આ MCQ મોડ્યુલ આના પર આધારિત છે: Fission Fusion
Fission Fusion
આ મૂલ્યાંકન આના પર આધારિત હશે: Fission Fusion
મૂલ્યાંકન બનાવવામાં તેમની સામગ્રી સામેલ કરવા ચિત્રો, PDF અથવા Word દસ્તાવેજ અપલોડ કરો.
Fission Fusion
13.7 Nuclear Energy — Why Fission and Fusion Both Release Energy
Recall the BE/A curve: the most tightly bound nuclei sit near A ≈ 56 (iron). Lighter nuclei are loosely bound; very heavy nuclei (A > 170) are also less tightly bound because Coulomb repulsion of many protons partly cancels the strong-force attraction. Energy is released whenever loosely-bound nuclei rearrange into more tightly-bound ones.
Two routes to climb up the BE curve:
- Fission: A heavy nucleus (A ~ 235) splits into two intermediate-mass fragments (each A ~ 100–140). Each fragment is more tightly bound — energy is released.
- Fusion: Two light nuclei merge into a heavier one with greater BE per nucleon — energy is released.
13.7.1 Nuclear Fission
Nuclear fission was discovered in 1938 by Otto Hahn and Fritz Strassmann (interpretation by Lise Meitner & Otto Frisch in 1939). When \(^{235}_{92}\mathrm{U}\) absorbs a slow neutron, the resulting \(^{236}\mathrm{U}^{*}\) compound nucleus is so unstable that it splits — typically into two unequal fragments and 2–3 prompt neutrons:
The fragments are radioactive — they sit on the neutron-rich side of the stability valley and undergo successive β-decays until reaching stable nuclei. The Q-value per fission is about 200 MeV, distributed roughly as 165 MeV kinetic energy of fragments + 5 MeV neutron KE + 7 MeV prompt γ-rays + the rest carried away by β/γ from fission products and antineutrinos.
Order-of-magnitude estimate of Q
Take a parent A = 240 nucleus with E_bn ≈ 7.6 MeV splitting into two A = 120 fragments with E_bn ≈ 8.5 MeV.
This rough estimate is in excellent agreement with measurements (~200 MeV).
Chain Reaction and Critical Mass
Each fission releases 2–3 neutrons. If at least one of those neutrons triggers another fission, a self-sustaining chain reaction develops. If on average exactly 1 neutron per fission causes the next fission (the multiplication factor k = 1), the reaction is critical and steady — the basis of a power reactor. If k > 1, fissions multiply exponentially — the basis of a fission bomb. The minimum mass of fissile material that allows k ≥ 1 (given a particular geometry) is the critical mass.
Nuclear Reactor (Schematic)
A nuclear reactor turns this chain reaction into controlled, steady heat. Five essential components:
- Fuel: Usually uranium enriched in ²³⁵U (or ²³⁹Pu). The fissile fuel is shaped into rods.
- Moderator: Water, heavy water (D₂O) or graphite. Slows down fast fission neutrons (≈ 1 MeV) to thermal energies (≈ 0.025 eV) where they are most efficiently absorbed by ²³⁵U.
- Control rods: Boron or cadmium absorb excess neutrons. Pushing them in slows the reaction; pulling them out speeds it up. They keep k = 1.
- Coolant: Water (or liquid metal/gas) carries away the heat.
- Shielding: Thick concrete and steel absorb stray neutrons and γ-rays.
Worked Example 13.7 — Energy from 1 kg of ²³⁹Pu
Number of atoms in 1 kg = (1000 g × N_A) / (239 g/mol) = (1000 × 6.022 × 10²³) / 239 ≈ 2.52 × 10²⁴ atoms.
\[ E_{\text{tot}} = 2.52 \times 10^{24} \times 180\ \text{MeV} = 4.54 \times 10^{26}\ \text{MeV} \]Converting to joules (1 MeV = 1.6 × 10⁻¹³ J):
\[ E_{\text{tot}} = 4.54 \times 10^{26} \times 1.6 \times 10^{-13} \approx 7.26 \times 10^{13}\ \text{J} \]Equivalent to burning roughly 2500 tonnes of coal!
13.7.2 Nuclear Fusion — Energy from the Stars
Nuclear fusion is the inverse process: light nuclei combine into a heavier one whose BE per nucleon is greater. Some examples:
The Coulomb Barrier
For fusion, the two positively charged nuclei must approach within ~1 fm so the strong force can take over. Their mutual Coulomb repulsion erects a potential barrier of typical height ≈ 400 keV (for two protons). To climb this barrier thermally requires temperatures of order
Such high temperatures are why fusion is described as thermonuclear. (The sun's core is "only" 1.5 × 10⁷ K — fusion proceeds there because the high-energy tail of the Maxwell-Boltzmann distribution and quantum tunnelling combine to make protons leak through the barrier.)
Proton-Proton Cycle (energy of the Sun)
In stars like the Sun, hydrogen is "burned" into helium through the p-p cycle:
Steps (i)-(iii) must occur twice for one (iv). Net effect:
Each second, the Sun converts ~6 × 10¹¹ kg of hydrogen into helium, losing ~4 × 10⁹ kg of mass per second to radiation — yet the Sun has enough hydrogen for another ~5 billion years.
Controlled Thermonuclear Fusion
If we can replicate stellar fusion on Earth, we get an essentially unlimited, low-radioactive-waste energy source. The challenge is plasma confinement — heating fuel to 10⁸ K without a container melting. Two main approaches:
- Magnetic confinement (tokamak): toroidal magnetic fields confine the plasma. Examples: ITER (international project), India's ADITYA and SST-1.
- Inertial confinement: high-power lasers (or ion beams) compress and heat a tiny fuel pellet (e.g. NIF, USA).
Worked Example 13.8 — Lamp powered by deuterium fusion
Number of D atoms in 2.0 kg: (2000 × 6.022 × 10²³)/2 = 6.022 × 10²⁶.
Two deuterons fuse per reaction → number of reactions = 6.022 × 10²⁶ / 2 = 3.011 × 10²⁶.
Total energy = 3.011 × 10²⁶ × 3.27 MeV × 1.6 × 10⁻¹³ J/MeV ≈ 1.576 × 10¹⁴ J.
\[ t = \frac{E}{P} = \frac{1.576 \times 10^{14}}{100} = 1.576 \times 10^{12}\ \text{s} \approx \mathbf{5 \times 10^{4}\ \text{years}} \]Worked Example 13.9 — Coulomb barrier height
At touch, separation = 2 × 2.0 fm = 4.0 × 10⁻¹⁵ m.
\[ U = \frac{1}{4\pi\varepsilon_0}\frac{e\cdot e}{r} = \frac{(9 \times 10^{9})(1.6 \times 10^{-19})^2}{4 \times 10^{-15}} \] \[ = \frac{2.304 \times 10^{-28}}{4 \times 10^{-15}} = 5.76 \times 10^{-14}\ \text{J} \]Converting to MeV: U ≈ 5.76 × 10⁻¹⁴ / 1.6 × 10⁻¹³ = 0.36 MeV ≈ 360 keV.
Interactive — Mass-to-Energy Calculator
Q-value calculator
Pick a nuclear reaction; see the mass defect and Q-value released.
Competency-Based Questions
Q1 (MCQ). The energy released per fission of ²³⁵U is approximately:
Q2 (MCQ). Which of the following is NOT a moderator in a thermal reactor?
Q3 (Short Answer). Why does fusion require very high temperatures?
Q4 (Numerical). Estimate the mass converted to energy when ²³⁵U undergoes fission releasing 200 MeV.
Q5 (HOTS). Why is fusion considered cleaner than fission as an energy source?
Assertion–Reason Questions
Options: (A) Both true, R correct explanation. (B) Both true, R not the correct explanation. (C) A true, R false. (D) A false, R true.
Assertion: A nuclear reactor uses moderators like heavy water to slow down neutrons.
Reason: Slow (thermal) neutrons are more efficiently captured by ²³⁵U to cause fission.
Assertion: Energy is released in both fission of ²³⁵U and fusion of deuterium.
Reason: In each case, the products have higher binding energy per nucleon than the reactants.
Assertion: Critical mass of fissile material depends on its geometry and surroundings.
Reason: Neutron leakage is determined by surface-area-to-volume ratio.
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Physics — CBSE Class XII Sample Paper 1 (2025-26)
Section A · Section B · Section C · Section D · Section E