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Ydse Diffraction Polarisation

🎓 Class 12 Physics CBSE Theory Ch 10 – Wave Optics ⏱ ~14 min
🌐 ભાષા:

આ MCQ મોડ્યુલ આના પર આધારિત છે: Ydse Diffraction Polarisation

આ મૂલ્યાંકન આના પર આધારિત હશે: Ydse Diffraction Polarisation

મૂલ્યાંકન બનાવવામાં તેમની સામગ્રી સામેલ કરવા ચિત્રો, PDF અથવા Word દસ્તાવેજ અપલોડ કરો.

Ydse Diffraction Polarisation

10.5 Young's Double-Slit Experiment (YDSE)

In 1801, Thomas Young did what Newton's corpuscles could not explain: he demonstrated the interference of light. A narrow source S illuminates a single slit (to create coherence), which then lights two close, parallel slits \(S_1\) and \(S_2\). These two slits act as coherent sources, and their waves overlap on a screen placed a distance \(D\) away, producing alternating bright and dark bands called fringes.

S single slit S₁ S₂ double slit (sep d) P (y) O (centre) distance D screen
Fig 10.4: Young's double-slit setup. Distance \(D\) = slit-to-screen; \(d\) = slit separation; \(y\) = fringe position.

Path Difference and Fringe Width

For a point \(P\) at height \(y\) on the screen (with \(d,y\ll D\)), the path difference between the two rays is approximately:

\[\Delta x=S_2P-S_1P\approx\frac{y\,d}{D}\]

Bright fringes (maxima) occur where \(\Delta x=n\lambda\):

\[y_n^\text{br}=\frac{n\lambda D}{d},\qquad n=0,\pm1,\pm2,\dots\]

Dark fringes (minima) occur where \(\Delta x=(n+\tfrac12)\lambda\):

\[y_n^\text{dk}=\left(n+\tfrac12\right)\frac{\lambda D}{d}\]

The spacing between consecutive bright (or dark) fringes — the fringe width — is a hallmark result:

\[\boxed{\;\beta=\frac{\lambda D}{d}\;}\]

The intensity variation across the screen is

\[I=4I_0\cos^2\!\left(\frac{\pi y d}{\lambda D}\right)\]

so fringes are equally spaced and have equal brightness (ideal case).

How changes affect the pattern: Larger \(\lambda\) or \(D\), or smaller \(d\), widens the fringes. Replacing air by water (index \(n\)) shrinks \(\lambda\) and hence \(\beta\) by a factor \(n\).

10.6 Diffraction

Diffraction is the bending of waves around obstacles or through apertures comparable in size to the wavelength. It is another direct proof of the wave nature of light.

Single-Slit Diffraction

When monochromatic light of wavelength \(\lambda\) passes through a slit of width \(a\), Huygens' wavelets from every point of the slit interfere. The screen shows a wide central maximum flanked by much weaker secondary maxima.

  • Minima: \(a\sin\theta=n\lambda\), \(n=\pm1,\pm2,\dots\)
  • Secondary maxima: \(a\sin\theta\approx\left(n+\tfrac12\right)\lambda\)
  • Central maximum width (between first minima on either side) on a screen distance \(D\) away: \(\;W=\dfrac{2\lambda D}{a}\).
central max 2°max 2°max −λ/a +λ/a −2λ/a +2λ/a sin θ
Fig 10.5: Single-slit diffraction pattern — a broad, bright central maximum plus much weaker secondary maxima.

YDSE vs Single-Slit Diffraction

FeatureYDSE (interference)Single slit (diffraction)
Fringe spacingEqual (\(\beta=\lambda D/d\))Central max twice as wide as side fringes
IntensitiesAll bright fringes ~equalCentral max dominates; side max much weaker
Condition for minima\((n+\tfrac12)\lambda\)\(a\sin\theta=n\lambda\)
Number of fringesMany observableOnly a few side bands visible

Resolving Power — Rayleigh's Criterion

Two point sources are just resolved by a circular aperture of diameter \(D\) when their angular separation equals

\[\Delta\theta_\text{min}=\frac{1.22\lambda}{D}\]

Larger apertures (telescopes, microscopes) and shorter wavelengths give finer resolution.

10.7 Polarisation

Light is a transverse EM wave — the electric field \(\vec E\) vibrates perpendicular to the direction of propagation. Ordinary sunlight is unpolarised: \(\vec E\) rapidly and randomly changes direction in the plane perpendicular to the ray.

In polarised light, \(\vec E\) vibrates in only one fixed plane.

unpolarised polaroid polarised I = I₀/2
Fig 10.6: A polaroid transmits only the component of \(\vec E\) along its transmission axis — unpolarised intensity is halved.

Malus's Law

If already polarised light of intensity \(I_0\) falls on a polariser whose axis makes an angle \(\theta\) with the light's polarisation, the transmitted intensity is:

\[\boxed{\;I=I_0\cos^2\theta\;}\]

Polarisation by Reflection — Brewster's Law

When unpolarised light falls on glass at a special angle \(\theta_B\), the reflected ray is completely polarised (perpendicular to the plane of incidence). The condition is that the reflected and refracted rays are perpendicular to each other, giving:

\[\tan\theta_B=n,\qquad \theta_B+\theta_r=90°\]
glass (n) θ_B θ_B θ_r reflected (polarised) incident refracted
Fig 10.7: At Brewster's angle, reflected + refracted = 90°, and the reflected ray is 100% polarised.

Applications of polarisation: polaroid sunglasses cut horizontal glare from roads and water; LCDs use polarising layers to switch pixels; 3-D cinema glasses use perpendicular polarisations per eye; photographers use polarising filters to deepen sky colour; engineers use "photo-elastic" polarisation to map stress in transparent models.

Activity 10.2 — Two polaroids at right angles

Hold one polaroid sheet in front of a lamp and rotate it — brightness is roughly constant.

Predict: Now bring a second polaroid behind the first and rotate it by 90°. What happens to the transmitted light?
The field drops to near-zero. By Malus's law, \(I=(I_0/2)\cos^2(90°)=0\). The first polaroid produces polarised light; the second blocks the component perpendicular to its own axis — proving light is a transverse wave.

Interactive — YDSE Fringe Calculator

Enter wavelength, screen distance and slit separation. The output gives the fringe width \(\beta=\lambda D/d\) and paints the resulting pattern.

β will appear here…

Worked Examples

Example 1 — YDSE fringe width

In YDSE, \(\lambda=600\) nm, \(D=1.2\) m, \(d=0.4\) mm. Find \(\beta\) and the position of the 3rd bright fringe.

\(\beta=\lambda D/d=(600\times10^{-9})(1.2)/(0.4\times10^{-3})=1.8\times10^{-3}\) m = 1.8 mm. Third bright: \(y_3=3\beta=5.4\) mm from centre.
Example 2 — Position of dark fringe

Same setup as Ex 1. Where is the 2nd dark fringe (\(n=1\) in \((n+\tfrac12)\))?

\(y=(1+\tfrac12)\beta=1.5\times1.8=2.7\) mm.
Example 3 — YDSE immersed in water

The apparatus of Ex 1 is submerged in water of index 1.33. What is the new fringe width?

Wavelength in water \(\lambda'=\lambda/n=600/1.33\approx451\) nm. \(\beta'=\lambda'D/d=\beta/n=1.8/1.33\approx\) 1.35 mm.
Example 4 — Central max of single slit

Light of 500 nm passes through a slit of width 0.1 mm; screen is 1 m away. Find the angular width of the central maximum and its linear width.

Angular half-width \(\theta=\lambda/a=500\times10^{-9}/10^{-4}=5\times10^{-3}\) rad. Full angular width \(2\theta=10^{-2}\) rad. Linear width \(W=2\lambda D/a=2\times5\times10^{-3}\times1=\) 10 mm.
Example 5 — Brewster's angle for glass

Refractive index of crown glass = 1.52. Compute Brewster's angle and the angle of refraction.

\(\tan\theta_B=1.52\Rightarrow\theta_B=\tan^{-1}(1.52)\approx56.66°\). Refraction \(\theta_r=90°-\theta_B\approx33.34°\).
Example 6 — Malus's law

Polarised light of intensity 80 W/m² is incident on a polariser whose axis makes 30° with the E-vector. Find the transmitted intensity.

\(I=I_0\cos^2(30°)=80\times(3/4)=\) 60 W/m².
Example 7 — Rayleigh limit

A telescope has aperture 20 cm. Minimum angular separation for 550 nm light?

\(\Delta\theta=1.22\lambda/D=1.22(550\times10^{-9})/0.2=3.36\times10^{-6}\) rad ≈ 0.69 arc-sec.

Competency-Based Questions

Q1. In YDSE, if the slit separation is doubled while \(\lambda\) and \(D\) stay the same, the fringe width:

  • (a) doubles
  • (b) halves
  • (c) unchanged
  • (d) quadruples
(b) \(\beta\propto1/d\), so it halves.

Q2. In single-slit diffraction, the first minimum occurs when:

  • (a) \(a\sin\theta=\lambda/2\)
  • (b) \(a\sin\theta=\lambda\)
  • (c) \(a\sin\theta=2\lambda\)
  • (d) \(a\sin\theta=3\lambda/2\)
(b).

Q3. (Short answer) Why does replacing a YDSE apparatus in water reduce the fringe width?

Wavelength becomes \(\lambda/n\) in water. Since \(\beta=\lambda D/d\), \(\beta\) shrinks by the same factor \(n\).

Q4. (Long answer) State Brewster's law and explain why the reflected light at Brewster's angle is completely polarised.

\(\tan\theta_B=n\). At this angle reflected and refracted rays are perpendicular; the component of \(\vec E\) in the plane of incidence cannot be reflected (its oscillating dipoles would have to radiate along their own axis, which is forbidden). Only the perpendicular component reflects.

Q5. (HOT) Two polaroids are crossed (90° apart). A third is inserted between them at 45°. Find the transmitted intensity if unpolarised light of intensity \(I_0\) falls on the first.

After first: \(I_0/2\). After middle (at 45°): \((I_0/2)\cos^2 45°=I_0/4\). After last (at 45° to middle): \((I_0/4)\cos^2 45°=I_0/8\).

Assertion–Reason Questions

Options: (A) Both true, R correct explanation. (B) Both true, R not correct explanation. (C) A true, R false. (D) A false, R true.

Assertion: In YDSE, the central fringe is bright for all wavelengths.

Reason: At the central point both paths are equal, giving zero path difference for every colour.

(A) Both true and the reason is the correct explanation.

Assertion: Sound waves can be polarised but light cannot.

Reason: Light waves are transverse while sound waves are longitudinal.

(D) Assertion is false (light can be polarised, sound cannot) but reason is true.

Assertion: The resolving power of a microscope increases with shorter wavelength.

Reason: The minimum resolvable angle follows \(\Delta\theta\propto\lambda/D\).

(A) Both correct; shorter \(\lambda\) means smaller \(\Delta\theta\) hence better resolution.

Frequently Asked Questions - Ydse Diffraction Polarisation

What is the main concept covered in Ydse Diffraction Polarisation?
In NCERT Class 12 Physics Chapter 10 (Wave Optics), "Ydse Diffraction Polarisation" covers the core principles and equations students need for board exam success. The MyAiSchool lesson explains the topic with definitions, derivations, worked examples, and interactive simulations. Key formulas and dimensional analysis are included to build conceptual depth and problem-solving skills aligned with the CBSE 2025-26 syllabus.
How is Ydse Diffraction Polarisation useful in real-life applications?
Real-life applications of "Ydse Diffraction Polarisation" from NCERT Class 12 Physics Chapter 10 include electronics, communication systems, medical imaging, solar energy, semiconductor devices, and modern technology. The MyAiSchool lesson links every concept to a tangible example so students see physics as a problem-solving framework for the physical world, not as abstract formulas.
What are the key formulas in Ydse Diffraction Polarisation?
Key formulas in "Ydse Diffraction Polarisation" (NCERT Class 12 Physics Chapter 10 Wave Optics) are derived step-by-step in the MyAiSchool lesson. Students should memorize the final formula AND understand its derivation for full board marks. Each formula is listed with its dimensional formula, SI unit, applicability range, and common pitfalls. The Summary section at the end of each part includes a quick-reference formula card.
How does this part connect to other parts of Chapter 10?
NCERT Class 12 Physics Chapter 10 (Wave Optics) is structured so each part builds on the previous one. "Ydse Diffraction Polarisation" connects directly to neighbouring parts via shared definitions, units, and methodology. The MyAiSchool lesson cross-references related concepts with internal links so students can navigate the whole chapter as one connected story rather than disconnected fragments.
What types of CBSE board questions come from Ydse Diffraction Polarisation?
CBSE board questions from "Ydse Diffraction Polarisation" typically include: (1) 1-mark MCQs on definitions and formulas, (2) 2-mark short-answer derivations or applications, (3) 3-mark numerical problems with units, (4) 5-mark long-answer derivations followed by application. The MyAiSchool lesson tags each Competency-Based Question (CBQ) with Bloom level (L1-L6) so students know how to study for each weight.
How can students use the interactive simulation effectively?
The interactive simulation in the "Ydse Diffraction Polarisation" lesson allows students to adjust input parameters (sliders or selectors) and see physical quantities update in real time. To use it effectively: (1) try extreme values to understand limiting cases, (2) compare with the analytical formula, (3) check unit consistency, (4) test special configurations from worked examples. The simulation reinforces conceptual intuition that pure formula manipulation cannot.
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Physics Class 12 Part II – NCERT (2025-26)
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