This MCQ module is based on: Multiplication and Division of Integers
Multiplication and Division of Integers
This mathematics assessment will be based on: Multiplication and Division of Integers
Targeting Class 7 level in General Mathematics, with Basic difficulty.
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2.2 Multiplication of Integers
We used the token model to represent addition and subtraction of integers. Now we explore how to model multiplication? of integers using tokens.
Positive × Positive (Placing Tokens)
Suppose we put some positive tokens into an empty bag. There are 8 positives in the bag. We can see this as adding 2 positives to the bag 4 times:
\(4 \times 2 = 8\) (two green tokens, 4 times = 8 green tokens)
Two green tokens, 4 times → \(4 \times 2 = 8\)
Positive × Negative (Placing Red Tokens)
Can we use tokens to give meaning to multiplications like \(4 \times (-2)\)?
\(4 \times (-2)\) can be interpreted as placing 2 negatives into an empty bag 4 times. There are now 8 red tokens, meaning −8.
Two red tokens, 4 times → \(4 \times (-2) = -8\)
Negative × Positive (Removing Green Tokens)
When the multiplier is positive, we place tokens into the bag. When the multiplier is negative, we remove tokens from the bag.
For \((-4) \times 2\), we need to remove 2 positives from the bag 4 times. But the bag is empty! Just as in the case of subtraction, we first place zero pairs inside and then remove the positives.
We need to remove 2 green tokens 4 times = 8 green tokens total. So we place 8 zero pairs, then remove 8 green tokens. What is left? 8 red tokens = −8.
\((-4) \times 2 = -8\)
Negative × Negative (Removing Red Tokens)
For \((-4) \times (-2)\), we need to remove 2 negatives from the bag 4 times. Again, the bag is empty, so we place 8 zero pairs, then remove 8 red tokens. What is left?
8 green tokens = +8!
\((-4) \times (-2) = +8\)
Patterns in Integer Multiplication
Let us construct a sequence of multiplications and observe the patterns:
Right column: When the multiplicand is −3, each unit decrease in multiplier increases the product by 3. This confirms that negative × negative = positive!
• \(1 \times a = a\) (identity)
• \((-1) \times a = -a\) (additive inverse)
• \(a \times b = b \times a\) (commutative? property)
Figure it Out (Multiplication)
(a) \(3 \times (-2) = -6\) (place 2 reds, 3 times = 6 reds)
(b) \((-5) \times (-2) = +10\) (remove 2 reds, 5 times → place 10 zero pairs, remove 10 reds, 10 greens left)
(c) \((-4) \times (-1) = +4\) (remove 1 red, 4 times → 4 greens left)
(d) \((-7) \times 3 = -21\) (remove 3 greens, 7 times → 21 reds left)
(a) \((-123) \times 456 = -56088\) (negative × positive = negative)
(b) \((-123) \times (-456) = +56088\) (negative × negative = positive)
(c) \(123 \times (-456) = -56088\) (positive × negative = negative)
• Same signs → Positive (both + or both −)
• Different signs → Negative (one + and one −)
In short: \(|a \times b| = |a| \times |b|\), and the sign follows the rule above.
Worked Examples
Marks for correct: \(30 \times 5 = 150\)
Marks for wrong: \(20 \times (-2) = -40\)
Total: \(150 + (-40) = 150 - 40 = \mathbf{110}\)
Mala got 110 marks.
(a) Speed = −3 m/min (downward). Time = 60 min.
Position = \(0 + 60 \times (-3) = 0 + (-180) = -180\) metres.
The elevator is 180 metres below ground level.
(b) Starting position = +15. Time = 45 min.
Distance = \(45 \times (-3) = -135\)
Position = \(15 + (-135) = -120\) metres.
The elevator is 120 metres below ground level.
A Magic Grid of Integers
A grid containing some numbers is given below. Follow the steps as shown until no number is left:
| 8 | −4 | 12 | −6 |
| −28 | 14 | −42 | 21 |
| 12 | −6 | 18 | −9 |
| 20 | −10 | 30 | −15 |
- Circle any number.
- Strike out the row and the column containing that number.
- Circle any unstruck number.
- Repeat until there are no more unstruck numbers.
- Multiply the circled numbers together.
Division of Integers
Division can be converted into multiplication. For example, \((-100) \div 25\) can be reframed as: "What should be multiplied to 25 to get −100?"
\(25 \times \,? = (-100)\)
We know that \(25 \times (-4) = (-100)\). Therefore, \((-100) \div 25 = (-4)\).
Similarly, \((-100) \div (-4)\) means: "What should be multiplied to \((-4)\) to get \((-100)\)?"
Since \((-4) \times 25 = (-100)\), we get \((-100) \div (-4) = 25\).
And \(50 \div (-25) = (-2)\), since \((-25) \times (-2) = 50\).
• \(a \div (-b) = -(a \div b)\)
• \((-a) \div b = -(a \div b)\)
• \((-a) \div (-b) = a \div b\)
Same sign → positive quotient. Different signs → negative quotient. (Same rules as multiplication!)
Figure it Out (Division)
(b) Grey loss: \(6400 \times (-5) = -32000\). To break even: \(n \times 8 = 32000\), so \(n = 4000\). 4,000 bags of white cement.
(a) \((-3) \times \text{___} = 27\)
(b) \(\text{___} \times (-8) = (-56)\)
(c) \(36 \div (-18) = \text{___}\)
(d) \(\text{___} \times (-12) = 132\)
(e) \(\text{___} \times (-8) = 7\)
(f) \(\text{___} \times 12 = -11\)
(b) \(7 \times (-8) = -56\) → 7
(c) \(36 \div (-18) = -2\) → −2
(d) \((-11) \times (-12) = 132\) → −11
(e) This requires \(-8x = 7\), so \(x = -7/8\) — no integer solution (not exactly divisible)
(f) This requires \(12x = -11\), so \(x = -11/12\) — no integer solution
Final temperature = \(32 + (-50) = 32 - 50 = \mathbf{-18°C}\).
Expressions Using Integers — Properties
Let us explore the key properties of integer multiplication and check if they hold for negative integers too.
Commutative Property
For any two integers \(a\) and \(b\): \(a \times b = b \times a\)
Example: \((-3) \times 5 = -15\) and \(5 \times (-3) = -15\) ✓
Associative Property
For any three integers \(a\), \(b\), and \(c\): \(a \times (b \times c) = (a \times b) \times c\)
Example: \(5 \times (-3) \times 4\). Either way: \((5 \times (-3)) \times 4 = (-15) \times 4 = -60\), or \(5 \times ((-3) \times 4) = 5 \times (-12) = -60\) ✓
Distributive Property
For any three integers \(a\), \(b\), and \(c\):
\(a \times (b + c) = (a \times b) + (a \times c)\)
Example: \(5 \times (4 + (-2)) = 5 \times 2 = 10\). Also: \(5 \times 4 + 5 \times (-2) = 20 + (-10) = 10\) ✓
When \(-1\) is multiplied an odd number of times, the product is negative.
In general: if a product has an even number of negative factors → result is positive; odd number → negative.
Pick the Pattern — Machine Puzzles
Two pattern machines are given below. Each machine takes 3 numbers, does some operations, and gives the result.
| Machine 1 | |||
|---|---|---|---|
| 5 | 8 | 3 | 10 |
| 10 | 11 | 12 | 9 |
| 5 | 8 | 3 | 10 |
| −3 | 10 | 2 | 5 |
| −4 | −1 | −6 | 1 |
| 10 | −11 | −1 | ? |
The operation done by Machine 1 is: (first number) + (second number) − (third number).
Written as an expression: \(a + b - c\). For example, \(5 + 8 - 3 = 10\) ✓, and \((-4) + (-1) - (-6) = -4 -1 + 6 = 1\) ✓.
So the last row: \(10 + (-11) - (-1) = 10 - 11 + 1 = 0\).
| Machine 2 | |||
|---|---|---|---|
| 4 | 9 | −3 | −21 |
| 6 | −11 | 12 | 54 |
| 5 | 3 | −2 | −22 |
| 3 | 9 | −8 | 35 |
| −1 | 5 | −4 | ? |
| −10 | −11 | −9 | ? |
- Choose an operation involving multiplication and addition of the three inputs.
- Test your machine with: (a) all positive inputs, (b) all negative, (c) mixed positive/negative.
- Does it always give a positive result? If not, modify your operation.
- Hint: Think about what happens when you square a number or use absolute values.
Example: Machine operation = \(a^2 + b^2 + c^2\). Since squaring any integer gives a non-negative result, the sum of three squares is always ≥ 0. It equals 0 only if all inputs are 0.
Another: \(a \times a + b \times b + 1\) — always positive since we add 1.
Competency-Based Questions
White cement: \(3000 \times 8 = +24000\)
Grey cement: \(5000 \times (-5) = -25000\)
Total: \(24000 + (-25000) = -1000\). A loss of ₹1,000.
New: \(3000 \times 8 + 5000 \times 2 = 24000 + 10000 = +34000\) (profit).
Difference: \(34000 - (-1000) = 35000\). The price change improves the outcome by ₹35,000.
Another: \((-20) \div 4 + 3 \times 1 - 5 = -5 + 3 - 5 = -7\) ✓
Many answers are possible!
Assertion–Reason Questions
Reason (R): The product of two negative integers is always positive.
Reason (R): A product with an odd number of negative factors is negative.
Reason (R): This property holds for all integers, including negative ones.
Frequently Asked Questions
What are the sign rules for multiplying integers?
Positive times positive gives positive. Positive times negative gives negative. Negative times positive gives negative. Negative times negative gives positive. In summary, same signs give positive and different signs give negative products. NCERT Class 7 Ganita Prakash Part II Chapter 2 explains these rules.
Why does negative times negative equal positive?
One way to understand this is through patterns. Minus 3 times 3 equals minus 9, minus 3 times 2 equals minus 6, minus 3 times 1 equals minus 3, minus 3 times 0 equals 0. Following the pattern (adding 3 each time), minus 3 times minus 1 equals 3, which is positive. NCERT Class 7 explains this pattern approach.
How do you divide integers with different signs?
When dividing integers, the sign rules are the same as multiplication. Positive divided by positive is positive. Positive divided by negative is negative. Negative divided by positive is negative. Negative divided by negative is positive. NCERT Class 7 Chapter 2 covers integer division.
What is the multiplicative identity for integers?
The multiplicative identity is 1 because any integer multiplied by 1 gives the same integer. For example, minus 7 times 1 equals minus 7. Also, any integer multiplied by 0 gives 0 and multiplied by minus 1 gives its additive inverse. NCERT Class 7 Maths covers these properties.
Can you divide by zero in integers?
No, division by zero is undefined for integers and all numbers. You cannot divide any integer by zero because no number multiplied by zero gives a non-zero result. NCERT Class 7 Ganita Prakash Part II reminds students that division by zero is not allowed in mathematics.
Frequently Asked Questions — Chapter 2
What is Multiplication and Division of Integers in NCERT Class 7 Mathematics?
Multiplication and Division of Integers is a key concept covered in NCERT Class 7 Mathematics, Chapter 2: Chapter 2. This lesson builds the student's foundation in the chapter by explaining the core ideas with worked examples, definitions, and step-by-step methods aligned to the CBSE curriculum.
How do I solve problems on Multiplication and Division of Integers step by step?
To solve problems on Multiplication and Division of Integers, follow the NCERT method: identify the given quantities, choose the relevant formula or theorem, substitute values carefully, and simplify. Class 7 exercises gradually increase in difficulty — start with solved NCERT examples before attempting exercise questions, and always verify your answer by substitution or diagram.
What are the most important formulas for Chapter 2: Chapter 2?
The essential formulas of Chapter 2 (Chapter 2) are listed in the chapter summary and highlighted throughout the lesson in formula boxes. Memorise them and practise at least 2–3 problems per formula. CBSE board exams frequently test direct application as well as combined use of multiple formulas from this chapter.
Is Multiplication and Division of Integers important for the Class 7 board exam?
Multiplication and Division of Integers is part of the NCERT Class 7 Mathematics syllabus and appears in CBSE board exams. Questions typically include short-answer, long-answer, and competency-based items. Review the NCERT examples, exercise questions, and previous-year board problems on this topic to prepare confidently.
What mistakes should students avoid in Multiplication and Division of Integers?
Common mistakes in Multiplication and Division of Integers include skipping steps, misapplying formulas, sign errors, and losing track of units. Write each step clearly, double-check algebraic manipulations, and re-read the question after solving to verify that your answer matches what was asked.
Where can I find more NCERT practice questions on Multiplication and Division of Integers?
End-of-chapter NCERT exercises for Multiplication and Division of Integers cover all difficulty levels tested in CBSE exams. After completing them, try the examples again without looking at the solutions, attempt the NCERT Exemplar questions for Chapter 2, and solve at least one previous-year board paper to consolidate your understanding.