numerical). A photodiode with E_g = 1.43 eV (GaAs) — what is the longest wavelength it can detect?
Q5 (HOTS). Why must the n-region of a solar cell be kept very thin compared to the p-region?
Assertion–Reason Questions
Options: (A) Both true, R correct explanation. (B) Both true, R not the correct explanation. (C) A true, R false. (D) A false, R true.
Assertion: A photodiode is operated in reverse bias.
Reason: Reverse bias widens the depletion region and makes the fractional change in current due to incoming photons more pronounced.
Assertion: White LEDs are usually made by combining a blue LED with a yellow phosphor.
Reason: No single semiconductor band gap can produce all visible wavelengths simultaneously.
Assertion: A solar cell does NOT need an external battery to produce a current through a load.
Reason: The built-in junction field separates photo-generated electron-hole pairs and develops an EMF on its own.
Frequently Asked Questions - Special Purpose Diodes
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Physics — CBSE Class XII Sample Paper 1 (2025-26)
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