This MCQ module is based on: Recap and Decimal Multiplication
Recap and Decimal Multiplication
This mathematics assessment will be based on: Recap and Decimal Multiplication
Targeting Class 7 level in General Mathematics, with Basic difficulty.
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4.1 A Quick Recap of Decimals
Recall that decimals? are the natural extension of the Indian place-value system to represent decimal fractions \(\left(\frac{1}{10}, \frac{1}{100}, \frac{1}{1000}\right.\) and so on) and their sums.
For example, 27.53 refers to a quantity that has: 2 Tens, 7 Units (Ones), 5 Tenths, 3 Hundredths.
We have already learned how to multiply and divide fractions. In this chapter, we will learn how to perform these operations on decimals. You will see that the procedures for multiplying and dividing decimals are simply an extension of the procedures we already know for multiplying and dividing counting numbers.
Jonali & Pallabi: Market Shopping
Jonali and Pallabi play a game. Jonali says a fraction and Pallabi gives the equivalent decimal. Pallabi's answers fill in the blank spaces.
Jonali goes to the market to buy spices. She purchases: 50 g of Cinnamon, 100 g of Cumin seeds, 25 g of Cardamom, and 250 g of Pepper. Express each of the quantities in kilograms by writing them in terms of fractions as well as decimals. (1 kg = 1000 g.)
| Spice | Grams | Fraction of 1 kg | Decimal (kg) |
|---|---|---|---|
| Cinnamon | 50 | \(\tfrac{50}{1000}\) | 0.050 |
| Cumin | 100 | \(\tfrac{100}{1000}\) | 0.100 |
| Cardamom | 25 | \(\tfrac{25}{1000}\) | 0.025 |
| Pepper | 250 | \(\tfrac{250}{1000}\) | 0.250 |
The fractions Jonali gave Pallabi have denominators 10, 100, 1000, and so on.
Expanding Fractions as Sums: From Fraction to Decimal
Write the following fractions as a sum of fractions and also as decimals.
| Fraction | Expanding the Numerator | Sum of tenths, hundredths, thousandths | Decimal |
|---|---|---|---|
| \(\tfrac{254}{1000}\) | \(\tfrac{200+50+4}{1000}\) | \(0.2 + 0.05 + 0.004\) | 0.254 |
| \(\tfrac{847}{10000}\) | \(\tfrac{800+40+7}{10000}\) | \(0.08+0.004+0.0007\) | 0.0847 |
| \(\tfrac{173}{100}\) | \(\tfrac{100+70+3}{100}\) | \(1+0.7+0.03\) | 1.73 |
| \(\tfrac{23}{1000}\) | \(\tfrac{0+20+3}{1000}\) | \(0.02+0.003\) | 0.023 |
- Step 1: Write the dividend as it is and place a decimal point at the end.
- Step 2: Count the number of zeros in the divisor.
- Step 3: Move the decimal point from Step 1 left by the same number of places as the count from Step 2. Add zeros in front if needed.
Other examples: \(24 \div 100 = 0.24\); \(12 \div 1000 = 0.012\); \(678 \div 1000 = 0.678\); \(12345 \div 1000 = 12.345\).
4.2 Decimal Multiplication
Example 1: Arshad's Pens
Arshad goes to a stationary shop and purchases 5 pens. If one pen costs ₹9.5 (9 rupees and 50 paisa), how much should he pay the shopkeeper?
What operation must we use here? We have to multiply 9.5 by 5, which is the same as adding 9.5 five times.
\(9.5 \times 5 = 9.5 + 9.5 + 9.5 + 9.5 + 9.5 = 47.5\)
We can also directly multiply the numbers by converting them into fractions.
\(9.5 = \frac{95}{10}\) and 5 is \(\frac{5}{1}\) as a fraction. So:
\(\frac{5}{1} \times \frac{95}{10} = \frac{5 \times 95}{1 \times 10} = \frac{475}{10} = 47.5\)
The cost of 5 pens is ₹47.50.
Recall that, to find the product of two fractions, we multiply the numerators and multiply the denominators.
Example 2: Car Petrol
A car travels 12.5 km per litre of petrol. What is the distance covered in 7.5 litres of petrol?
We have to multiply 12.5 by 7.5.
The distance covered = \(12.5 \times 7.5 = \frac{125}{10} \times \frac{75}{10} = \frac{125 \times 75}{10 \times 10} = \frac{9375}{100} = 93.75\).
The distance covered is 93.75 km.
Example: \(0.5 \times 4 = 2\) (whole). Yes, products of decimals can land exactly on a whole number when the decimal parts combine to 1 (or multiples of 1).
Example 3: Ajay's Walk to School
The distance between Ajay's school and his home is 827 m. He walks to school in the morning and then walks back home in the evening, 6 days a week. How much does Ajay walk in a week? Answer in kilometres.
Each way between school and home, Ajay walks 827 metres, i.e., 0.827 km. So, in a day he walks:
\(0.827 \times 2 = \frac{827}{1000} \times 2 = \frac{827 \times 2}{1000} = \frac{1654}{1000} = 1.654\) km
He goes to school 6 days a week. So, in a week he walks:
\(1.654 \times 6 = \frac{1654}{1000} \times 6 = \frac{9924}{1000} = 9.924\) km.
Ajay walks 9.924 km a week.
Example 4: Area of a Rectangle
Find the area of the given rectangle with length 13.3 cm and breadth 5.7 cm.
The area = length × breadth = \(5.7 \times 13.3 = \frac{57}{10} \times \frac{133}{10} = \frac{7581}{100} = 75.81\) sq cm.
Rule: Counting Decimal Places in Products
Observe the number of digits after the decimal point in the multiplier, the multiplicand and the product. Also note the number of zeros in the denominator.
| Example | Digits in Multiplier | Digits in Multiplicand | Digits in Product |
|---|---|---|---|
| 9.5 × 5 = 47.5 | 1 | 0 | 1 |
| 12.5 × 7.5 = 93.75 | 1 | 1 | 2 |
| 1.64 × 6 = 9.84 | 2 | 0 | 2 |
| 5.7 × 13.3 = 75.81 | 1 | 1 | 2 |
| 5.96 × 24.8 = 147.808 | 2 | 1 | 3 |
Suppose we know that \(596 \times 248 = 147808\). Can you immediately write down the product of \(5.96 \times 24.8\)?
Example: To evaluate \(5.96 \times 24.8\):
\(596 \times 248 = 147808\) → 2 + 1 = 3 decimal places → 5.96 × 24.8 = 147.808
- Round the numbers: 3.5 ≈ 3.5, ₹124.50 ≈ ₹125.
- Estimate: 3.5 × 125 = 437.50.
- Now multiply exactly: 3.5 × 124.50 = 35/10 × 12450/100 = 435750/1000 = 435.75.
- Compare estimate (₹437.50) vs exact (₹435.75). The error is ≈ ₹1.75 — good estimate!
Insight: Rounding to 'friendly' numbers (125, 10, etc.) gives quick mental estimates that are usually within 1–2% of the exact value. Useful for checking whether a shop bill is reasonable.
Competency-Based Questions
Car A: 15.5 km/l, trip 310 km → 20 l → ₹2129 at ₹106.45/l.
Bike: 45.5 km/l, trip 227.5 km → 5 l → ₹532.25.
SUV: 9.5 km/l, trip 190 km → 20 l → ₹2129. Many valid designs possible — required: decimal efficiency and decimal cost per litre.
Assertion–Reason Questions
R: The number of decimal places in a product equals the sum of the decimal places of the factors.
R: 0.1 = 1/10.
Frequently Asked Questions
How do you multiply two decimals?
Ignore decimal points, multiply the numbers as whole numbers, then place the decimal point in the product so the total decimal places equal the sum of decimal places in the two factors. For example, 0.3 x 0.2 = 0.06. NCERT Class 7 Chapter 4 teaches this rule.
What is 2.5 x 1.5?
Ignore decimals: 25 x 15 = 375. Each factor has 1 decimal place, so the product has 1 + 1 = 2 decimal places. Answer: 3.75. NCERT Class 7 Ganita Prakash Part 2 Chapter 4 uses this method.
Why multiply decimals as if they were whole numbers first?
Treating decimals as whole numbers avoids confusion during the multiplication step. The decimal point is inserted at the end based on a simple counting rule. NCERT Class 7 Chapter 4 finds this the clearest approach for beginners.
How does multiplying by 0.1 affect a number?
Multiplying by 0.1 shrinks the number to one-tenth: shift the decimal point one place left. For example, 34 x 0.1 = 3.4; 0.7 x 0.1 = 0.07. NCERT Class 7 Part 2 Chapter 4 emphasises this pattern.
What is decimal place value recap about?
The recap revisits ones, tenths, hundredths, thousandths positions and the value of each digit. It prepares students for decimal multiplication and division. NCERT Class 7 Ganita Prakash Part 2 Chapter 4 starts with this foundation.
How many decimal places does 1.23 x 4.5 have?
1.23 has 2 decimal places and 4.5 has 1 decimal place, so the product has 2 + 1 = 3 decimal places. Compute 123 x 45 = 5535, then place the decimal: 5.535. NCERT Class 7 Chapter 4 shows this.
Frequently Asked Questions — Chapter 4
What is Recap and Decimal Multiplication in NCERT Class 7 Mathematics?
Recap and Decimal Multiplication is a key concept covered in NCERT Class 7 Mathematics, Chapter 4: Chapter 4. This lesson builds the student's foundation in the chapter by explaining the core ideas with worked examples, definitions, and step-by-step methods aligned to the CBSE curriculum.
How do I solve problems on Recap and Decimal Multiplication step by step?
To solve problems on Recap and Decimal Multiplication, follow the NCERT method: identify the given quantities, choose the relevant formula or theorem, substitute values carefully, and simplify. Class 7 exercises gradually increase in difficulty — start with solved NCERT examples before attempting exercise questions, and always verify your answer by substitution or diagram.
What are the most important formulas for Chapter 4: Chapter 4?
The essential formulas of Chapter 4 (Chapter 4) are listed in the chapter summary and highlighted throughout the lesson in formula boxes. Memorise them and practise at least 2–3 problems per formula. CBSE board exams frequently test direct application as well as combined use of multiple formulas from this chapter.
Is Recap and Decimal Multiplication important for the Class 7 board exam?
Recap and Decimal Multiplication is part of the NCERT Class 7 Mathematics syllabus and appears in CBSE board exams. Questions typically include short-answer, long-answer, and competency-based items. Review the NCERT examples, exercise questions, and previous-year board problems on this topic to prepare confidently.
What mistakes should students avoid in Recap and Decimal Multiplication?
Common mistakes in Recap and Decimal Multiplication include skipping steps, misapplying formulas, sign errors, and losing track of units. Write each step clearly, double-check algebraic manipulations, and re-read the question after solving to verify that your answer matches what was asked.
Where can I find more NCERT practice questions on Recap and Decimal Multiplication?
End-of-chapter NCERT exercises for Recap and Decimal Multiplication cover all difficulty levels tested in CBSE exams. After completing them, try the examples again without looking at the solutions, attempt the NCERT Exemplar questions for Chapter 4, and solve at least one previous-year board paper to consolidate your understanding.