This MCQ module is based on: Em Waves Properties
Em Waves Properties
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Em Waves Properties
8.4 Electromagnetic Waves — Their Nature
From Maxwell's equations one can derive a wave equation that has plane-wave solutions of the form:
Here the wave propagates along +x; the electric field oscillates along y; the magnetic field oscillates along z. Three crucial features fall out:
- Transverse: Both E and B are perpendicular to the direction of propagation \(\hat{c}\).
- E ⊥ B: The electric field is perpendicular to the magnetic field at every instant.
- In phase: E and B reach their maxima and zeros at the same instants.
Furthermore the amplitudes are related by:
8.5 Sources of EM Waves — Hertz's Experiment
Maxwell predicted EM waves theoretically in 1865. The decisive experimental confirmation came two decades later when Heinrich Hertz built a spark-gap transmitter and a loop receiver (1887).
8.5.1 Hertz Apparatus
- Transmitter: a high-voltage induction coil charges two metal balls separated by a small spark gap. When the breakdown voltage is reached the spark jumps, driving rapid oscillation of charge in the connected wire dipole — radiating EM waves at ~50 MHz.
- Receiver: a separate copper-wire loop with its own tiny spark gap, placed across the room. Tiny sparks appear in this gap whenever the transmitter sparks — proof that the radiation has crossed the room.
8.5.2 Hertz's Conclusions
- The radiation could be reflected by metal sheets and refracted by a pitch prism - just like light.
- It could be polarised by passing through a wire grid.
- Its measured speed equalled c - confirming Maxwell's prediction.
An accelerating (or decelerating) charge is the fundamental source of EM waves. Stationary or uniformly moving charges produce only static fields - no radiation.
8.6 Speed of Electromagnetic Waves
Maxwell's equations applied to a plane wave in vacuum yield the wave speed:
In a material medium of permittivity ε and permeability μ:
For most non-magnetic transparent media \(\mu_r \approx 1\), giving the familiar \(n \approx \sqrt{\varepsilon_r}\).
| Quantity | Symbol | Value (SI) | Comment |
|---|---|---|---|
| Permittivity of free space | ε₀ | 8.854 × 10⁻¹² F/m | describes E in vacuum |
| Permeability of free space | μ₀ | 4π × 10⁻⁷ T·m/A | describes B in vacuum |
| Speed of light in vacuum | c | 2.998 × 10⁸ m/s | = 1/√(μ₀ε₀) |
| Speed in medium | v | c/n | n = refractive index |
| Ratio E₀ / B₀ | — | c | in vacuum |
8.6.1 The Wave Relations
All sinusoidal waves obey \(c = f\lambda\). For EM waves additionally:
A microwave oven operates at 2.45 GHz. Find (a) wavelength in vacuum, (b) wave number k.
(a) λ = c/f = (3 × 10⁸)/(2.45 × 10⁹) = 0.122 m = 12.2 cm. (This explains why microwave ovens are about 30 cm wide - to accommodate several half-wavelengths for a standing-wave pattern that heats food more evenly.)
(b) k = 2π/λ = 51.5 rad/m.
An EM wave in vacuum has peak electric field E0 = 50 N/C. Find (a) peak magnetic field B0, (b) peak energy density of the E-field, (c) peak energy density of the B-field.
(a) B0 = E0/c = 50/(3 × 10⁸) = 1.67 × 10⁻⁷ T.
(b) uEmax = ½ ε₀ E₀² = ½ × 8.854×10⁻¹² × 2500 = 1.11 × 10⁻⁸ J/m³.
(c) uBmax = B₀²/(2μ₀) = (1.67×10⁻⁷)²/(8π×10⁻⁷) = 1.11 × 10⁻⁸ J/m³.
The two peak energy densities are equal - a basic feature of an EM wave: energy is shared equally between E and B.
Simulation: EM Wave Calculator (E, B and c)
Set the frequency. Read the wavelength, wave number, period and the E-to-B ratio (always c).
| Wavelength λ | 12.2 cm |
| Wave number k | 51.5 rad/m |
| Period T | 0.408 ns |
| Peak magnetic field B₀ | 1.67×10⁻⁷ T |
| Speed c (in vacuum) | 2.998 × 10⁸ m/s (always) |
Pick up two polarising filters (sunglasses lenses or photography filters).
- Hold them stacked, lined up, looking at a lamp.
- Slowly rotate one filter through 90°.
Light brightness falls as you rotate. At 90° the field is almost completely blocked (Malus's law: I = I₀ cos²θ). This is possible only because light is a TRANSVERSE wave - the E-field oscillates perpendicular to propagation, so a polariser can let through only one polarisation component. Longitudinal waves (sound) cannot be polarised.
Competency-Based Questions L1L2L3L4L5
1. The wavelength of the broadcast is closest to: L1
2. Explain why E and B in an EM wave are in phase. L2
3. Find the peak magnetic field at the receiver. L3
4. Justify Hertz's claim that EM waves are transverse using one of his observations. L4
5. Critique the statement: "Static charges and uniformly moving charges both produce EM waves." L5
Assertion-Reason Questions
Assertion: The ratio E₀/B₀ for an EM wave in vacuum equals the speed of light.
Reason: Maxwell's equations require E and B amplitudes to be related by c = 1/√(μ₀ε₀).
Assertion: EM waves cannot travel through a perfect vacuum.
Reason: Waves require a material medium to vibrate.
Assertion: In an EM wave the energy is shared equally between the electric and magnetic fields.
Reason: The energy densities are uE = ½ ε₀E² and uB = B²/(2μ₀), and with E = cB these become equal.
Frequently Asked Questions - Em Waves Properties
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🎯 Practise Physics
Sit a full paper on what you have been studying, marked question by question.
Board exam sample papers
Physics — CBSE Class XII Sample Paper 1 (2025-26)
Section A · Section B · Section C · Section D · Section E