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Vector Addition, Components and Section Formula

🎓 Class 12 Mathematics CBSE Theory Ch 10 — Vector Algebra ⏱ ~15 min
🌐 Language: [gtranslate]

This MCQ module is based on: Vector Addition, Components and Section Formula

This mathematics assessment will be based on: Vector Addition, Components and Section Formula
Targeting Class 12 level in General Mathematics, with Advanced difficulty.

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10.4 Addition of Vectors

Triangle Law

Triangle Law
If two vectors are represented by sides \(\vec{AB}\) and \(\vec{BC}\) of a triangle taken in order (head of one at the tail of the next), then the sum is represented by the closing side \(\vec{AC}\): \[\boxed{\;\vec{AB}+\vec{BC}=\vec{AC}\;}\]
A B C a⃗ b⃗ a⃗ + b⃗
Triangle law: head-to-tail placement; the closing side is the sum.

Parallelogram Law

Parallelogram Law
If two vectors with the same initial point form adjacent sides of a parallelogram, their sum is the diagonal of the parallelogram drawn from the common point: \[\vec a+\vec b=\vec c\quad\text{(diagonal)}\] The two laws are equivalent — they describe the same operation.

Properties of vector addition

Algebra of vector addition
For any vectors \(\vec a,\vec b,\vec c\):
  • Commutative: \(\vec a+\vec b=\vec b+\vec a\) (parallelogram law).
  • Associative: \((\vec a+\vec b)+\vec c=\vec a+(\vec b+\vec c)\).
  • Identity: \(\vec a+\vec 0=\vec a\).
  • Inverse: \(\vec a+(-\vec a)=\vec 0\).
  • Subtraction: \(\vec a-\vec b=\vec a+(-\vec b)\).

10.5 Multiplication of a Vector by a Scalar

Scalar multiplication
For a scalar \(\lambda\in\mathbb R\) and vector \(\vec a\), the scalar multiple \(\lambda\vec a\) has
• magnitude \(|\lambda|\,|\vec a|\),
• direction same as \(\vec a\) if \(\lambda>0\), opposite if \(\lambda<0\), and \(\lambda\vec a=\vec 0\) if \(\lambda=0\).

Properties: \(\lambda(\vec a+\vec b)=\lambda\vec a+\lambda\vec b\); \((\lambda+\mu)\vec a=\lambda\vec a+\mu\vec a\); \(\lambda(\mu\vec a)=(\lambda\mu)\vec a\); \(1\vec a=\vec a\).
Unit vector
\(\hat a=\dfrac{\vec a}{|\vec a|}\) is the unit vector along \(\vec a\). It captures the direction of \(\vec a\) only; the magnitude is normalised to 1.

10.5.1 Components of a Vector

Components
Any vector \(\vec r\) in 3-D can be uniquely written as \[\vec r=a\,\hat\imath+b\,\hat\jmath+c\,\hat k,\] where \(a, b, c\) are the scalar components (real numbers) and \(a\hat\imath, b\hat\jmath, c\hat k\) are the vector components along the three coordinate axes.

\(|\vec r|=\sqrt{a^2+b^2+c^2}\). Two vectors are equal iff all three components match.

10.5.2 Vector Joining Two Points

PQ formula
If \(P(x_1,y_1,z_1)\) and \(Q(x_2,y_2,z_2)\) have position vectors \(\vec a,\vec b\) respectively, then \[\boxed{\;\vec{PQ}=\vec b-\vec a=(x_2-x_1)\hat\imath+(y_2-y_1)\hat\jmath+(z_2-z_1)\hat k\;}\] "Head minus tail" — direction goes FROM \(P\) TO \(Q\). Magnitude \(|\vec{PQ}|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}\) is the distance from \(P\) to \(Q\).

10.5.3 Section Formula

Section formula — internal and external division
If \(R\) divides segment \(PQ\) (with position vectors \(\vec a,\vec b\)) in the ratio \(m:n\),

Internal division: \(\vec{OR}=\dfrac{m\vec b+n\vec a}{m+n}\).
External division: \(\vec{OR}=\dfrac{m\vec b-n\vec a}{m-n}\).
Midpoint (\(m=n=1\)): \(\vec{OR}=\dfrac{\vec a+\vec b}{2}\).

Worked Examples

Example 6. \(\vec a=2\hat\imath+3\hat\jmath\), \(\vec b=\hat\imath-\hat\jmath\). Find \(\vec a+\vec b,\ \vec a-\vec b,\ 2\vec a+3\vec b\).
\(\vec a+\vec b=3\hat\imath+2\hat\jmath\). \(\vec a-\vec b=\hat\imath+4\hat\jmath\). \(2\vec a+3\vec b=4\hat\imath+6\hat\jmath+3\hat\imath-3\hat\jmath=7\hat\imath+3\hat\jmath\).
Example 7. Find \(\vec{PQ}\) where \(P(2, 1, 3)\) and \(Q(5, 4, -1)\). Magnitude.
\(\vec{PQ}=(5-2)\hat\imath+(4-1)\hat\jmath+(-1-3)\hat k=3\hat\imath+3\hat\jmath-4\hat k\). \(|\vec{PQ}|=\sqrt{9+9+16}=\sqrt{34}\) units.
Example 8. Position vectors \(\vec a=2\hat\imath+\hat\jmath-3\hat k,\ \vec b=4\hat\imath+5\hat\jmath+\hat k\). Find the position vector of the point dividing AB in ratio 2:3 internally.
\(\vec{OR}=\dfrac{2\vec b+3\vec a}{2+3}=\dfrac{2(4,5,1)+3(2,1,-3)}{5}=\dfrac{(8+6,10+3,2-9)}{5}=\dfrac{14\hat\imath+13\hat\jmath-7\hat k}{5}\).
Example 9. Find the midpoint of \(P(2,3,4)\) and \(Q(4,1,-2)\).
Midpoint = \((\vec a+\vec b)/2=((2+4)/2,(3+1)/2,(4-2)/2)=(3,2,1)\), or as vector \(3\hat\imath+2\hat\jmath+\hat k\).
Example 10. Show that \(A(1,2,7),\ B(2,6,3),\ C(3,10,-1)\) are collinear.
\(\vec{AB}=\hat\imath+4\hat\jmath-4\hat k\); \(\vec{BC}=\hat\imath+4\hat\jmath-4\hat k=\vec{AB}\). So \(\vec{BC}=\vec{AB}\), meaning B and C lie on the same direction from A — collinear (with B as midpoint of AC).
Activity: Force Resultant
L4 Analyse
Materials: Pen, paper.
Predict: Two forces \(\vec F_1=3\hat\imath+4\hat\jmath\) N and \(\vec F_2=-\hat\imath+2\hat\jmath\) N act on a body. What's the magnitude of the resultant force?
  1. Resultant: \(\vec F=\vec F_1+\vec F_2=2\hat\imath+6\hat\jmath\) N.
  2. Magnitude: \(\sqrt{4+36}=\sqrt{40}=2\sqrt{10}\approx 6.32\) N.
  3. Direction: angle with x-axis is \(\tan^{-1}(6/2)=\tan^{-1}3\approx 71.6°\).
  4. Now add a third force \(\vec F_3=2\hat\imath-3\hat\jmath\) N. Find total. (\(\vec F_{\text{tot}}=4\hat\imath+3\hat\jmath\); magnitude 5.)
  5. Lesson: components convert vector addition into ordinary scalar arithmetic.
Vector addition by components is ALWAYS easier than triangle/parallelogram law for arbitrary numbers of vectors. The geometric laws give intuition; the algebra delivers efficiency. This is exactly why physics simulations work in components.

Competency-Based Questions

Scenario: A delivery drone goes from warehouse W(0, 0, 0) to checkpoint A(3, 4, 0) and then to destination B(7, 8, 6). Total displacement is computed via vector addition.
Q1. The vector \(\vec{WB}\) is:
L3 Apply
Answer: \(\vec{WB}=7\hat\imath+8\hat\jmath+6\hat k\). Magnitude \(\sqrt{49+64+36}=\sqrt{149}\) units.
Q2. Verify \(\vec{WA}+\vec{AB}=\vec{WB}\) (triangle law).
L3 Apply
Solution: \(\vec{WA}=3\hat\imath+4\hat\jmath\); \(\vec{AB}=4\hat\imath+4\hat\jmath+6\hat k\). Sum \(=7\hat\imath+8\hat\jmath+6\hat k=\vec{WB}\). ✓
Q3. (T/F) "If A, B, C are collinear, then \(\vec{AB}\) and \(\vec{BC}\) are parallel." Justify.
L5 Evaluate
True. Collinear ⇒ A, B, C lie on a single line, so \(\vec{AB}\) and \(\vec{BC}\) point along this line — parallel (same or opposite direction). Algebraic test: \(\vec{BC}=k\vec{AB}\) for some scalar k.
Q4. Apply: find the point dividing \(P(1,−2,3)\) and \(Q(3,4,−5)\) in ratio 2:3 externally.
L4 Analyse
Solution: External: \(\vec{OR}=(2\vec b-3\vec a)/(2-3)=-(2\vec b-3\vec a)=3\vec a-2\vec b=3(1,-2,3)-2(3,4,-5)=(3-6,-6-8,9+10)=(-3,-14,19)\).
Q5. Design: in 3-D space, find a unit vector that is the sum of \(\hat\imath+2\hat\jmath+3\hat k\) and \(2\hat\imath-\hat\jmath+\hat k\), divided by the magnitude.
L6 Create
Solution: Sum = \(3\hat\imath+\hat\jmath+4\hat k\). Magnitude = \(\sqrt{9+1+16}=\sqrt{26}\). Unit vector: \(\dfrac{1}{\sqrt{26}}(3\hat\imath+\hat\jmath+4\hat k)\).

Assertion–Reason Questions

Assertion (A): Vector addition is commutative.
Reason (R): The parallelogram law gives the same diagonal regardless of which side is labelled \(\vec a\) or \(\vec b\).
(a) Both true, R explains A.
(b) Both true, R doesn't explain A.
(c) A true, R false.
(d) A false, R true.
Answer: (a). Geometric symmetry of the parallelogram is the visual proof.
Assertion (A): The position vector of the midpoint of segment PQ (position vectors a, b) is (a + b)/2.
Reason (R): The midpoint divides PQ internally in ratio 1:1, so by section formula it equals (1·b + 1·a)/(1+1).
(a) Both true, R explains A.
(b) Both true, R doesn't explain A.
(c) A true, R false.
(d) A false, R true.
Answer: (a). R is the section-formula derivation of A.
Assertion (A): If \(\vec a\) and \(\vec b\) are non-zero non-collinear vectors, then \(\alpha\vec a+\beta\vec b=\vec 0\) implies \(\alpha=\beta=0\).
Reason (R): Non-collinear vectors are linearly independent.
(a) Both true, R explains A.
(b) Both true, R doesn't explain A.
(c) A true, R false.
(d) A false, R true.
Answer: (a). R is the technical name for the property in A.

Frequently Asked Questions — Vector Addition, Components and Section Formula

What is the triangle law of vector addition?
Two vectors a and b placed head-to-tail; the sum is the closing side.
What is the parallelogram law of vector addition?
Two vectors from the same point form sides of a parallelogram; the sum is the diagonal from the same starting point.
How do you add vectors in component form?
Add corresponding components.
What is the section formula?
Internal: (m·b + n·a)/(m+n) for ratio m:n. External: (m·b − n·a)/(m−n).
How is the vector joining two points found?
PQ = position vector of Q − position vector of P (head minus tail).
What is the midpoint formula in vectors?
(a + b)/2 — section formula with m = n = 1.
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