This MCQ module is based on: Position Electronic Config
Position Electronic Config
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Position Electronic Config
Introduction: The Metals That Built Civilisation
Iron, copper, silver and gold — four metals that shaped human history — share something invisible to the eye: each carries a partly filled set of d-orbitals. Throw in titanium for jet engines, vanadium for catalysts, chromium for steel, and you have the d-block elements. Add the radioactive uranium and thorium that power reactors, and you reach the f-block.
This chapter unlocks why a single block in the periodic table — Groups 3 to 12 — produces metals so versatile they appear in every cell of your body (Fe in haemoglobin), in every electronic device (Cu wiring), and in every modern catalyst.
8.1 Position in the Periodic Table
The d-block sits in the wide central section of the periodic table — flanked on the left by the s-block and on the right by the p-block. Within these elements, it is the d-orbitals of the penultimate (n-1) energy level that progressively fill, giving four horizontal series:
- 3d series — Sc to Zn (Z = 21 to 30) in Period 4.
- 4d series — Y to Cd (Z = 39 to 48) in Period 5.
- 5d series — La and Hf to Hg (Z = 57, 72 to 80) in Period 6.
- 6d series — Ac and Rf to Cn (Z = 89, 104 to 112) in Period 7.
The two inner-transition (lanthanoid 4f and actinoid 5f) series sit in a separate panel below the main table.
Q. On what ground can you say that scandium (Z = 21) is a transition element but zinc (Z = 30) is not?
Step 1: Write the ground-state configurations.
Step 2: Sc atom has an incomplete 3d shell (d¹) — it qualifies. Zn atom and Zn²⁺ both carry a complete 3d¹⁰ — it does not qualify, even though it sits in the d-block column.
8.2 Electronic Configurations of the d-Block
The general outer configuration of a d-block element is
The (n-1) tells us electrons enter the inner d-orbitals of the second-from-last shell, while one or two electrons sit in the outer ns. Because the energy difference between (n-1)d and ns is very small, the simple Aufbau prediction sometimes fails — and we get exceptions driven by the extra stability of half-filled (d⁵) and fully filled (d¹⁰) sub-shells.
8.2.1 The Cr and Cu Anomalies
Naively, Cr (Z = 24) should be 3d⁴4s² and Cu (Z = 29) should be 3d⁹4s². Instead, both promote one 4s electron into 3d, giving:
The added exchange energy from a half-filled or fully filled d-shell more than pays for the small extra cost of unpairing the 4s electrons.
8.2.2 Outer Configurations Across All Four Series
| Series | Element & Z — outer configuration |
|---|---|
| 3d (Period 4) | Sc(21)3d¹4s² · Ti(22)3d²4s² · V(23)3d³4s² · Cr(24)3d⁵4s¹ · Mn(25)3d⁵4s² · Fe(26)3d⁶4s² · Co(27)3d⁷4s² · Ni(28)3d⁸4s² · Cu(29)3d¹⁰4s¹ · Zn(30)3d¹⁰4s² |
| 4d (Period 5) | Y(39)4d¹5s² · Zr(40)4d²5s² · Nb(41)4d⁴5s¹ · Mo(42)4d⁵5s¹ · Tc(43)4d⁶5s¹ · Ru(44)4d⁷5s¹ · Rh(45)4d⁸5s¹ · Pd(46)4d¹⁰5s⁰ · Ag(47)4d¹⁰5s¹ · Cd(48)4d¹⁰5s² |
| 5d (Period 6) | La(57)5d¹6s² · Hf(72)5d²6s² · Ta(73)5d³6s² · W(74)5d⁴6s² · Re(75)5d⁵6s² · Os(76)5d⁶6s² · Ir(77)5d⁷6s² · Pt(78)5d⁹6s¹ · Au(79)5d¹⁰6s¹ · Hg(80)5d¹⁰6s² |
| 6d (Period 7) | Ac(89)6d¹7s² · Rf(104)6d²7s² · Db(105)6d³7s² · Sg(106)6d⁴7s² · Bh(107)6d⁵7s² · Hs(108)6d⁶7s² · Mt(109)6d⁷7s² · Ds(110)6d⁸7s² · Rg(111)6d¹⁰7s¹ · Cn(112)6d¹⁰7s² |
Notice the unique Pd exception: it skips its 5s entirely (4d¹⁰ 5s⁰) — a consequence of two paired-up exchange contributions plus relativistic effects.
Interactive: d-Block Configuration Builder L3 Apply L4 Analyse
Pick any 3d-series element and see (i) its outer configuration, (ii) the number of unpaired electrons, (iii) the spin-only magnetic moment, and (iv) whether it follows or breaks Aufbau.
8.3 General Properties of the Transition (d-Block) Elements
Almost every transition metal is hard, lustrous, ductile, malleable, with high tensile strength and excellent thermal/electrical conductivity. The exceptions you must remember are the soft, low-melting Zn, Cd, Hg (no unpaired d-electrons available for metallic bonding) and the unusual Mn (complex bcc structure).
8.3.1 Lattice Structures
| Series | Sc | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn |
|---|---|---|---|---|---|---|---|---|---|---|
| 3d | hcp | hcp | bcc | bcc | X | bcc | ccp | ccp | ccp | X |
bcc = body-centred cubic · hcp = hexagonal close-packed · ccp = cubic close-packed · X = atypical metal lattice.
8.3.2 High Melting Points and Enthalpy of Atomisation
Transition metals melt at very high temperatures because both the (n-1)d and ns electrons participate in metallic bonding. In each row the melting point peaks roughly at d⁵ (one electron per d-orbital, all spins parallel) — the textbook example is W (3683 K, the highest of any metal). Mn and Tc dip anomalously, and the curve falls again towards Zn/Cd/Hg.
8.4 Why Are They Called "Transition" Elements?
The historical name comes from their position: they bridge the highly electropositive s-block and the largely non-metallic p-block. Chemically, they are "transitional" in two senses — they share metallic character with the s-block but display the variable oxidation states and complex-forming tendency that some p-block elements show only weakly.
The presence of partly filled d-orbitals gives the d-block elements five hallmark features that we will explore in Part 2:
- Variable oxidation states (e.g. Mn from +2 to +7).
- Coloured ions (d-d transitions).
- Paramagnetism (unpaired d-electrons).
- Complex-ion formation (vacant d-orbitals + small size).
- Catalytic activity (multiple oxidation states + adsorption sites).
Aim: Use the exchange-energy idea to predict why Cr is 3d⁵4s¹ and not 3d⁴4s².
Procedure:
- Draw the five 3d boxes and the 4s box for the configuration 3d⁴4s². Assume Hund's rule (all four d-electrons spin-up). Count the number of pairs of parallel-spin electrons in the 3d set.
- Now draw the alternative 3d⁵4s¹. Again count parallel-spin pairs (3d set + 4s set together if they happen to be parallel).
- The configuration with the larger number of parallel pairs has the larger exchange energy and wins.
Predict: Which configuration should have more parallel-spin pairs and therefore be more stable?
3d⁴4s²: Parallel pairs in 3d = C(4,2) = 6 pairs.
3d⁵4s¹: Parallel pairs in 3d = C(5,2) = 10 pairs. If the 4s¹ electron also has parallel spin to the 3d set, add 5 more cross-set pairs (these contribute, though weighted differently).
Conclusion: 3d⁵4s¹ wins by at least 4 extra parallel-spin pairs — a substantial exchange-energy gain that more than offsets the small promotion energy 4s → 3d. The same accounting predicts 3d¹⁰4s¹ over 3d⁹4s² for Cu.
Q. Why do the transition elements exhibit higher enthalpies of atomisation than s-block neighbours?
Transition metals carry a large number of unpaired electrons in their 3d/4s (and equivalent) orbitals. These unpaired electrons form strong, multi-electron metallic bonds in the lattice, requiring large amounts of energy to break — hence high ΔₐH.
Q. Write the expected and observed ground-state configurations of the Cu atom and identify the source of stabilisation.
Expected (Aufbau): [Ar] 3d⁹ 4s². Observed: [Ar] 3d¹⁰ 4s¹.
Promoting one 4s electron to fill the last 3d vacancy converts a 3d⁹ shell into a fully-filled 3d¹⁰ shell. The exchange energy stabilisation of d¹⁰ outweighs the small 4s → 3d promotion cost, so the d¹⁰s¹ form is the ground state.
Competency-Based Questions L3 L4
Q1. (MCQ) The two anomalous configurations in the 3d series are:
Q2. (SA) Predict whether the Pt atom (Z = 78) follows the simple Aufbau order or shows an exception. Justify.
Q3. (MCQ) Which of these is not classified as a transition element by IUPAC?
Q4. (LA) Write the ground-state outer configurations of (i) V (ii) Cr³⁺ (iii) Cu (iv) Zn²⁺. State which of these has the maximum number of unpaired electrons.
Q5. (HOT) Across the 3d row, melting points first rise, peak, then fall. Suggest two reasons why Mn melts at a much lower temperature than its neighbours Cr and Fe.
Assertion–Reason Questions L4 L5
Choose: A) Both A and R true and R explains A · B) Both true but R does not explain A · C) A true, R false · D) A false, R true.
Assertion (A): Cr has the configuration [Ar]3d⁵4s¹ rather than [Ar]3d⁴4s².
Reason (R): A half-filled d⁵ sub-shell is exceptionally stable due to maximum exchange energy.
Assertion (A): Zinc is not regarded as a transition element.
Reason (R): Zinc has a fully filled d-shell (3d¹⁰) in both its ground state and its common +2 oxidation state.
Assertion (A): Pd has the unique outer configuration 4d¹⁰5s⁰.
Reason (R): The energy gap between 4d and 5s in Pd is so large that the 5s lies far above the 4d after both electrons are promoted.
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