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Refraction Total Internal

🎓 Class 12 Physics CBSE Theory Ch 9 – Ray Optics and Optical Instruments ⏱ ~14 min
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આ MCQ મોડ્યુલ આના પર આધારિત છે: Refraction Total Internal

આ મૂલ્યાંકન આના પર આધારિત હશે: Refraction Total Internal

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Refraction Total Internal

9.3 Refraction of Light

When a ray of light travels from one transparent medium into another, its speed changes and, unless it strikes the boundary at 90°, its direction also changes. This bending of light on crossing a boundary is called refraction.

Snell's Law of Refraction: \[n_1 \sin\theta_1 = n_2 \sin\theta_2\] where \(\theta_1\) is the angle of incidence (in medium 1), \(\theta_2\) the angle of refraction (in medium 2), and \(n_1,n_2\) are the respective refractive indices measured from the normal.

The absolute refractive index of a medium is

\[n = \frac{c}{v}\]

where \(c = 3\times 10^8\) m/s is the speed of light in vacuum and \(v\) its speed in the medium. Since \(v < c\) always, \(n > 1\). The relative refractive index of medium 2 with respect to medium 1 is

\[n_{21}=\frac{n_2}{n_1}=\frac{v_1}{v_2}=\frac{\sin\theta_1}{\sin\theta_2}\]
  • When light passes from a rarer to a denser medium (air → glass), it bends towards the normal — \(\theta_2<\theta_1\).
  • When it goes from denser to rarer (glass → air), it bends away from the normal — \(\theta_2>\theta_1\).
Normal incident ray θ₁ refracted ray θ₂ Rarer (air, n₁) Denser (glass, n₂)
Fig 9.4: Refraction from a rarer medium into a denser one: the ray bends towards the normal (\(\theta_2 < \theta_1\)).

Apparent Depth

An object submerged in water appears to lie closer to the surface than it really is. If the object is at real depth \(h\) in a medium of refractive index \(n_2\) and the observer looks from medium of index \(n_1\),

\[h' = h\,\frac{n_1}{n_2}\]

For a coin at the bottom of a swimming pool 2 m deep (\(n_{\text{water}}=1.33\)), the apparent depth is only \(2/1.33 \approx 1.5\) m. A straw dipped in a glass of water looks bent at the water-air interface for the same reason.

O (real) O' (apparent) Air (n=1) Water (n=1.33) h
Fig 9.5: A submerged object O appears raised to O′ at \(h' = h \cdot n_1/n_2\).

9.4 Total Internal Reflection (TIR)

When light travels from a denser to a rarer medium, the refracted ray bends away from the normal. As the angle of incidence is increased, the refracted angle approaches 90°. At a particular angle of incidence — the critical angle \(\theta_c\) — the refracted ray just grazes the boundary. Beyond that, no refraction is possible: all of the light is reflected back into the denser medium.

Critical angle: \(\sin\theta_c = \dfrac{n_2}{n_1}\) (light going from medium 1, denser, to medium 2, rarer).
(a) θ<θc: refracts (b) θ=θc: grazes (c) θ>θc: TIR Rarer Denser
Fig 9.6: As the angle of incidence increases beyond the critical angle, refraction is replaced by total internal reflection.

Everyday Applications of TIR

  1. Mirage on a hot road: a layer of hot (hence less dense, lower-n) air sits over cooler air above. Light from the sky grazing downward into the hotter layer undergoes TIR, so the driver sees an inverted image of the sky that looks like a patch of water.
  2. Brilliance of a diamond: diamond has \(n=2.42\), giving a small critical angle \(\theta_c \approx 24.4°\). Rays that enter through the faceted top are trapped by multiple total internal reflections and emerge only through the top facets, producing the "fire" of the stone.
  3. Totally reflecting prisms in binoculars, periscopes and SLR cameras: right-angle glass prisms use TIR at 45° (greater than the glass critical angle of about 42°) — far more efficient than a silvered mirror.
  4. Optical fibres: a thin glass core of high \(n\) is surrounded by cladding of slightly lower \(n\). Light entering at a small angle bounces by repeated TIR along the length of the fibre with negligible loss — the backbone of modern telecommunications, endoscopy and fibre-optic sensors.
Cladding (lower n) Core (higher n)
Fig 9.7: An optical fibre traps light inside the high-index core by repeated total internal reflection.

9.5 Refraction at Spherical Surfaces and Lenses

For a single spherical refracting surface of radius \(R\) separating media of refractive indices \(n_1\) (object side) and \(n_2\) (image side), the Cartesian-sign-convention formula is

\[\frac{n_2}{v} - \frac{n_1}{u} = \frac{n_2 - n_1}{R}\]

Lens Maker's Formula

A thin lens is two refracting spherical surfaces back-to-back. Applying the surface formula twice and combining:

\[\frac{1}{f} = (n-1)\left(\frac{1}{R_1} - \frac{1}{R_2}\right)\]

where \(n\) is the refractive index of the lens material relative to the surrounding medium, and \(R_1,R_2\) are the radii of the two surfaces (with sign).

Thin-Lens Formula and Magnification

\[\frac{1}{v} - \frac{1}{u} = \frac{1}{f} \qquad\text{and}\qquad m = \frac{v}{u} = \frac{h'}{h}\]

Note the sign pattern: unlike the mirror formula which has "\(+\)" between the two reciprocals, the lens formula has "\(-\)".

Combination of Thin Lenses in Contact

When two thin lenses of focal lengths \(f_1\) and \(f_2\) are placed in contact, the system behaves like a single lens of focal length \(f\) given by

\[\frac{1}{f} = \frac{1}{f_1} + \frac{1}{f_2}\]

Power of a Lens

The power \(P\) of a lens is the reciprocal of its focal length in metres:

\[P = \frac{1}{f\,(\text{m})}\qquad \text{unit: dioptre (D)}\]

For lenses in contact, powers add: \(P = P_1 + P_2\). A converging lens has \(P > 0\); a diverging lens has \(P < 0\).

Convex vs Concave Lens

FeatureConvex (converging)Concave (diverging)
Focal length signPositiveNegative
Power+ve (D)–ve (D)
Parallel raysConverge to real focusAppear to diverge from virtual focus
Image for real objectVaries with position (like concave mirror)Always virtual, erect, diminished
Convex lens F Concave lens F (virtual)
Fig 9.8: A convex lens brings parallel rays to a real focus; a concave lens makes them diverge as if from a virtual focus on the incident side.

Six Cases of Image Formation by a Convex Lens

Object PositionImage PositionNatureSize
At infinityAt FReal, invertedPoint
Beyond 2FBetween F and 2FReal, invertedDiminished
At 2FAt 2FReal, invertedSame size
Between 2F and FBeyond 2FReal, invertedMagnified
At FAt infinityReal, invertedHighly magnified
Between F and O (lens)Same side as objectVirtual, erectMagnified (magnifying glass)

Worked Examples — Refraction and Lenses

Example 1: Apparent depth of a coin

A coin lies at the bottom of a tank of water 1.5 m deep (\(n=4/3\)). What is its apparent depth as seen from above?

\(h' = h\,(n_1/n_2) = 1.5\times(1/(4/3)) = 1.5\times 0.75 = \boxed{1.125\ \text{m}}\).

Example 2: Critical angle for water

Find the critical angle for water (\(n_1=1.33\)) with respect to air (\(n_2=1\)).

\(\sin\theta_c = n_2/n_1 = 1/1.33 = 0.7519\). \(\theta_c = \sin^{-1}(0.7519) \approx \boxed{48.8°}\).

Example 3: Lens maker's formula

A double-convex lens of glass (\(n=1.5\)) has both surfaces of radius 20 cm. Find its focal length.

\(R_1=+20, R_2=-20\) cm. \(\dfrac{1}{f} = (1.5-1)\left(\dfrac{1}{20}-\dfrac{1}{-20}\right)=0.5\times\dfrac{2}{20}=\dfrac{1}{20}\). \(\boxed{f = +20\ \text{cm}}\).

Example 4: Image by a convex lens

An object is placed 30 cm from a convex lens of focal length 20 cm. Find the image position, magnification and nature.

\(u=-30, f=+20\) cm. \(\frac{1}{v}=\frac{1}{f}+\frac{1}{u}=\frac{1}{20}-\frac{1}{30}=\frac{1}{60}\). \(v=+60\) cm. \(m=v/u=60/(-30)=-2\). Real, inverted, magnified twofold.

Example 5: Combined power

A convex lens of focal length 25 cm is placed in contact with a concave lens of focal length 50 cm. Find the equivalent power and focal length.

\(P_1 = 1/0.25 = +4\) D, \(P_2 = 1/(-0.50) = -2\) D. \(P = P_1+P_2 = \boxed{+2\ \text{D}}\). \(f = 1/P = +0.50\) m \(= +50\) cm — net converging.

Example 6: Refraction at a single spherical surface

A point object in air (\(n_1=1\)) lies on the axis of a glass sphere (\(n_2=1.5\)), 15 cm from a convex surface of radius 10 cm. Find the image distance.

\(u=-15, R=+10\). \(\frac{1.5}{v}-\frac{1}{-15} = \frac{1.5-1}{10}\). \(\frac{1.5}{v} = 0.05 - 0.0667 = -0.01667\). \(v = -90\) cm. Image is virtual, on the same side as the object.

Example 7: Magnifying glass

A convex lens of focal length 10 cm is used as a magnifier. Where should a stamp be placed to form a virtual image at 25 cm from the lens?

\(v = -25\) cm, \(f = +10\) cm. \(\frac{1}{u} = \frac{1}{v}-\frac{1}{f}=\frac{1}{-25}-\frac{1}{10}=-\frac{7}{50}\). \(u = -7.14\) cm. So the stamp is placed about 7.14 cm in front of the lens, inside the focal length.

Example 8: Speed in glass and refraction angle

Light enters glass (\(n=1.5\)) from air at 60°. Find the angle of refraction and speed in the glass.

\(\sin\theta_2 = \sin 60°/1.5 = 0.866/1.5 = 0.577\). \(\theta_2 = 35.26°\). \(v = c/n = 3\times 10^8/1.5 = \boxed{2\times 10^8\ \text{m/s}}\).
Activity — The Disappearing CoinL3 Apply
Predict: What will happen to a coin at the bottom of an opaque cup when you slowly fill the cup with water — even if your eye does not move?
  1. Place a coin at the bottom of an opaque cup.
  2. Step back until the rim of the cup just hides the coin from view.
  3. Keep your eye fixed. Ask a friend to pour water slowly into the cup.
  4. Notice when the coin appears to rise into view.
Explanation: Light from the coin, refracting as it exits the water at the surface, bends away from the normal. This effectively lifts the image of the coin to an "apparent depth" \(h/n\) closer to the surface, bringing it above the line-of-sight blocked by the rim.

Interactive: Lens Ray Diagram Calculator L3 Apply

Choose lens type (convex/concave), enter magnitude of focal length (cm) and object distance (cm).

Competency-Based Questions

Endoscopes used for medical imaging and telecom cables both rely on bundles of very fine optical fibres. A single silica fibre has a core index 1.50 and a cladding index 1.48.

Q1. L3 Apply Calculate the critical angle at the core–cladding interface. (3 marks)

\(\sin\theta_c = 1.48/1.50 = 0.9867\). \(\theta_c \approx 80.6°\). Rays striking the boundary at any angle greater than 80.6° (measured from normal) undergo TIR.

Q2. L1 Remember Refractive index of a medium is defined as:

  • A. \(v/c\)
  • B. \(c/v\)
  • C. \(v\cdot c\)
  • D. \(c-v\)
Answer: B. \(n=c/v\) — higher \(n\) means slower light.

Q3. L2 Understand Why does a diamond sparkle more than glass? (2 marks)

Diamond has a very high refractive index (2.42), so its critical angle is small (~24°). Most light entering the top is trapped by repeated TIR from facets, eventually emerging from the top with high concentration — the "brilliance" of diamond.

Q4. L3 Apply Two thin lenses of powers +3 D and –1 D are in contact. Find the equivalent focal length. (2 marks)

\(P = 2\) D, \(f = 0.5\) m \(= 50\) cm.

Q5. L4 Analyse A concave lens of focal length 15 cm forms an image at 10 cm in front of the lens. Find the object distance. (3 marks)

\(v=-10, f=-15\). \(\frac{1}{u}=\frac{1}{v}-\frac{1}{f}=-\frac{1}{10}+\frac{1}{15}=-\frac{1}{30}\). \(u = -30\) cm.

Assertion-Reason Questions

Assertion (A): A fish under water sees the outside world within a cone of half-angle equal to the critical angle.

Reason (R): Light rays entering water from all directions are squeezed into the cone by refraction.

  • A. Both true; R is correct explanation.
  • B. Both true; R not correct explanation.
  • C. A true, R false.
  • D. A false, R true.
Answer: A. Reversibility plus the critical-angle condition imply a 97°-wide "Snell's window".

Assertion (A): A concave lens always produces a virtual image of a real object.

Reason (R): A concave lens diverges incident rays.

  • A. Both true; R is correct explanation.
  • B. Both true; R not correct explanation.
  • C. A true, R false.
  • D. A false, R true.
Answer: A. Diverging rays never converge on the other side, so only their extensions meet — forming a virtual image.

Assertion (A): The focal length of a convex lens increases when it is immersed in water.

Reason (R): The relative refractive index between glass and water is smaller than between glass and air.

  • A. Both true; R is correct explanation.
  • B. Both true; R not correct explanation.
  • C. A true, R false.
  • D. A false, R true.
Answer: A. From the lens-maker's formula, smaller \((n-1)\) ⇒ larger \(f\).

Frequently Asked Questions - Refraction Total Internal

What is the main concept covered in Refraction Total Internal?
In NCERT Class 12 Physics Chapter 9 (Ray Optics and Optical Instruments), "Refraction Total Internal" covers the core principles and equations students need for board exam success. The MyAiSchool lesson explains the topic with definitions, derivations, worked examples, and interactive simulations. Key formulas and dimensional analysis are included to build conceptual depth and problem-solving skills aligned with the CBSE 2025-26 syllabus.
How is Refraction Total Internal useful in real-life applications?
Real-life applications of "Refraction Total Internal" from NCERT Class 12 Physics Chapter 9 include electronics, communication systems, medical imaging, solar energy, semiconductor devices, and modern technology. The MyAiSchool lesson links every concept to a tangible example so students see physics as a problem-solving framework for the physical world, not as abstract formulas.
What are the key formulas in Refraction Total Internal?
Key formulas in "Refraction Total Internal" (NCERT Class 12 Physics Chapter 9 Ray Optics and Optical Instruments) are derived step-by-step in the MyAiSchool lesson. Students should memorize the final formula AND understand its derivation for full board marks. Each formula is listed with its dimensional formula, SI unit, applicability range, and common pitfalls. The Summary section at the end of each part includes a quick-reference formula card.
How does this part connect to other parts of Chapter 9?
NCERT Class 12 Physics Chapter 9 (Ray Optics and Optical Instruments) is structured so each part builds on the previous one. "Refraction Total Internal" connects directly to neighbouring parts via shared definitions, units, and methodology. The MyAiSchool lesson cross-references related concepts with internal links so students can navigate the whole chapter as one connected story rather than disconnected fragments.
What types of CBSE board questions come from Refraction Total Internal?
CBSE board questions from "Refraction Total Internal" typically include: (1) 1-mark MCQs on definitions and formulas, (2) 2-mark short-answer derivations or applications, (3) 3-mark numerical problems with units, (4) 5-mark long-answer derivations followed by application. The MyAiSchool lesson tags each Competency-Based Question (CBQ) with Bloom level (L1-L6) so students know how to study for each weight.
How can students use the interactive simulation effectively?
The interactive simulation in the "Refraction Total Internal" lesson allows students to adjust input parameters (sliders or selectors) and see physical quantities update in real time. To use it effectively: (1) try extreme values to understand limiting cases, (2) compare with the analytical formula, (3) check unit consistency, (4) test special configurations from worked examples. The simulation reinforces conceptual intuition that pure formula manipulation cannot.
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