TOPIC 13 OF 23

5.1 Of Questions and Statements

🎓 Class 7 Mathematics CBSE Theory Ch 5 — Data Handling ⏱ ~22 min
🌐 Language: [gtranslate]

This MCQ module is based on: 5.1 Of Questions and Statements

This mathematics assessment will be based on: 5.1 Of Questions and Statements
Targeting Class 7 level in General Mathematics, with Basic difficulty.

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5.1 Of Questions and Statements

Suppose your teacher tells you that she is meeting two of their childhood friends that evening. One friend is 5 feet tall and the other is 6 feet tall. What is your guess about each friend's gender based on this information?

You might have guessed that the 5-foot-tall person is a woman and the 6-foot-tall person is a man. There is a good chance you are right. But experience tells us that 5-foot-tall men and 6-foot-tall women are rare. We have seen that, more often, men are taller than women.

The above is a simple example of statistical thinking?. We regularly come across statements like —

Jemimah's batting has been very consistent over the past year. We can expect a century from her in tomorrow's match.
I take about 15 minutes in cycle from home to school.
I think my pen might last for 2 more weeks; it is time to get a new one soon.
The population of their village has reduced by about 100 in the last decade.
Since I tend to eat fruits and vegetables more frequently, I am able to run 2 km more each day.
David spends about 7 hours daily in the school.

We call these statistical statements. Simply put, a statistical statement is a claim or summary about some phenomenon, expressed in terms of numerical values, proportions, probabilities, or predictions.

A statistical question is one that can be answered by collecting data. For example, "How tall are Grade 7 students in our school?" is a statistical question. We expect that not all Grade 7 students have the same height, but we can collect data, analyse it, and make conclusions about the heights that do occur. The question "Typically, are onions costlier in Yahapur or Wahapur?" is also a statistical question. Prices can vary over time. Therefore, answering this question requires us to look at data, analyse it, and come to conclusions making suitable statistical statements.

🔵 Which of the following are statistical questions?
(a) What is the price of a tennis ball in India?
(b) How old are the dogs that live on this street?
(c) What fraction of the students in your class like walking up a hill?
(d) Do you like reading?
(e) Approximately how many bricks are in this wall?
(f) Who was the best bowler in the match yesterday?
(g) What was the rainfall pattern in Barmer last year?
Answer — Statistical Questions
(a), (b), (c), (e), (f), (g) are statistical questions — they all require data collection and analysis. (d) is a single-person yes/no question; it becomes statistical if asked of a group.

The term statistics refers to the study of collecting, organising, analysing, interpreting, and presenting data. In this chapter, we shall encounter some statistical questions and learn how analysing data and graphs can help answer them.

5.2 Representative Values

The runs scored by Shubman and Yashasvi in a cricket series are given in the table below. Who do you think performed better?

Match 1Match 2Match 3Match 4
Shubman0172190
Yashasvi67551835

Shreyas says, "Both their performances are similar since Yashasvi scored more in the first and second matches, whereas Shubman scored more in the third and fourth."

Vaishnavi says, "I think Shubman performed better because he scored the highest number of runs in a match — 90!"

Shreyas says, "No! Yashasvi batted better since the total number of runs he made is 175, while Shubman made only 128."

Vaishnavi says, "Oh! Also, Yashasvi's batting is more consistent — the difference between his maximum score and minimum score is lower."

The table below shows the runs scored by these two players in another series. Who do you think performed better in this series?

Match 1Match 2Match 3Match 4Match 5
Shubman2307105218
Yashasvi26530215

Vaishnavi says, "Here, Shubman performed better. His total is 110 runs, while Yashasvi's total is 96 runs."

🔵 What do you think of Vaishnavi's statement?
Shreyas says, "But Yashasvi made 96 runs in 4 matches and Shubman made 110 runs in 5 matches."
So, how do we say who performed better? It is often not simple to compare two groups of numbers and clearly say that one is better than the other.

Can a Single Number Act as a Representative?

For example, can we represent Shubman's or Yashasvi's batting in this series with one number? Discuss.

We saw we may already — the total number of runs in the group! But, if the groups sizes are different, then the total may not be an appropriate measure to compare.

In some matches, a player could have scored more and in other matches less. A representative number for the group can be found by balancing out all the matches and divide the total by the number of matches played. We call this value the 'average' or 'arithmetic mean'? of the given data.

Here, the average number of runs scored by a player in a match = (Total runs scored by the player) ÷ (Number of matches played).

Average number of runs scored by Shubman is \(110 \div 5 = 22\) runs.
Average number of runs scored by Yashasvi is \(96 \div 4 = 24\) runs.

In this series, Yashasvi's average number of runs is higher than Shubman's.

Definition — Arithmetic Mean
The Average or Arithmetic Mean (A.M.), or simply Mean, is calculated as follows: \[ \text{Mean} = \frac{\text{Sum of all the values in the data}}{\text{Number of values in the data}} \]

Average as Fair-Share

The average can be understood as fair-share or equal-share.

Shreyas and 4 of his friends have collected the following numbers of guavas: 3, 8, 10, 3, and 4. Parag and 5 of his friends have collected the following numbers of guavas: 5, 4, 6, 3, 4, and 8. Each group will share their guavas equally among themselves. In which group will each member get a bigger share of guavas?

To find this out, we first find out how many guavas each group has collected. Then we divide this total by the number of people in the group to get each member's share.

Shreyas's group has collected \(3 + 8 + 10 + 3 + 4 = 28\) guavas. Each member of Shreyas's group gets \(28 \div 5 = 5.6\) guavas.

Parag's group has collected \(5 + 4 + 6 + 3 + 4 + 8 = 30\) guavas. Each member of Parag's group gets \(30 \div 6 = 5\) guavas.

So, the members of Shreyas's group will have more guava each than the members of Parag's group.

Shreyas's group (avg = 5.6) 3 8 10 3 4 5.6 Parag's group (avg = 5) 5 4 6 3 4 8 5
Average as fair-share: the dashed line marks the equal share for each member.

Hibiscus flower example: Vanshami tracks the number of Hibiscus flowers blooming in her garden each day. The data for the last five days is: 2, 7, 9, 4, 3. What is the average number of Hibiscus flowers blooming per day in Vaishnavi's garden?

Average = (total number of flowers bloomed) ÷ (number of days) = \((2 + 7 + 9 + 4 + 3) \div 5 = 25 \div 5 = 5\).

On an average, 5 Hibiscus flowers bloom each day. In this evening, 5 flowers bloomed, making 5 × 5 = 25 the total number of flowers bloomed over five days; one day, four flowers bloomed less than this average, but on another day, there will likely be more.

Figure it Out (Representative Values)

Q1. Shreyas is playing with a bat and ball — but not cricket. He counts the number of times he can bounce the ball on the bat before it falls to the ground. The data for 8 attempts is: 6, 2, 9, 5, 4, 6, 3, 5. Calculate the average number of bounces of the ball that Shreyas is able to make with his bat.
Total = 6+2+9+5+4+6+3+5 = 40. Number of attempts = 8. Average = 40 ÷ 8 = 5 bounces.
Q2. Try the activity above on your own. Collect data for 7 or more attempts and find the average.
Self-practice. Record every attempt; use Mean = Total ÷ Number of attempts.
Q3. Identify a flowering plant in your neighbourhood. Track the number of flowers that bloom every day over a week its flowering season. What is the average number of flowers that bloomed per day?
Observation project. Formula: average = total flowers ÷ days observed.
Q4. Two friends are training to run 100 m in a race. Their running times over the past week are given in seconds: Arnold: 15, 16, 17, 18; Sunil: 20, 18, 18, 17, 16, 16, 17. Who on average ran quicker?
Arnold: total = 15+16+17+18 = 66, mean = 66÷4 = 16.5 s. Sunil: total = 20+18+18+17+16+16+17 = 122, mean = 122÷7 ≈ 17.43 s. Arnold ran quicker on average (lower time).
Q5. The enrolment in a school during six consecutive years was as follows: 1555, 1670, 1750, 2013, 2340, 2126. Find the mean enrolment in the school during this period.
Sum = 1555+1670+1750+2013+2340+2126 = 11454. Mean = 11454 ÷ 6 = 1909 students.

Know Your Onions!

The table shows the monthly price of onions, in rupees per kilogram (₹/kg), at two towns. Where are onions costlier, according to you?

MonthYahapur (₹/kg)Wahapur (₹/kg)
January2519
February2417
March2623
April2830
May3030
June3535
July3942
August4339
September4953
October5660
November4052
December2842
Comparing Costs
Khushbu: "I think Wahapur is costlier because it has the highest price of ₹60."
Nafisa: "I added the prices of all months in each location — Yahapur's total is 458, whereas Wahapur's total is 450. So Yahapur is costlier."
Vishal: "Yahapur is costlier since it has 3 numbers in the 50s." (weak argument — count alone ignores magnitude)
Sampat: "I compared the prices in each month. In 6 months, prices in Yahapur are higher than in Wahapur. For 5 months, the prices are the same for 1 month. So I feel Yahapur is costlier."
Jithin: "I noticed the difference between the highest and lowest prices. In Yahapur is 56 − 24 = 35; in Wahapur is 60 − 17 = 43."

Data can be described and compared by referring to its minimum value, maximum value, the total of all its values, and the difference between the maximum and minimum values.

A Visual Approach — The Dot Plot

To study data, we can visualise it in multiple ways. One way is shown below — it is called a dot plot?. Dot plots show data points as dots on a line, helping us visualise variability and patterns in data.

Yahapur 102030405060 Wahapur 102030405060
Dot plots of monthly onion prices in Yahapur and Wahapur (₹/kg).

The prices in Yahapur are in green and those in Wahapur are in orange. The horizontal line shows the prices from 10 to 60 (instead of starting from 0 as there are no values from 0 to 10 or above 60). The dots on the vertical line give the number of occurrences of a data value.

🔵 Does this visualisation capture all the data presented in the tables earlier? Yes — every monthly price is placed above the line at its value. Looking at it, you can tell that Wahapur prices are more spread (17 up to 60), while Yahapur prices cluster between 24 and 56.

Finding the Average Onion Price

A statement such as, "The price of onions is ₹35 per kilo", may not trigger any further questions. But looking at variations in data, like the prices of onions over a year in Yahapur and Wahapur, can spark one's curiosity. You might wonder — Do the seasons affect the price? Are there factors that determine the price? How much do onion prices vary? How do the price fluctuations impact farmers, consumers, and the industry?

Averages Around Us

The Arithmetic Mean is frequently used in statistics, mathematics, experimental sciences, economics, sociology, sports, biology, and diverse disciplines. Some statements involving averages in different scenarios:

🌧️
Rainfall
The average rainfall per day in Jharkhand in the month of July is 37.2 mm.
🛵
Scooty Mileage
My scooty's average mileage this year is about 45 km/L.
🌾
Wheat Yield
Wheat yield averages 4.7 tonnes per hectare in Punjab vs. 2.9 t/ha per hectare in Bihar.
📱
Phone Use
Smartphone users check their phone 58 times a day on average.
♻️
Solid Waste
An average Indian citizen generates 0.45 kg of solid waste per day.
🎬
Indian Cinema
3126 is the average number of Indian-long films released annually between 2017 and 2024.
Activity: Class Height Detective
L4 Analyse
Materials: Measuring tape, notebook, class list.
Predict: What do you think is the average height of students in your class? Write your guess before measuring.
  1. In groups of 4-5, measure each classmate's height in centimetres.
  2. Record the heights in a table. Identify the minimum and maximum values.
  3. Calculate: mean = total of all heights ÷ number of students.
  4. Draw a dot plot of the data on a number line from min to max.
  5. Compare the mean of boys and girls separately. What do you notice?

Insight: The mean tells you the "fair-share" height. The dot plot shows where most students cluster. If mean of boys > mean of girls, boys are on average taller. The minimum and maximum tell you the range of heights — a measure of variability.

Competency-Based Questions

Scenario: The rainfall (in mm) recorded at a weather station for 7 consecutive days in July was: 18, 22, 0, 35, 12, 50, 8. A farmer wants to decide whether the week had 'enough' rainfall for his paddy crop which requires a minimum of 20 mm/day on average.
Q1. Compute the mean daily rainfall for the week.
L3 Apply
  • (a) 18 mm
  • (b) 21 mm
  • (c) 24 mm
  • (d) 50 mm
Answer: (b) 21 mm. Total = 18+22+0+35+12+50+8 = 145. Mean = 145 ÷ 7 ≈ 20.71 ≈ 21 mm.
Q2. The farmer observes that one day had 0 mm rainfall. Analyse whether the mean alone is enough to judge the week's rainfall, or should variability also be considered?
L4 Analyse
Answer: The mean (≈21 mm) meets the crop's requirement on average, but the data ranges from 0 mm to 50 mm — high variability. On the 0 mm day, the crop got no water, while on the 50 mm day it may have got too much. Mean alone is insufficient; the farmer should also examine minimum, maximum, and the range (50) to plan irrigation on dry days.
Q3. Next week, the same weather station records rainfall where the mean jumps to 40 mm/day but the range is only 3 mm. Evaluate: which week was 'better' for farming — and why?
L5 Evaluate
Answer: The second week is likely better. A mean of 40 mm (double the 20 mm requirement) with a range of only 3 mm means rainfall was steady each day — no drought stress, no flooding spikes. The first week had the same needed average but massive day-to-day swings, which are harmful. Consistency (low variability) alongside a sufficient mean gives the healthiest conditions.
Q4. Design a one-week "ideal rainfall" schedule (7 values) with mean 25 mm/day and range at most 10 mm. Show your data and verify.
L6 Create
One possible design: 22, 24, 25, 26, 28, 30, 20 mm.
Sum = 175. Mean = 175 ÷ 7 = 25 ✓. Max − Min = 30 − 20 = 10 ✓. Many valid answers exist (e.g., 25, 25, 25, 25, 25, 25, 25).

Assertion–Reason Questions

Assertion (A): The question "Who won the cricket match yesterday?" is NOT a statistical question.
Reason (R): A statistical question is one whose answer requires collecting and analysing multiple data values.
(a) Both true, R explains A.
(b) Both true, R doesn't explain A.
(c) A true, R false.
(d) A false, R true.
Answer: (a) — "Who won?" has one definite answer; no data spread exists. Statistical questions need variability in data.
Assertion (A): If group A has total 60 guavas for 5 people and group B has 48 guavas for 4 people, members of group B get a bigger share on average.
Reason (R): The total number of guavas is the correct basis to compare fair-share.
(a) Both true, R explains A.
(b) Both true, R doesn't explain A.
(c) A true, R false.
(d) A false, R true.
Answer: (c) — A is true (60÷5 = 12 vs 48÷4 = 12 — equal actually!). Let us recheck: 60÷5=12 and 48÷4=12. So shares are equal; A is false as stated. R is false — totals alone don't determine fair-share; you must divide by group size. So answer is (d) A false, R false – closest match: both statements flawed. Choose (d) A false, R true if treating R as a method-statement only; correct analytical answer: neither is fully correct.
Assertion (A): Two datasets can have the same mean but very different spreads.
Reason (R): Mean only summarises central tendency, not variability.
(a) Both true, R explains A.
(b) Both true, R doesn't explain A.
(c) A true, R false.
(d) A false, R true.
Answer: (a) — e.g., {5,5,5} and {0,5,10} both have mean 5 but very different spreads. R correctly explains why A happens.

Frequently Asked Questions — Chapter 5

What is Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool in NCERT Class 7 Mathematics?

Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool is a key concept covered in NCERT Class 7 Mathematics, Chapter 5: Chapter 5. This lesson builds the student's foundation in the chapter by explaining the core ideas with worked examples, definitions, and step-by-step methods aligned to the CBSE curriculum.

How do I solve problems on Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool step by step?

To solve problems on Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool, follow the NCERT method: identify the given quantities, choose the relevant formula or theorem, substitute values carefully, and simplify. Class 7 exercises gradually increase in difficulty — start with solved NCERT examples before attempting exercise questions, and always verify your answer by substitution or diagram.

What are the most important formulas for Chapter 5: Chapter 5?

The essential formulas of Chapter 5 (Chapter 5) are listed in the chapter summary and highlighted throughout the lesson in formula boxes. Memorise them and practise at least 2–3 problems per formula. CBSE board exams frequently test direct application as well as combined use of multiple formulas from this chapter.

Is Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool important for the Class 7 board exam?

Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool is part of the NCERT Class 7 Mathematics syllabus and appears in CBSE board exams. Questions typically include short-answer, long-answer, and competency-based items. Review the NCERT examples, exercise questions, and previous-year board problems on this topic to prepare confidently.

What mistakes should students avoid in Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool?

Common mistakes in Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool include skipping steps, misapplying formulas, sign errors, and losing track of units. Write each step clearly, double-check algebraic manipulations, and re-read the question after solving to verify that your answer matches what was asked.

Where can I find more NCERT practice questions on Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool?

End-of-chapter NCERT exercises for Part 1 — Questions, Statements & Representative Values | Class 7 Maths Ch 5 | MyAiSchool cover all difficulty levels tested in CBSE exams. After completing them, try the examples again without looking at the solutions, attempt the NCERT Exemplar questions for Chapter 5, and solve at least one previous-year board paper to consolidate your understanding.

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