આ MCQ મોડ્યુલ આના પર આધારિત છે: NCERT Exercises and Solutions: Wave Optics
NCERT Exercises and Solutions: Wave Optics
આ મૂલ્યાંકન આના પર આધારિત હશે: NCERT Exercises and Solutions: Wave Optics
મૂલ્યાંકન બનાવવામાં તેમની સામગ્રી સામેલ કરવા ચિત્રો, PDF અથવા Word દસ્તાવેજ અપલોડ કરો.
NCERT Exercises and Solutions: Wave Optics
Chapter 10 Summary — Key Formulae
Huygens principle
- Every point on a wavefront is a source of secondary wavelets; the new wavefront is their forward envelope.
- Laws of reflection and refraction follow from wavefront geometry.
- Frequency is unchanged on refraction; \(\lambda\) and \(v\) change by a factor \(n\).
Coherent superposition
- \(I=I_1+I_2+2\sqrt{I_1I_2}\cos\phi\)
- Equal intensities: \(I=4I_0\cos^2(\phi/2)\)
- \(I_\text{max}=(\sqrt{I_1}+\sqrt{I_2})^2,\;I_\text{min}=(\sqrt{I_1}-\sqrt{I_2})^2\)
Young's double slit
- Path difference \(\Delta x=yd/D\)
- Bright: \(y_n=n\lambda D/d\); Dark: \(y_n=(n+\tfrac12)\lambda D/d\)
- Fringe width \(\beta=\lambda D/d\)
Single-slit diffraction
- Minima: \(a\sin\theta=n\lambda\)
- Central maximum width: \(W=2\lambda D/a\)
- Resolving power (Rayleigh): \(\Delta\theta_\text{min}=1.22\lambda/D\)
Polarisation
- Malus: \(I=I_0\cos^2\theta\)
- Brewster: \(\tan\theta_B=n\), \(\theta_B+\theta_r=90°\)
- Unpolarised → polaroid: intensity halved.
Keywords
NCERT Exercises — Solved
Monochromatic light of wavelength 589 nm from a sodium lamp enters water of refractive index 1.33. Find the wavelength, frequency and speed of (a) the reflected, (b) the refracted light.
(b) Refracted light: frequency unchanged, \(\nu=5.09\times10^{14}\) Hz. \(v=c/n=3\times10^8/1.33=2.26\times10^8\) m/s. \(\lambda_w=\lambda/n=589/1.33=442.9\) nm.
Give the shape of the wavefront for: (a) a point source, (b) light diverging from a convex lens placed after a point source at its focus, (c) a distant star.
(b) Plane wavefronts (lens converts diverging rays from focus into a parallel beam).
(c) Plane wavefronts (star is effectively infinitely distant; tiny patch of a vast sphere looks flat).
(a) The refractive index of glass is 1.5. Compute the speed of light in glass. (b) Is the speed of light the same for all colours travelling from vacuum into glass?
(b) No. Glass is dispersive — \(n\) depends on \(\lambda\). Red light (\(n\approx1.513\)) travels slightly faster than violet (\(n\approx1.532\)), which is why prisms split white light.
In a YDSE the slits are 0.28 mm apart and the screen is 1.4 m away. The third bright fringe is found at 1.2 cm from the central maximum. Find (a) the wavelength of light, (b) the fringe width, (c) the position of the 2nd bright fringe. (NCERT-style: adjusted — here we use \(\lambda=600\) nm directly.)
Fringe width \(\beta=\lambda D/d=(600\times10^{-9})(1.4)/(2.8\times10^{-4})=3\times10^{-3}\) m = 3 mm.
Second bright: \(y_2=2\beta=6\) mm from centre.
Light of \(\lambda=600\) nm is used in YDSE with \(d=1\) mm and \(D=1\) m. Find the angular width of a fringe.
In YDSE the slits produce waves of intensities \(I\) and \(4I\). Compute the ratio \(I_\text{max}:I_\text{min}\).
A diffraction grating has 5000 lines/cm. What is the angle of first-order maximum for \(\lambda=600\) nm?
Light of \(\lambda=500\) nm falls on a 0.1-mm slit; screen 1 m away. Find the width of the central bright maximum.
A slit 0.2 mm wide is illuminated by \(\lambda=600\) nm. At what angle is the 2nd minimum from centre?
In YDSE, if \(I_\text{max}/I_\text{min}=25/9\), find the ratio of slit widths (which is the ratio of amplitudes squared, i.e. intensity ratio).
YDSE: \(\lambda=500\) nm, \(D=1\) m, \(d=0.5\) mm. Find the distance between the 3rd bright fringe and the 5th dark fringe (on the same side).
\(y_3^\text{br}=3\beta=3\) mm. 5th dark: \(y=(4+\tfrac12)\beta=4.5\) mm. Difference = 1.5 mm.
A microscope uses 550 nm light through an aperture of 1 mm. Find the minimum angular separation resolved.
Refractive index of water is 1.33. Find Brewster's angle for light reflecting off a calm lake surface.
Unpolarised light of intensity \(I_0\) is incident on two polaroids whose axes are at 60° to each other. What is the final transmitted intensity?
Light passes through three polaroids whose transmission axes make angles 0°, 30° and 90° with the horizontal. The incident light is unpolarised of intensity \(I_0\). Find the intensity after all three.
After P2 (30° w.r.t. P1): \(I_2=I_1\cos^2 30°=(I_0/2)(3/4)=3I_0/8\).
After P3 (90° w.r.t. P1, i.e. 60° w.r.t. P2): \(I_3=I_2\cos^2 60°=(3I_0/8)(1/4)=\) \(3I_0/32\).
Frequently Asked Questions - NCERT Exercises and Solutions: Wave Optics
What are the key NCERT exercise types in Chapter 10 Wave Optics?
How should students approach numerical problems in Wave Optics?
What are the most-asked CBSE board questions from Chapter 10?
How do I check the dimensional correctness of my answer?
What are common mistakes students make in Chapter 10 exercises?
How does the MyAiSchool solution differ from other NCERT solution sets?
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Physics — CBSE Class XII Sample Paper 1 (2025-26)
Section A · Section B · Section C · Section D · Section E