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Prism Instruments

🎓 Class 12 Physics CBSE Theory Ch 9 – Ray Optics and Optical Instruments ⏱ ~14 min
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Prism Instruments

9.6 Refraction Through a Prism

A prism is a triangular block of transparent material. Light entering through one of its two refracting faces leaves through the other, being bent twice towards the base. The angle between the two refracting faces is the angle of prism \(A\); the angle between the emergent ray and the original direction of the incident ray is the angle of deviation \(\delta\).

A i (incident) r₁ r₂ e (emergent) δ
Fig 9.9: Refraction through a prism. The emergent ray is deviated by an angle δ from the incident direction.
Geometry of a prism: \[A = r_1 + r_2, \qquad \delta = (i + e) - (r_1 + r_2) = i + e - A\]

Minimum Deviation

As the angle of incidence varies, \(\delta\) first decreases, reaches a minimum \(\delta_m\), then increases. At this minimum, the ray inside the prism travels parallel to the base and the path is symmetric: \(i = e\) and \(r_1 = r_2 = A/2\). This gives the prism formula for refractive index:

\[n = \frac{\sin\left(\dfrac{A+\delta_m}{2}\right)}{\sin\left(\dfrac{A}{2}\right)}\]

9.7 Dispersion by a Prism

When white light passes through a prism it emerges as a band of seven colours — Violet, Indigo, Blue, Green, Yellow, Orange, Red (VIBGYOR). This splitting is called dispersion and arises because the refractive index of the glass depends on wavelength: shorter wavelengths (violet) experience a higher \(n\) and are bent more; longer wavelengths (red) experience a smaller \(n\) and are bent less.

white ROYGBIV
Fig 9.10: Dispersion of white light by a prism. Violet bends most, red least.

9.8 Some Natural Phenomena Due to Refraction and Scattering

Rainbow

A rainbow is nature's own giant spectrum, produced when sunlight enters a spherical raindrop, undergoes refraction → internal reflection → refraction. The primary rainbow appears at ~42° from the anti-solar point with red on the outside and violet on the inside; the fainter secondary rainbow appears at ~51° with reversed colour order (two internal reflections).

sunlight R ≈ 42° Raindrop
Fig 9.11: Primary rainbow — refraction, one internal reflection, refraction. Red exits at ~42°, violet at ~40°.

Scattering of Light

When light encounters particles much smaller than its wavelength, it is scattered. Lord Rayleigh showed that the scattered intensity varies as

\[I_{\text{scatter}} \propto \frac{1}{\lambda^4}\]

This inverse-fourth-power law explains:

  • Blue sky: Blue light (\(\lambda \approx 450\) nm) scatters about 10 times more strongly than red (\(\lambda \approx 700\) nm) by air molecules, so the diffuse sky glow looks blue.
  • Red sun at sunrise/sunset: At low elevations, sunlight traverses a much longer atmospheric path. Blue is scattered out along the way, so the direct beam that reaches us is dominated by the red-orange end.
  • White clouds: Cloud droplets are much larger than the wavelength of visible light. All colours are scattered almost equally (Mie scattering), so clouds look white.

9.9 Optical Instruments

The Human Eye

The eye acts as a fixed camera with a variable-focus lens. Ciliary muscles alter the focal length of the eye-lens to focus objects at different distances — a process called accommodation. The near point (least distance of distinct vision) for a normal young adult is \(D = 25\) cm.

DefectSymptomCorrection
Myopia (short-sight)Distant objects blurred; image forms in front of retina.Concave (diverging) lens.
Hypermetropia (long-sight)Near objects blurred; image forms behind retina.Convex (converging) lens.
PresbyopiaLoss of accommodation in old age (both near and far).Bifocal / progressive lenses.
AstigmatismCornea curvature unequal in different planes.Cylindrical lens.
Myopia — image in front Corrected with concave lens
Fig 9.12: A concave lens diverges incoming parallel rays just enough for the eye lens to focus them onto the retina.

Simple Microscope (Magnifying Glass)

A convex lens with the object placed within its focal length produces a virtual, erect, magnified image.

\[m_{\text{near point}} = 1 + \frac{D}{f}, \qquad m_{\infty} = \frac{D}{f}\]

Compound Microscope

Two converging lenses: a short-focus objective (\(f_o\)) forms a real, inverted, magnified intermediate image, which is then magnified further by an eyepiece (\(f_e\)) acting as a simple magnifier.

\[m = m_o \times m_e = \frac{L}{f_o}\left(1 + \frac{D}{f_e}\right)\]

where \(L\) is the distance between the objective's second focus and the eyepiece's first focus (the tube length).

Objective Eyepiece Object Real image Final (virtual)
Fig 9.13: The compound microscope — the objective produces a real magnified image that the eyepiece magnifies further.

Astronomical (Refracting) Telescope

Objective has a long focal length and large aperture, the eyepiece a short focal length. In normal adjustment (final image at infinity):

\[m = \frac{f_o}{f_e}, \qquad L = f_o + f_e\]
Objective (f₀ large) Eyepiece (fₑ small) Intermediate image
Fig 9.14: Astronomical telescope — parallel rays from infinity, objective forms a real image at its focal plane, eyepiece sends parallel rays to the eye.

Reflecting Telescope (Cassegrain)

A large concave primary mirror replaces the objective lens. A small convex secondary mirror redirects the converging beam through a hole in the primary to the eyepiece. Advantages over refractors: no chromatic aberration, easier to support huge apertures, and cheaper to build large (most modern professional telescopes — Hubble, Palomar — are reflecting).

Worked Examples — Prism, Eye and Instruments

Example 1: Refractive index from minimum deviation

A prism of angle 60° produces a minimum deviation of 30°. Find its refractive index.

\(n = \sin[(A+\delta_m)/2]/\sin[A/2] = \sin 45°/\sin 30° = (1/\sqrt 2)/(1/2) = \sqrt 2 \approx \boxed{1.414}\).

Example 2: Angular dispersion of a thin prism

A thin prism of angle 4° is made of crown glass with \(n_{\text{red}} = 1.513\) and \(n_{\text{violet}} = 1.532\). Find the angular dispersion.

For a thin prism, \(\delta = (n-1)A\). \(\delta_V - \delta_R = (n_V - n_R)A = 0.019\times 4° = \boxed{0.076°}\).

Example 3: Correction of myopia

A myopic person cannot see objects beyond 80 cm clearly. What focal length lens will correct his vision to see distant objects?

The lens should form the image of an object at infinity at his far point, 80 cm in front. \(u = -\infty,\ v = -80\) cm. \(\frac{1}{f}=\frac{1}{v}-\frac{1}{u}=-\frac{1}{80}\). \(f = -80\) cm (concave). \(P = -1.25\) D.

Example 4: Correction of hypermetropia

A hypermetropic person has a near point at 75 cm. What lens will let him read at the normal near point of 25 cm?

Lens must form image of the 25-cm object at his own near point (75 cm). \(u = -25, v = -75\). \(\frac{1}{f}=\frac{1}{-75}-\frac{1}{-25}=\frac{-1+3}{75}=\frac{2}{75}\). \(f = +37.5\) cm (convex). \(P \approx +2.67\) D.

Example 5: Compound microscope magnification

A compound microscope has \(f_o=1\) cm, \(f_e=2.5\) cm, tube length \(L=15\) cm. Final image at near point. Find magnification.

\(m = (L/f_o)(1+D/f_e) = (15/1)(1+25/2.5) = 15\times 11 = \boxed{165}\).

Example 6: Telescope magnification

A refracting telescope has \(f_o=150\) cm and \(f_e=5\) cm. Find the magnifying power in normal adjustment and the length of the tube.

\(m = f_o/f_e = 150/5 = \boxed{30}\). \(L = f_o+f_e = 155\) cm.

Example 7: Simple magnifier

A convex lens of focal length 5 cm is used as a simple magnifier with the image at 25 cm. Find the magnification.

\(m = 1 + D/f = 1 + 25/5 = \boxed{6}\).
Activity — Make Your Own SpectrumL3 Apply
Predict: If you shine sunlight onto a shallow dish of water with a mirror propped inside it, will the light emerging onto a wall be white or coloured? Why?
  1. Pour water into a shallow dish until it is half full.
  2. Rest a small plane mirror against the inside wall of the dish, tilted so its reflecting face is partly under water.
  3. Place the dish in bright sunlight and hold a white card about 30–50 cm above the mirror.
  4. Tilt and adjust the mirror angle until a spectrum appears on the card.
Explanation: The water-mirror combination behaves like a thick prism. The top surface of the water acts as one refracting face and the mirror reflects light back through the water, giving a second refraction on exit. Each colour has a different refractive index, so the emergent beam is dispersed — you see a miniature rainbow on the card.

Interactive: Eye-Defect Simulator L3 Apply

Choose the defect and a far-point / near-point value. The tool returns the corrective lens focal length and power.

Competency-Based Questions

A biology student observes onion peel under a compound microscope with objective \(f_o = 2\) cm and eyepiece \(f_e = 5\) cm. She adjusts the tube length to 15 cm and views the final image at the near point \(D=25\) cm.

Q1. L1 Remember At minimum deviation in a prism, \(r_1\) and \(r_2\) satisfy:

  • A. \(r_1 = r_2\)
  • B. \(r_1 = 2r_2\)
  • C. \(r_1 + r_2 = 90°\)
  • D. \(r_1 = 0\)
Answer: A. Symmetric ray path ⇒ \(r_1 = r_2 = A/2\).

Q2. L3 Apply Find the magnification of the compound microscope in the scenario. (3 marks)

\(m = (L/f_o)(1+D/f_e) = (15/2)(1+25/5) = 7.5\times 6 = \boxed{45}\).

Q3. L2 Understand Why does the sky look blue during the day but red at sunset? (3 marks)

Rayleigh scattering intensity \(\propto 1/\lambda^4\). During the day, short-wavelength blue scatters most, so the diffuse sky is blue. Near sunset, sunlight travels a long atmospheric slant; most blue is scattered away before reaching us, leaving the longer-wavelength red.

Q4. L3 Apply A myopic person's far point is 2 m. Find the power of corrective lens. (2 marks)

\(f = -2\) m. \(P = 1/f = -0.5\) D (concave).

Q5. L4 Analyse Why is the objective of a telescope made with large aperture and long focal length? (3 marks)

Large aperture gathers more light (brighter image) and improves resolution (smaller diffraction disc). Long \(f_o\) gives large magnification \(m=f_o/f_e\) and spreads the image across more retinal receptors for better detail.

Assertion-Reason Questions

Assertion (A): The sky appears blue to an observer on Earth.

Reason (R): Rayleigh scattering cross-section is proportional to \(1/\lambda^4\).

  • A. Both true; R is correct explanation.
  • B. Both true; R not correct explanation.
  • C. A true, R false.
  • D. A false, R true.
Answer: A. Short-wavelength blue scatters about 10× more strongly than red.

Assertion (A): Reflecting telescopes are preferred over refracting ones for large apertures.

Reason (R): A mirror shows no chromatic aberration and can be supported from the back.

  • A. Both true; R is correct explanation.
  • B. Both true; R not correct explanation.
  • C. A true, R false.
  • D. A false, R true.
Answer: A. Exactly the two main reasons reflecting designs dominate at large sizes.

Assertion (A): A concave lens is used to correct myopia.

Reason (R): The myopic eye forms the image behind the retina.

  • A. Both true; R is correct explanation.
  • B. Both true; R not correct explanation.
  • C. A true, R false.
  • D. A false, R true.
Answer: C. Assertion is correct; reason is wrong — myopia forms the image in front of the retina, not behind it.

Frequently Asked Questions - Prism Instruments

What is the main concept covered in Prism Instruments?
In NCERT Class 12 Physics Chapter 9 (Ray Optics and Optical Instruments), "Prism Instruments" covers the core principles and equations students need for board exam success. The MyAiSchool lesson explains the topic with definitions, derivations, worked examples, and interactive simulations. Key formulas and dimensional analysis are included to build conceptual depth and problem-solving skills aligned with the CBSE 2025-26 syllabus.
How is Prism Instruments useful in real-life applications?
Real-life applications of "Prism Instruments" from NCERT Class 12 Physics Chapter 9 include electronics, communication systems, medical imaging, solar energy, semiconductor devices, and modern technology. The MyAiSchool lesson links every concept to a tangible example so students see physics as a problem-solving framework for the physical world, not as abstract formulas.
What are the key formulas in Prism Instruments?
Key formulas in "Prism Instruments" (NCERT Class 12 Physics Chapter 9 Ray Optics and Optical Instruments) are derived step-by-step in the MyAiSchool lesson. Students should memorize the final formula AND understand its derivation for full board marks. Each formula is listed with its dimensional formula, SI unit, applicability range, and common pitfalls. The Summary section at the end of each part includes a quick-reference formula card.
How does this part connect to other parts of Chapter 9?
NCERT Class 12 Physics Chapter 9 (Ray Optics and Optical Instruments) is structured so each part builds on the previous one. "Prism Instruments" connects directly to neighbouring parts via shared definitions, units, and methodology. The MyAiSchool lesson cross-references related concepts with internal links so students can navigate the whole chapter as one connected story rather than disconnected fragments.
What types of CBSE board questions come from Prism Instruments?
CBSE board questions from "Prism Instruments" typically include: (1) 1-mark MCQs on definitions and formulas, (2) 2-mark short-answer derivations or applications, (3) 3-mark numerical problems with units, (4) 5-mark long-answer derivations followed by application. The MyAiSchool lesson tags each Competency-Based Question (CBQ) with Bloom level (L1-L6) so students know how to study for each weight.
How can students use the interactive simulation effectively?
The interactive simulation in the "Prism Instruments" lesson allows students to adjust input parameters (sliders or selectors) and see physical quantities update in real time. To use it effectively: (1) try extreme values to understand limiting cases, (2) compare with the analytical formula, (3) check unit consistency, (4) test special configurations from worked examples. The simulation reinforces conceptual intuition that pure formula manipulation cannot.
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