This MCQ module is based on: Huygens Principle Interference
Huygens Principle Interference
This assessment will be based on: Huygens Principle Interference
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Huygens Principle Interference
10.1 Introduction — From Particles to Waves
For centuries, physicists argued about what light really is. In 1637, Descartes treated light as tiny material particles, and Newton later refined this into the corpuscular theory — small "corpuscles" travelling in straight lines. But as early as 1678, the Dutch scientist Christiaan Huygens proposed that light is a wave, much like ripples spreading on a pond.
Newton's reputation kept the particle picture alive until Thomas Young's 1801 double-slit experiment produced unmistakable interference fringes — a signature only waves can create. By 1873, James Clerk Maxwell unified electricity, magnetism and optics: light is an electromagnetic wave.
10.2 Huygens Principle
A wavefront is the locus of all points that oscillate in the same phase. For a stone dropped in water, the circular ripples are the wavefronts. For light, three shapes are common:
- Spherical — from a point source radiating equally in all directions.
- Cylindrical — from a line source such as a slit illuminated by a lamp.
- Plane — from a very distant source (e.g. the Sun), where the curvature is negligible.
Huygens' construction
Huygens' geometrical principle has two statements:
- Every point on a given wavefront acts as a fresh secondary source emitting tiny spherical wavelets in the forward direction, each travelling with the speed of the wave in the medium.
- The new wavefront, at a later instant \(t\), is the forward envelope (tangent surface) of all these secondary wavelets.
10.3 Reflection and Refraction Using Huygens Principle
Deriving the Law of Reflection
Consider a plane wavefront AB falling obliquely on a plane mirror. As B travels a distance \(v\tau\) to hit the mirror at \(C\), the wavelet from A expands into a hemisphere of radius \(v\tau\). The tangent from \(C\) touches this hemisphere at \(E\). Triangles \(ABC\) and \(AEC\) share the hypotenuse \(AC\) and both have perpendicular sides of length \(v\tau\); hence they are congruent. Therefore:
Deriving Snell's Law of Refraction
Let light cross from medium 1 (speed \(v_1\)) into medium 2 (speed \(v_2\)). While the wavelet at \(B\) travels \(BC=v_1\tau\) to reach the interface, the wavelet from \(A\) in the second medium has expanded a radius \(AE=v_2\tau\). From the two right-angled triangles sharing \(AC\):
\[\sin i=\frac{v_1\tau}{AC},\qquad \sin r=\frac{v_2\tau}{AC}\]Dividing:
\[\boxed{\;\frac{\sin i}{\sin r}=\frac{v_1}{v_2}=\frac{n_2}{n_1}\;}\]This is Snell's law: \(n_1\sin i=n_2\sin r\). Two important facts:
- Frequency \(\nu\) is unchanged on refraction — it is fixed by the source.
- Wavelength and speed change: \(\lambda_2=\lambda_1(v_2/v_1)=\lambda_1/n\) (for light going from vacuum into a medium of refractive index \(n\)).
10.4 Coherent and Incoherent Addition of Waves
The superposition principle states: when two or more waves meet at a point, the resultant displacement equals the algebraic sum of the individual displacements.
Coherent Sources
Let two coherent waves of amplitudes \(a_1,a_2\) and intensities \(I_1\propto a_1^2,\ I_2\propto a_2^2\) meet with phase difference \(\phi\). The resulting intensity is:
\[I=I_1+I_2+2\sqrt{I_1 I_2}\cos\phi\]- Constructive (\(\phi=0,2\pi,\dots\)): \(I_\text{max}=(\sqrt{I_1}+\sqrt{I_2})^2\).
- Destructive (\(\phi=\pi,3\pi,\dots\)): \(I_\text{min}=(\sqrt{I_1}-\sqrt{I_2})^2\).
- For equal intensities \(I_1=I_2=I_0\): \(I=4I_0\cos^2(\phi/2)\), with \(I_\text{max}=4I_0\) and \(I_\text{min}=0\).
Incoherent Sources
If phase varies rapidly and randomly (two separate bulbs, for instance), \(\cos\phi\) averages to zero and intensities simply add:
\[I=I_1+I_2\]Take a rectangular tray of water. Dip a finger to generate circular ripples, then dip two fingers together at the same rate about 4 cm apart.
- Observe the still "lines" radiating outward — points of destructive interference.
- Observe the "loud" crests in between — points of constructive interference.
- Now tap one finger irregularly. The pattern disappears.
Interactive — Wavefront Propagation
Play the animation to watch a plane wavefront reflecting off a mirror, then refracting at a denser medium (wavelength shrinks).
Worked Examples
A plane wavefront strikes a mirror such that \(BC=v\tau=3\) cm is the distance travelled by one edge while the other edge reflects. Using Huygens' construction, prove \(i=r\) and find the reflected-wavefront length if \(AC=5\) cm.
Light travelling in air (\(v_1=3\times10^8\) m/s) enters glass with \(v_2=2\times10^8\) m/s at \(i=30°\). Find \(r\) and verify the refractive index.
Two coherent waves of wavelength 600 nm travel from two sources to a point, with path difference 1.5 μm. Find the phase difference and state whether interference is constructive or destructive.
Two coherent sources have intensities in the ratio \(I_1:I_2=9:1\). Find the ratio \(I_\text{max}:I_\text{min}\).
Two coherent waves each of intensity \(I_0\) overlap at a point where their phase difference is \(\phi=60°\). Find the resultant intensity.
Competency-Based Questions
Q1. The principle that every point on a wavefront acts as a secondary source of wavelets was given by:
Q2. When light passes from air into water, which of the following remains unchanged?
Q3. (Short Answer) Why can two independent bulbs never produce an interference pattern?
Q4. (True/False) The frequency of light changes when it enters a denser medium.
Q5. (HOT) Two coherent sources have intensities \(I\) and \(4I\). Compute the ratio of maximum to minimum intensity on a screen.
Assertion–Reason Questions
Options: (A) Both true, R correct explanation of A. (B) Both true, R not the correct explanation. (C) A true, R false. (D) A false, R true.
Assertion: A point source produces a spherical wavefront.
Reason: Every ray emitted from such a source travels outward in all directions with the same speed in a homogeneous medium.
Assertion: Two independent sodium lamps cannot produce sustained interference.
Reason: Their phase difference is constant in time.
Assertion: For equal-intensity coherent sources, the minimum intensity in the interference pattern is zero.
Reason: \(I=4I_0\cos^2(\phi/2)\) vanishes when \(\phi=\pi\).
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Board exam sample papers
Physics — CBSE Class XII Sample Paper 1 (2025-26)
Section A · Section B · Section C · Section D · Section E